How living in groups helps animals survive

Grade 9 Science Worksheet - Challenge Me

NameDate

Circle the best answer.

  1. Read this first

    A colony with and without a sentinel (model data)

    measurewith a sentinelno sentinel
    seconds until the colony hears a warning412
    the sentinel's chance of being lost each day (%)3not on duty
    any other member's chance of being lost each day (%)11
  2. Ari reads model data on a meerkat colony. Which conclusion about sentinel duty is best supported?

    • The colony gains a warning in 4 s instead of 12 s, but the sentinel carries 3 times the risk
    • The sentinel gains the most, since it spots the threat first and can reach cover before the others
    • The sentinel carries 3 percentage points more risk than the others
    • The colony gains and no member pays, since the colony is warned in 4 s
  3. Minnows in same-size tanks (model data)

    group sizeshare surviving at day 10 (%)
    470
    885
    1690
    3275
  4. Jun thinks crowding in a fixed tank lowered survival at 32 fish. Which new test would best check that explanation?

    • Add extra food to the tank of 4 fish and compare
    • Keep 32 fish per tank, but test tanks of two sizes with the same water and light
    • Test 4 fish in a smaller tank to see what crowding does
    • Repeat with 16 fish in the same tank to see the 90% result again and confirm the rise
  5. Scatter of the place a dance advertises (model data)

    resourcedistance (m)spread of the place (m)
    near patch20030
    far patch600?
  6. Bo reads the model data. The angle's precision stays the same at any distance. How much wider is the zone to search at 600 m, and why?

    • 3 times wider, since angle precision gets worse with distance
    • 3 times wider: the same angle error covers a wider strip at a longer distance
    • 9 times wider, since both the distance and the width triple
    • The same width at any distance, since the angle's precision is the same for near and far patches
  7. Use the table

    A male's day (model rule: heat lost is proportional to the gap from 38 °C; shares from Gilbert et al. 2006) (model data and Gilbert et al. 2006)

    situationshare of timeair temperature (°C)
    huddling38%10
    not huddling62%−17
  8. Luz compares a male's average heat loss with never huddling. By about what percent did huddling cut it?

    • About 19%: the average gap is 0.38 × 28 + 0.62 × 55 ≈ 45 °C, against 55 °C
    • About 81%: the heat that is still lost
    • About 38%: the share of time huddling
    • About 49%: huddling cuts the gap from 55 °C to 28 °C
  9. Three studies of fish (model data)

    studyfish per conditionhow fish got their conditionsurvivors in groupssurvivors alone
    study A5assigned at random53
    study B100assigned at random8060
    study C200fish chose170110
  10. Zee compares three model studies of fish in groups and alone. Which gives the strongest evidence that groups raise survival?

    • Study C: 200 fish per condition is the biggest sample, so it must settle the question
    • No study: a gap of 20 points is too small to count
    • Study B: random assignment and 100 fish per condition give a fair, steady comparison
    • Study A: its 40-point gap is the biggest
  11. Notebook

    Notes on a model huddle (classmate's notebook), 4 lines. Columns: line, entry. Line 1: Heat lost is proportional to the gap between a bird's 38 °C and the air. Line 2: In −17 °C air the gap is 38 − 17 = 21 °C. Line 3: In a 20 °C pocket the gap is 38 − 20 = 18 °C. Line 4: So the pocket bird loses 18 ÷ 21, about 86%, as much heat.

  12. Ari reads a classmate's notebook about a model huddle. Which line has the mistake?

    • Line 2: the gap from 38 °C down to −17 °C is 38 + 17 = 55 °C
    • Line 3: the gap in a 20 °C pocket should be 38 + 20 = 58 °C
    • Line 1: heat loss depends on the air temperature alone, not on a gap
    • Line 4: 18 ÷ 21 should be written as 21 ÷ 18
  13. Notebook

    Notes on a patch at 220° (classmate's notebook), 4 lines. Columns: line, entry. Line 1: At 12:00 the sun is at 180°, so the dancer shows 220 − 180 = 40° clockwise. Line 2: The sun moves 15° clockwise each hour. Line 3: At 14:00 the sun is at 210°, so the dancer shows 220 − 210 = 10°. Line 4: So the angle stays at 40° all day, because the patch has not moved.

