Births, deaths, immigration and emigration
Grade 9 Science Worksheet

Circle the best answer.
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One frog pond during one year (model data)
measure frogs frogs at the start of the year 200 births in the year 30 deaths in the year 10 Ari reads the model data for one frog pond. What is the per-capita birth rate for the year?
- 0.05 births per frog: 10 ÷ 200, the deaths row
- 30 births per frog: the total number of births
- 6.67 births per frog: 200 ÷ 30
- 0.15 births per frog: 30 ÷ 200
Two lakes of ducks during one year (model data)
lake ducks at the start births A 400 60 B 100 20 Bo reads the table. Which lake has the higher per-capita birth rate?
- Lake A: it had more births, 60 against 20 for lake B
- Lake A: it started with more ducks, 400 against 100
- Lake A: 0.15 births per duck, against 0.20 for lake B
- Lake B: 0.20 births per duck, against 0.15 for lake A
Turtles in one year with no moves in or out (model data)
measure value turtles at the start of the year 500 births per turtle 0.20 deaths per turtle 0.08 Esme reads the model data for 500 turtles. No turtles move in or out. What is the change in the number of turtles in one year?
- +100: 0.20 × 500, the births alone and no losses
- +0.12: 0.20 − 0.08, a rate and not a count
- +60: (0.20 − 0.08) × 500
- +140: (0.20 + 0.08) × 500, the two rates added
Birds in one wood, starting with 120 birds (model data)
year births deaths immigrants emigrants 1 15 6 4 3 2 12 9 2 8 3 18 7 5 4 Jun reads the table. Immigrants moved in; emigrants moved out. How many birds are in the wood at the end of year 3?
- 165 birds: 120 plus the births of the 3 years
- 132 birds: 120 plus the year 3 change alone
- 143 birds: 120 plus births minus deaths, no moves
- 139 birds: 120 + 10 − 3 + 12
Snails in one marsh for one year (model data)
count snails at the start of the year 200 births 30 deaths 12 immigrants (moved in) 5 emigrants (moved out) ? at the end of the year 205 Kira reads the table of snails in one marsh for a year. How many emigrants moved out?
- 18 snails: 200 + 30 + 5 − 12 − 205
- 5 snails: 205 − 200, the net change
- 13 snails: 200 + 30 − 12 − 205, no arrivals
- 23 snails: 30 + 5 − 12, the gain of the year
Turtles on one island (model data)
year births deaths immigrants emigrants 1 30 20 6 4 2 40 25 5 30 3 15 22 20 3 4 28 28 2 2 Luz reads the table of turtles on one island. Immigrants moved in; emigrants moved out. In which year did the number of turtles fall?
- Year 2: a fall of 10, as 30 moved out
- Year 4: births and deaths are both 28, so it fell
- Year 1: deaths, 20, and emigrants, 4, make 24 lost, so it fell
- Year 3: deaths, 22, are more than births, 15
Two plots of seedlings after one night of frost (model data)
plot seedlings before seedlings after percent that survive sparse plot 50 30 60 crowded plot 400 240 60 Milo reads the model data after one night of frost. Which type of factor is the frost?
- Neither type: a frost is not a factor that changes a population
- Density-independent: the frost did not change the seedlings in either plot
- Density-dependent: the crowded plot had 160 fewer seedlings, the sparse plot 20 fewer
- Density-independent: both plots kept 60%, sparse or crowded
Plants per square meter and the percent that survive the year (model data)
plants per square meter percent that survive 10 90 40 70 80 45 Noah reads the model data. Which statement fits the table?
- A density-independent effect: weather reached the three plots alike
- A density-dependent effect: a smaller share survives as crowding rises
- A density-dependent effect: a larger share survives as crowding rises
- A density-independent effect: the share that survives is the same in each plot
Mark and recapture on one lake (model data)
step ducks marked and released in the first catch 60 caught in the second catch 90 marked ducks in the second catch 15 Ren reads the model data for one lake. What is the estimate of the number of ducks in the lake?
- 150 ducks: 60 + 90, the two catches added
- 135 ducks: 60 + 90 − 15, the counts added
- 10 ducks: (60 × 15) ÷ 90, flipped
- 360 ducks: (60 × 90) ÷ 15
Mark and recapture on one pond (model data)
step frogs marked and released in the first catch 45 caught in the second catch 60 marked frogs in the second catch 18 Tala reads the model data for one pond. Estimate the number of frogs in the pond.
- 13.5 frogs: (45 × 18) ÷ 60, flipped
- 87 frogs: 45 + 60 − 18, the counts added
- 60 frogs: the number caught the second time
- 150 frogs: (45 × 60) ÷ 18