systems of three equations: solve, and count the solutions

Grade 11 Math Worksheet

NameDate

Circle the best answer.

  1. Read this first

    Use the table

    Equations: (1) -3x + 2y + z = 12; (2) 3x − 4y − z = -4; (3) 6x + 5y + 2z = -40.

    xyztotal
    (1)-32112
    (2)3-4-1-4
    (3)652-40
  2. Luz cancelled z with rows (1) and (2). Row (3) has a z number twice the size of row (1)'s. Which step on rows (1) and (3) cancels z?

    • Add rows (1) and (3)
    • Subtract row (3) from row (1)
    • Add 2 × row (1) to row (3)
    • Subtract row (3) from 2 × row (1)
  3. Noah cancelled z from rows (1) and (2) and now works on rows (1) and (3). Which step cancels z?

    • Subtract row (3) from row (1)
    • Subtract row (3) from 2 × row (1)
    • Add rows (1) and (3)
    • Add 2 × row (1) to row (3)
  4. Pia multiplies row (1) by 2 and subtracts it from row (2) to cancel x. Which new row is left?

    • 13y − 6z = 5
    • 4x − 3y + 10z = -16
    • -3y − 6z = -16
    • 13y − 6z = 12
  5. To cancel x, Ren subtracts 3 × row (1) from row (2) of the number table. Which new row is left?

    • -8y − 7z = -46
    • 16y − 7z = 50
    • 6x − 8y + 5z = -46
    • 16y − 7z = 18
  6. In Ari's table, row (2) minus 2 × row (1) cancels x. Which new row is left?

    • 9y + 3z = 60
    • 4x − 3y − 13z = -72
    • 9y + 3z = 27
    • -3y − 13z = -72
  7. Use the table

    Equations: (1) 2x + 2y + z = -8; (2) -5x − 4y − z = 6; (3) 4x + 2y − z = 11.

    xyztotal
    (1)221-8
    (2)-5-4-16
    (3)42-111

    Row (4) = row (1) + row (2): -3x − 2y = -2. Row (5) = row (1) + row (3): 6x + 4y = 3.

  8. Bo adds row (1) to rows (2) and (3) to cancel z, giving rows (4) and (5). How many solutions does the system have?

    • No solution
    • Infinitely many solutions
    • Exactly one solution
  9. Use the table

    Equations: (1) 2x + 3y − z = 3; (2) -6x − 4y + z = -10; (3) 2x − 2y + z = 4.

    xyztotal
    (1)23-13
    (2)-6-41-10
    (3)2-214

    Row (4) = row (1) + row (2): -4x − y = -7. Row (5) = row (1) + row (3): 4x + y = 7.

  10. Esme cancels z, making rows (4) and (5) from the table. How many solutions does the system have?

    • Exactly one solution
    • Infinitely many solutions
    • No solution
  11. Use the table

    Equations: (1) 3x − 2y + z = -3; (2) -7x + 3y − z = 8; (3) -2x + 6y − z = -11.

    xyztotal
    (1)3-21-3
    (2)-73-18
    (3)-26-1-11

    Row (4) = row (1) + row (2): -4x + y = 5. Row (5) = row (1) + row (3): x + 4y = -14.

  12. Adding row (1) to rows (2) and (3) gives Jun rows (4) and (5) without z. How many solutions does the system have?

    • Exactly one solution
    • No solution
    • Infinitely many solutions
  13. Use the table

    Equations: (1) -x − 2y + 3z = -5; (2) -x − 2y − 3z = 1; (3) -3x − 6y − 3z = -4.

    xyztotal
    (1)-1-23-5
    (2)-1-2-31
    (3)-3-6-3-4

    Row (4) = row (1) + row (2): -2x − 4y = -4. Row (5) = row (1) + row (3): -4x − 8y = -9.

  14. Kira adds row (1) to rows (2) and (3) to cancel z, giving rows (4) and (5). How many solutions does the system have?

    • Exactly one solution
    • Infinitely many solutions
    • No solution
  15. Use the table

    Equations: (1) x − y − 3z = -2; (2) 2x + 2y + 3z = 4; (3) 8x + 4y + 3z = 8.

    xyztotal
    (1)1-1-3-2
    (2)2234
    (3)8438

    Row (4) = row (1) + row (2): 3x + y = 2. Row (5) = row (1) + row (3): 9x + 3y = 6.

  16. Luz cancels z, making rows (4) and (5) from the table. How many solutions does the system have?

    • No solution
    • Exactly one solution
    • Infinitely many solutions
PencilGopencilgo.com

systems of three equations: solve, and count the solutions

Answer Key - Grade 11 Math Worksheet

Circle the best answer.