  14. Kira reads a classmate's notebook about a model dance. Which line has the mistake?

    • Line 4: the patch stays put, but the angle shrinks as the sun moves
    • Line 3: the angle should be 210 − 220 = −10°
    • Line 2: the sun should move 30° each hour
    • Line 1: the angle shows the kind of resource, not the direction
  15. Flocks and visits (model data)

    flock sizevisits a daychance one bird is lost in a day (%)
    10110
    10044
    1000161.6
  16. Ren's friend says a flock's risk falls in proportion to its size. Which reply uses the table best?

    • Agree: the risk is shared out evenly, so a flock 10 times larger has 10 times less risk each
    • Agree: 4% is half of 10%, so doubling the flock halves the risk
    • Disagree: bigger flocks are riskier, since visits rise from 1 to 16
    • Disagree: more visits arrive, so a flock 10 times larger cut the risk only from 10% to 4%
  17. Colony size and chicks (model data)

    nests in the colonychicks surviving per nest
    103.0
    402.5
    1601.8
  18. Tala claims living in a group helps every species. Which reply fits the model table?

    • Disagree: the table cannot say anything about benefits
    • Agree: 160 nests rear 288 chicks in total against 30 in the small colony, so the big colony wins
    • Disagree: chicks per nest fall from 3.0 to 1.8, so crowding costs more than the group gives here
    • Agree: 1.8 chicks per nest is still a benefit, so the group helps
  19. Use the table

    What the huddling study found (data: Gilbert et al. 2006)

    findingvalue
    average length of one huddle1.6 h
    huddlesdiscontinuous and variable in length
    access to the warmth of huddlesequal for all birds
    huddling time above 20 °C13%
  20. Zee claims edge birds in a huddle never get warm. Which reply fits the study?

    • Supported: only 13% of huddling time was above 20 °C
    • Not supported: huddles were short and changing, and every bird had equal access to warmth
    • Supported: huddles were uneven in size and length, so the edge birds must stay cold the whole time
    • Not supported: the study found birds were never cold
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How living in groups helps animals survive

Answer Key - Grade 9 Science Worksheet - Challenge Me

Circle the best answer.

  1. Read this first

    A colony with and without a sentinel (model data)

    measurewith a sentinelno sentinel
    seconds until the colony hears a warning412
    the sentinel's chance of being lost each day (%)3not on duty
    any other member's chance of being lost each day (%)11
  2. Ari reads model data on a meerkat colony. Which conclusion about sentinel duty is best supported?

    • The colony gains a warning in 4 s instead of 12 s, but the sentinel carries 3 times the risk
    • The sentinel gains the most, since it spots the threat first and can reach cover before the others
    • The sentinel carries 3 percentage points more risk than the others
    • The colony gains and no member pays, since the colony is warned in 4 s
  3. Minnows in same-size tanks (model data)

    group sizeshare surviving at day 10 (%)
    470
    885
    1690
    3275
  4. Jun thinks crowding in a fixed tank lowered survival at 32 fish. Which new test would best check that explanation?

    • Add extra food to the tank of 4 fish and compare
    • Keep 32 fish per tank, but test tanks of two sizes with the same water and light
    • Test 4 fish in a smaller tank to see what crowding does
    • Repeat with 16 fish in the same tank to see the 90% result again and confirm the rise
  5. Scatter of the place a dance advertises (model data)

    resourcedistance (m)spread of the place (m)
    near patch20030
    far patch600?
  6. Bo reads the model data. The angle's precision stays the same at any distance. How much wider is the zone to search at 600 m, and why?

    • 3 times wider, since angle precision gets worse with distance
    • 3 times wider: the same angle error covers a wider strip at a longer distance
    • 9 times wider, since both the distance and the width triple
    • The same width at any distance, since the angle's precision is the same for near and far patches
  7. Use the table

    A male's day (model rule: heat lost is proportional to the gap from 38 °C; shares from Gilbert et al. 2006) (model data and Gilbert et al. 2006)

    situationshare of timeair temperature (°C)
    huddling38%10
    not huddling62%−17
  8. Luz compares a male's average heat loss with never huddling. By about what percent did huddling cut it?

