Compound interest with a formula
Grade 9 Math Worksheet

Circle the best answer, or write your answer on the line.
Mr. Dunn puts $2,500 in a pretend account at 4% a year, compounded quarterly, for 3 years. Noah uses A = P(1 + r/n)^(nt). To the nearest cent, what is the balance?
Ms. Hale puts $600 in a pretend account at 3% a year, compounded twice a year, for 5 years. Pia uses A = P(1 + r/n)^(nt). To the nearest cent, what is the balance?
Mr. Cole puts $400 in a pretend account at 5% a year, compounded monthly, for 1 year. Ren uses A = P(1 + r/n)^(nt). To the nearest cent, what is the balance?
Ms. Shaw puts $5,000 in a pretend account at 2% a year, compounded quarterly, for 4 years. Tala uses A = P(1 + r/n)^(nt). To the nearest cent, what is the balance?
Mr. Grove's pretend account holds $1,500 at 6% a year, compounded quarterly, for 2 years. Ari wants only the interest. To the nearest cent, how much interest is earned?
The art club's pretend fund holds $2,000 at 3% a year, compounded monthly, for 5 years. Esme wants only the interest. To the nearest cent, how much interest is earned?
Mr. Cole puts $750 in a pretend account at 3% a year, compounded monthly, for 4 years. Jun checks the formula. Which one gives the balance?
- A = 750(1 + 0.03/12)^4
- A = 750(1 + 3/12)^(12 · 4)
- A = 750(1 + 0.03/12)^(12 · 4)
- A = 750(1 + 0.03)^(12 · 4)
Ms. Reyes puts $1,200 in a pretend account at 4% a year, compounded quarterly, for 5 years. Kira checks the formula. Which one gives the balance?
- A = 1200(1 + 0.04)^(4 · 5)
- A = 1200(1 + 0.04/4)^5
- A = 1200(1 + 4/4)^(4 · 5)
- A = 1200(1 + 0.04/4)^(4 · 5)
The class puts $500 in a pretend account at 6% a year, compounded twice a year, for 3 years. Luz checks the formula. Which one gives the balance?
- A = 500(1 + 0.06)^(2 · 3)
- A = 500(1 + 0.06/2)^3
- A = 500(1 + 0.06/2)^(2 · 3)
- A = 500(1 + 6/2)^(2 · 3)
Mr. Vance puts $2,000 in a pretend account at 5% a year, compounded monthly, for 2 years. Milo checks the formula. Which one gives the balance?
- A = 2000(1 + 0.05/12)^2
- A = 2000(1 + 0.05/12)^(12 · 2)
- A = 2000(1 + 0.05)^(12 · 2)
- A = 2000(1 + 5/12)^(12 · 2)