ATP: the cell's energy carrier
Grade 9 Science Worksheet - Challenge Me

Circle the best answer.
Flow diagram (model, not to scale), drawn inside the cell membrane. Ari reads that one ATP's hydrolysis releases 7.3 kcal/mol and moving one sodium ion across a membrane takes 2.1 kcal/mol. How many whole sodium ions could that energy move?
- 4 ions: 7.3 ÷ 2.1 = 3.5, and half an ion is rounded up to 4
- 1 ion: each ATP is meant to move a single sodium ion
- 9 ions: 7.3 + 2.1 = 9.4, and that is rounded down to 9
- 3 ions: 3 × 2.1 = 6.3 fits in 7.3, but 4 × 2.1 = 8.4 does not
Read this first
Use this
Flow diagram (model, not to scale), drawn inside the cell. Inputs in boxes on the left: ATP; model reaction X. Outputs in boxes on the right: ADP and Pi; model reaction X done. A wavy arrow points out of the reaction: 14 kcal/mol released by ATP hydrolysis in a living cell. Each run of model reaction X needs 5 kcal/mol.
Bo reads that ATP hydrolysis in a living cell releases 14 kcal/mol. A model reaction X needs 5 kcal/mol each time. How many whole runs of X can one ATP drive?
- 9 runs: 14 − 5 = 9, and each run uses up one unit of 5
- 3 runs: 14 ÷ 5 = 2.8, and the 0.8 is counted as a whole run
- 0 runs: ATP releases energy, so it cannot drive anything
- 2 runs: 2 × 5 = 10 fits in 14, but 3 × 5 = 15 is too much
This is the first step of glycolysis. In the first step of glycolysis, a cell spends ATP to add a phosphate group to glucose. Esme asks why. What is the best reason?
Flow diagram (model, not to scale), drawn inside the cytoplasm. Inputs in boxes on the left: ATP; glucose. Outputs in boxes on the right: ADP; glucose with a phosphate group added. A wavy arrow points out of the reaction: energy released by ATP and used to add the phosphate. This is the first step of glycolysis. Flow diagram (model, not to scale), drawn inside the cytoplasm. Inputs in boxes on the left: ATP; glucose. Outputs in boxes on the right: ADP; glucose with a phosphate group added. A wavy arrow points out of the reaction: energy released by ATP and used to add the phosphate. This is the first step of glycolysis. cytoplasm ATP glucose ADP glucose with a phosphate group added energy released by ATP and used to add the phosphate - Adding a phosphate to glucose needs energy, and ATP hydrolysis supplies it
- ATP stores the glucose until the cell needs it later on
- The ATP is used up for good once it gives away its phosphate
- Adding a phosphate to glucose releases energy, so ATP is a spare
Jun reads a model graph. At time 0 a cell stops rebuilding ATP while it keeps working. When does the ATP run out, and what does that show?
Model graph of ATP in a model cell after rebuilding stops (model data). Time (s) across, 0 to 4, a mark every 1. ATP molecules present (molecules) up, 0 to 40, a mark every 10. The line joins (0 s, 30), (1 s, 20), (2 s, 10), (3 s, 0), (4 s, 0) with straight pieces. Model graph of ATP in a model cell after rebuilding stops (model data). Time (s) across, 0 to 4, a mark every 1. ATP molecules present (molecules) up, 0 to 40, a mark every 10. The line joins (0 s, 30), (1 s, 20), (2 s, 10), (3 s, 0), (4 s, 0) with straight pieces. Model graph of ATP in a model cell after rebuilding stops (model data) 0 1 2 3 4 0 10 20 30 40 Time (s) ATP molecules present (molecules) - At 30 s: ATP is the cell's long-term store of energy
- At 3 s: the ATP is gone for good, so the cell cannot recover
- At 3 s: ATP is a short-term supply that must be rebuilt
- At no point: ADP and Pi turn back into ATP on their own
ATP budget of a model cell (model data)
measure ATP molecules present at the start 40 broken down each second 8 rebuilt each second 5 Kira reads a model ATP budget. The cell works for 4 seconds at these rates. How many ATP molecules are present at the end?
