systems of three equations: solve, and count the solutions
Grade 11 Math Worksheet

Circle the best answer.
Read this first
Use the table
Equations: (1) x + 3y + z = 24; (2) x + 2y + 3z = 27; (3) 3x + y − 2z = 12.
x y z total (1) 1 3 1 24 (2) 1 2 3 27 (3) 3 1 -2 12 Esme's math club card gives the system in the table. Which ordered triple (x, y, z) solves all three equations?
- (5, 5, 4)
- y = 5 and z = 4
- (12, 3, 3)
- (4, 5, 5)
Jun copies a system into a number table. Which ordered triple (x, y, z) makes all three rows true?
- (2, -5, -10)
- y = 4 and z = -4
- (-4, 4, 5)
- (5, 4, -4)
Kira is checking a homework system, shown as a table. Which ordered triple (x, y, z) is its solution?
- (8, -5, -11)
- (-1, 5, -4)
- y = 5 and z = -4
- (-4, 5, -1)
Noah cancelled z from rows (1) and (2) and now works on rows (1) and (3). Which step cancels z?
- Add 2 × row (1) to row (3)
- Subtract row (3) from 2 × row (1)
- Add rows (1) and (3)
- Subtract row (3) from row (1)
To cancel x, Ren subtracts 3 × row (1) from row (2) of the number table. Which new row is left?
- 16y − 7z = 50
- 6x − 8y + 5z = -46
- 16y − 7z = 18
- -8y − 7z = -46
Tala takes -2 copies of row (1) away from row (2), so x cancels. Which new row is left?
- -4x − 11y − 12z = -36
- 5y + 4z = -23
- 5y + 4z = 16
- -11y − 12z = -36
In Ari's table, row (2) minus 2 × row (1) cancels x. Which new row is left?
- 9y + 3z = 27
- 9y + 3z = 60
- -3y − 13z = -72
- 4x − 3y − 13z = -72
Use the table
Equations: (1) 2x + 2y + z = -8; (2) -5x − 4y − z = 6; (3) 4x + 2y − z = 11.
x y z total (1) 2 2 1 -8 (2) -5 -4 -1 6 (3) 4 2 -1 11 Row (4) = row (1) + row (2): -3x − 2y = -2. Row (5) = row (1) + row (3): 6x + 4y = 3.
Bo adds row (1) to rows (2) and (3) to cancel z, giving rows (4) and (5). How many solutions does the system have?
- Exactly one solution
- Infinitely many solutions
- No solution
Use the table
Equations: (1) 3x − 2y + z = -3; (2) -7x + 3y − z = 8; (3) -2x + 6y − z = -11.
x y z total (1) 3 -2 1 -3 (2) -7 3 -1 8 (3) -2 6 -1 -11 Row (4) = row (1) + row (2): -4x + y = 5. Row (5) = row (1) + row (3): x + 4y = -14.
Adding row (1) to rows (2) and (3) gives Jun rows (4) and (5) without z. How many solutions does the system have?
- No solution
- Exactly one solution
- Infinitely many solutions
Use the table
Equations: (1) -x − 2y + 3z = -5; (2) -x − 2y − 3z = 1; (3) -3x − 6y − 3z = -4.
x y z total (1) -1 -2 3 -5 (2) -1 -2 -3 1 (3) -3 -6 -3 -4 Row (4) = row (1) + row (2): -2x − 4y = -4. Row (5) = row (1) + row (3): -4x − 8y = -9.
Kira adds row (1) to rows (2) and (3) to cancel z, giving rows (4) and (5). How many solutions does the system have?
- Exactly one solution
- No solution
- Infinitely many solutions