choosing the model that fits the data: linear, quadratic or exponential
Grade 11 Math Worksheet

Circle the best answer.
0 → 50; 1 → 40; 3 → 25.6. Tala tracks a vehicle's value in thousands of dollars at years 0, 1 and 3. Which equation fits all three rows?
- y = 50 − 10x
- y = 50(0.64)^x
- y = 50(0.8)^x
Read this first
Table, week → cm
1 → 2.1; 2 → 2.6; 3 → 3.9; 4 → 6.2; 5 → 9.1; 6 → 12.8; 7 → 17.0. Line: y = 2.51x − 2.37, r = 0.97. Residuals: +2.0, 0.0, −1.3, −1.5, −1.1, +0.1, +1.8.
Luz fits a line to a plant's height by week. Technology gives r = 0.97, but the residuals form a U. Which conclusion is best?
- The line fits: the residuals are small, from −1.5 to +2.0
- The line fits well: r = 0.97 is close to 1, so the residuals do not matter
- The line is a poor model: a high r can hide a curve, so a quadratic is better
Kira fits a line and an exponential to the same six points. Both have r above 0.96. Which model should Kira use?
- Either one: both have r above 0.96, so they are equally good for these points
- The exponential: its residuals are small and scattered; the line's form a U
- The line: it has fewer parts, and its residuals are about as small as the curve's
Milo fits a line to eight points. The residuals alternate in sign and the later ones are much larger. Which conclusion is best?
Line: y = 2.10x + 6.01, r = 0.93. Residuals for x = 1 to 8: −0.1, −0.8, +0.9, −1.2, +2.0, −1.7, +3.5, −2.5. Line: y = 2.10x + 6.01, r = 0.93. Residuals for x = 1 to 8: −0.1, −0.8, +0.9, −1.2, +2.0, −1.7, +3.5, −2.5. y = 2.10x + 6.01, r = 0.93 x residual 1 2 3 4 5 6 7 8 -0.1 -0.8 +0.9 -1.2 +2.0 -1.7 +3.5 -2.5 - A curve fits better, because the line's r is just 0.93
- The line is centered, but the errors grow with x, so large-x predictions are less reliable
- A curve fits better, because the residuals alternate above and below 0 as x grows
- The line fits equally well across the x-values, because the residuals average about 0 across the eight points
Points
(1, 2.4), (2, 3.1), (3, 4.9), (4, 5.2), (5, 6.8), (6, 7.1), (7, 8.9), (9, 3). With all eight, r = 0.43. Without (9, 3), r = 0.99.
A line through eight points has r = 0.43. Without the point (9, 3), the other seven give r = 0.99. What should Tala do first?
- Delete the point at once, because removing it raises r from 0.43 to 0.99
- Check whether (9, 3) is a mistake or a real case, then compare fits with and without it
- Keep the whole data set and use the line, because r is simply what the data give, however odd the point looks
Table, x → y → ln y
1 → 6 → 1.79; 2 → 10 → 2.30; 3 → 17 → 2.83; 4 → 29 → 3.37; 5 → 50 → 3.91; 6 → 86 → 4.45. r for (x, y) is 0.935; r for (x, ln y) is 0.9999.
Noah fits y against x and then ln y against x. Technology gives the two r values shown. Which model does the data support?
- A quadratic: the points curve upward, so a parabola should fit them well
- An exponential: ln y is almost linear in x, so y grows by a steady factor
- A power model: ln y against x is a line, so y is a power of x
- A line: r = 0.935 is already close to 1, so no change to the model is needed
Pia fits a line to six points and gets the residuals shown, a U. Just beyond x = 6, will the line likely be too high or too low?
Data, x → y: 1 → 3.0; 2 → 4.4; 3 → 6.4; 4 → 9.5; 5 → 13.9; 6 → 20.6. Line y = 3.42x − 2.33. Residuals (data − line): +1.9, −0.1, −1.5, −1.8, −0.9, +2.4. Data, x → y: 1 → 3.0; 2 → 4.4; 3 → 6.4; 4 → 9.5; 5 → 13.9; 6 → 20.6. Line y = 3.42x − 2.33. Residuals (data − line): +1.9, −0.1, −1.5, −1.8, −0.9, +2.4. Data, x → y 0 1 2 3 4 5 6 7 0 5 10 15 20 y = 3.42x - 2.33 Residuals (data - line): +1.9, -0.1, -1.5, -1.8, -0.9, +2.4. - Right on target: the residuals average 0, so the line is exact
- Too low: the data curve upward, so the line falls further below them
- Too high: the line goes through the middle of the data, so it overestimates
Esme's fit y = 2.4x + 15 gives a vine's height in cm after x weeks. Esme rewrites it with x in days. Which equation matches?
- y = 0.34x + 15, because only the slope changes
- y = 0.34x + 2.1, because both numbers are divided by 7
- y = 16.8x + 15, because there are 7 days in a week
Fits y = 2,400(1.06)^x and y = 2,400(1.09)^x give two towns' library cardholders after x years. Which statement does Ari make comparing them?
- The first grows faster, because 1.06 is closer to 1
- The second starts higher, because 1.09 is bigger than 1.06
- Both start at 2,400; the second grows 9% a year, the first 6%
- The second adds 3% more cardholders each year, a constant amount
Technology fits y = 800(0.75)^(x/2) to a phone's resale value in dollars after x years. Which description does Luz choose?
- Starts at 800 and falls about 13.4% each year, 25% every 2 years
- Starts at 800 and falls 25% each year, so about 600 are left after 1 year
- Starts at 800 and falls 12.5% each year, half of the 25% over 2 years
- Starts at 0.75 and is multiplied by 800 every 2 years