- 60: 4 seconds × 5 rebuilt adds 20 to the 40, with nothing broken down
- 52: each second 8 − 5 = 3 is gained, so 40 + 12 = 52
- 8: 4 seconds × 8 broken down leaves 8, with nothing rebuilt
- 28: each second 8 are broken down and 5 rebuilt, a net loss of 3
Use this
Flow diagram (model, not to scale), drawn inside the cell. Inputs in boxes on the left: line 1: ATP and water. Outputs in boxes on the right: line 2: ADP, with 2 phosphate groups, and Pi; line 3: ADP and Pi leave the cell as waste; line 4: glucose breakdown later supplies energy to rebuild. A wavy arrow points out of the reaction: line 1: energy released.
Milo's notebook describes what happens to ATP in a cell, in four lines. Which line has a flaw?
- Line 3: ADP and Pi are rebuilt into ATP, not thrown away
- Line 4: rebuilding ATP needs no energy, so line 4 is extra
- Line 1: ATP should hold its energy for weeks, not release it
- Line 2: ADP should have 3 phosphate groups, like ATP
Flow diagram (model, not to scale), drawn inside the cell. Noah's notebook shows ATP and water becoming ADP and Pi, with a wavy arrow into the reaction labeled energy needed. What is the flaw?
Flow diagram (model, not to scale), drawn inside the cell. Inputs in boxes on the left: ATP; water. Outputs in boxes on the right: ADP with 2 phosphate groups; Pi. A wavy arrow points into the reaction: energy needed. Flow diagram (model, not to scale), drawn inside the cell. Inputs in boxes on the left: ATP; water. Outputs in boxes on the right: ADP with 2 phosphate groups; Pi. A wavy arrow points into the reaction: energy needed. ATP water ADP with 2 phosphate groups Pi energy needed - The wavy arrow should point out: breaking ATP down releases energy
- Water should be an output, since hydrolysis releases water
- The arrow is right: making ADP and Pi from ATP needs an energy input
- The ADP box should show 3 phosphate groups to match ATP
ATP in a working model cell (model data)
time (s) ATP present ATP broken down each second ATP rebuilt each second 0 60 12 12 10 60 12 12 20 60 12 12 Pia says the amount of ATP stayed at 60, so the cell used none. What is the flaw in that claim?
- A steady amount shows the ATP was stored away in the cell, not used
- The amount should rise, because using ATP makes more of it
- A steady amount can mean ATP is rebuilt as fast as it is used
- The amount should fall, because used ATP is gone for good
Use this
Flow diagram (model, not to scale), drawn inside the cell. No wavy arrow label is drawn. No wavy arrow labels are drawn.
Tala's friend says rebuilding ATP is what releases the energy a cell uses for work. Which reply is correct?
Flow diagram (model, not to scale), drawn inside the cell. Inputs in boxes on the left: ATP and water; ADP and Pi. Outputs in boxes on the right: ADP and Pi; ATP and water. No wavy arrow label is drawn. Two changes make a loop: ATP breaks into ADP and Pi, and ADP and Pi join back into ATP. No wavy arrow labels are drawn. Flow diagram (model, not to scale), drawn inside the cell. Inputs in boxes on the left: ATP and water; ADP and Pi. Outputs in boxes on the right: ADP and Pi; ATP and water. No wavy arrow label is drawn. Two changes make a loop: ATP breaks into ADP and Pi, and ADP and Pi join back into ATP. No wavy arrow labels are drawn. ATP and water ADP and Pi ADP and Pi ATP and water ATP breaks into ADP and Pi ADP and Pi join back into ATP - Agree: joining the third phosphate to ADP releases energy
- Disagree: rebuilding releases energy, and breaking takes it in
- Disagree: rebuilding takes energy in; breaking ATP down releases it
- Agree: ADP and Pi make the energy by themselves
ATP made during glucose breakdown (real data, from OpenStax Biology 2e)
process share of the ATP where it happens chemiosmosis 90 percent mitochondria in a eukaryotic cell substrate-level phosphorylation a few ATP molecules steps of the glucose pathways Zee reads that the mitochondria in a model muscle cell stop working. Which prediction fits the card?
- ATP rebuilding falls sharply, since 90 percent of the ATP from glucose is made in mitochondria
- ATP rebuilding stays the same, since stored ATP lasts for months
- ATP rebuilding stays the same, since ADP and Pi make energy alone
- ATP rebuilding stops at once, since the ATP is used up for good