  1. Read this first

    Use the table

    Equations: (1) -3x + 2y + z = 12; (2) 3x − 4y − z = -4; (3) 6x + 5y + 2z = -40.

    xyztotal
    (1)-32112
    (2)3-4-1-4
    (3)652-40
  2. Luz cancelled z with rows (1) and (2). Row (3) has a z number twice the size of row (1)'s. Which step on rows (1) and (3) cancels z?

    • Add rows (1) and (3)
    • Subtract row (3) from row (1)
    • Add 2 × row (1) to row (3)
    • Subtract row (3) from 2 × row (1)
  3. Noah cancelled z from rows (1) and (2) and now works on rows (1) and (3). Which step cancels z?

    • Subtract row (3) from row (1)
    • Subtract row (3) from 2 × row (1)
    • Add rows (1) and (3)
    • Add 2 × row (1) to row (3)
  4. Pia multiplies row (1) by 2 and subtracts it from row (2) to cancel x. Which new row is left?

    • 13y − 6z = 5
    • 4x − 3y + 10z = -16
    • -3y − 6z = -16
    • 13y − 6z = 12
  5. To cancel x, Ren subtracts 3 × row (1) from row (2) of the number table. Which new row is left?

    • -8y − 7z = -46
    • 16y − 7z = 50
    • 6x − 8y + 5z = -46
    • 16y − 7z = 18
  6. In Ari's table, row (2) minus 2 × row (1) cancels x. Which new row is left?

    • 9y + 3z = 60
    • 4x − 3y − 13z = -72
    • 9y + 3z = 27
    • -3y − 13z = -72
  7. Use the table

    Equations: (1) 2x + 2y + z = -8; (2) -5x − 4y − z = 6; (3) 4x + 2y − z = 11.

    xyztotal
    (1)221-8
    (2)-5-4-16
    (3)42-111

    Row (4) = row (1) + row (2): -3x − 2y = -2. Row (5) = row (1) + row (3): 6x + 4y = 3.

  8. Bo adds row (1) to rows (2) and (3) to cancel z, giving rows (4) and (5). How many solutions does the system have?

    • No solution
    • Infinitely many solutions
    • Exactly one solution
  9. Use the table

    Equations: (1) 2x + 3y − z = 3; (2) -6x − 4y + z = -10; (3) 2x − 2y + z = 4.

    xyztotal
    (1)23-13
    (2)-6-41-10
    (3)2-214

    Row (4) = row (1) + row (2): -4x − y = -7. Row (5) = row (1) + row (3): 4x + y = 7.

  10. Esme cancels z, making rows (4) and (5) from the table. How many solutions does the system have?

    • Exactly one solution
    • Infinitely many solutions
    • No solution
  11. Use the table

    Equations: (1) 3x − 2y + z = -3; (2) -7x + 3y − z = 8; (3) -2x + 6y − z = -11.

    xyztotal
    (1)3-21-3
    (2)-73-18
    (3)-26-1-11

    Row (4) = row (1) + row (2): -4x + y = 5. Row (5) = row (1) + row (3): x + 4y = -14.

  12. Adding row (1) to rows (2) and (3) gives Jun rows (4) and (5) without z. How many solutions does the system have?

    • Exactly one solution
    • No solution
    • Infinitely many solutions
  13. Use the table

    Equations: (1) -x − 2y + 3z = -5; (2) -x − 2y − 3z = 1; (3) -3x − 6y − 3z = -4.

    xyztotal
    (1)-1-23-5
    (2)-1-2-31
    (3)-3-6-3-4

    Row (4) = row (1) + row (2): -2x − 4y = -4. Row (5) = row (1) + row (3): -4x − 8y = -9.

  14. Kira adds row (1) to rows (2) and (3) to cancel z, giving rows (4) and (5). How many solutions does the system have?

    • Exactly one solution
    • Infinitely many solutions
    • No solution
  15. Use the table

    Equations: (1) x − y − 3z = -2; (2) 2x + 2y + 3z = 4; (3) 8x + 4y + 3z = 8.

    xyztotal
    (1)1-1-3-2
    (2)2234
    (3)8438

    Row (4) = row (1) + row (2): 3x + y = 2. Row (5) = row (1) + row (3): 9x + 3y = 6.

  16. Luz cancels z, making rows (4) and (5) from the table. How many solutions does the system have?

    • No solution
    • Exactly one solution
    • Infinitely many solutions