    • About 19%: the average gap is 0.38 × 28 + 0.62 × 55 ≈ 45 °C, against 55 °C
    • About 81%: the heat that is still lost
    • About 38%: the share of time huddling
    • About 49%: huddling cuts the gap from 55 °C to 28 °C
  9. Three studies of fish (model data)

    studyfish per conditionhow fish got their conditionsurvivors in groupssurvivors alone
    study A5assigned at random53
    study B100assigned at random8060
    study C200fish chose170110
  10. Zee compares three model studies of fish in groups and alone. Which gives the strongest evidence that groups raise survival?

    • Study C: 200 fish per condition is the biggest sample, so it must settle the question
    • No study: a gap of 20 points is too small to count
    • Study B: random assignment and 100 fish per condition give a fair, steady comparison
    • Study A: its 40-point gap is the biggest
  11. Notebook

    Notes on a model huddle (classmate's notebook), 4 lines. Columns: line, entry. Line 1: Heat lost is proportional to the gap between a bird's 38 °C and the air. Line 2: In −17 °C air the gap is 38 − 17 = 21 °C. Line 3: In a 20 °C pocket the gap is 38 − 20 = 18 °C. Line 4: So the pocket bird loses 18 ÷ 21, about 86%, as much heat.

  12. Ari reads a classmate's notebook about a model huddle. Which line has the mistake?

    • Line 2: the gap from 38 °C down to −17 °C is 38 + 17 = 55 °C
    • Line 3: the gap in a 20 °C pocket should be 38 + 20 = 58 °C
    • Line 1: heat loss depends on the air temperature alone, not on a gap
    • Line 4: 18 ÷ 21 should be written as 21 ÷ 18
  13. Notebook

    Notes on a patch at 220° (classmate's notebook), 4 lines. Columns: line, entry. Line 1: At 12:00 the sun is at 180°, so the dancer shows 220 − 180 = 40° clockwise. Line 2: The sun moves 15° clockwise each hour. Line 3: At 14:00 the sun is at 210°, so the dancer shows 220 − 210 = 10°. Line 4: So the angle stays at 40° all day, because the patch has not moved.

  14. Kira reads a classmate's notebook about a model dance. Which line has the mistake?

    • Line 4: the patch stays put, but the angle shrinks as the sun moves
    • Line 3: the angle should be 210 − 220 = −10°
    • Line 2: the sun should move 30° each hour
    • Line 1: the angle shows the kind of resource, not the direction
  15. Flocks and visits (model data)

    flock sizevisits a daychance one bird is lost in a day (%)
    10110
    10044
    1000161.6
  16. Ren's friend says a flock's risk falls in proportion to its size. Which reply uses the table best?

    • Agree: the risk is shared out evenly, so a flock 10 times larger has 10 times less risk each
    • Agree: 4% is half of 10%, so doubling the flock halves the risk
    • Disagree: bigger flocks are riskier, since visits rise from 1 to 16
    • Disagree: more visits arrive, so a flock 10 times larger cut the risk only from 10% to 4%
  17. Colony size and chicks (model data)

    nests in the colonychicks surviving per nest
    103.0
    402.5
    1601.8
  18. Tala claims living in a group helps every species. Which reply fits the model table?

    • Disagree: the table cannot say anything about benefits
    • Agree: 160 nests rear 288 chicks in total against 30 in the small colony, so the big colony wins
    • Disagree: chicks per nest fall from 3.0 to 1.8, so crowding costs more than the group gives here
    • Agree: 1.8 chicks per nest is still a benefit, so the group helps
  19. Use the table

    What the huddling study found (data: Gilbert et al. 2006)

    findingvalue
    average length of one huddle1.6 h
    huddlesdiscontinuous and variable in length
    access to the warmth of huddlesequal for all birds
    huddling time above 20 °C13%
  20. Zee claims edge birds in a huddle never get warm. Which reply fits the study?

    • Supported: only 13% of huddling time was above 20 °C
    • Not supported: huddles were short and changing, and every bird had equal access to warmth
    • Supported: huddles were uneven in size and length, so the edge birds must stay cold the whole time
    • Not supported: the study found birds were never cold