Piecewise continuity and the Intermediate Value Theorem
Grade 12 Math Worksheet - Building Confidence

Circle the best answer, or write your answer on the line.
f(x) = 3x + 1 for x < 2 and f(x) = x + 5 for x ≥ 2. Ari checks the join. What happens at x = 2?
- a jump at x = 2
- a hole at x = 2
- continuous at x = 2
f(x) = x + 2 for x < 3 and f(x) = 2x − 1 for x ≥ 3. Esme checks the join. What happens at x = 3?
- continuous at x = 3
- a jump at x = 3
- a hole at x = 3
f(x) = 4x + 6 for x < -1 and f(x) = -x + 3 for x ≥ -1. Jun checks the join. What happens at x = -1?
- a jump at x = -1
- continuous at x = -1
- a hole at x = -1
f(x) = 2x + 1 for x < 3 and f(x) = -x + 12 for x ≥ 3. Kira needs f(3). What is it?
f(x) = 5x − 3 for x < 2 and f(x) = 3x − 2 for x ≥ 2. Luz needs f(2). What is it?
f(x) = -2x + 8 for x < 1 and f(x) = 4x + 3 for x ≥ 1. Noah needs f(1). What is it?
f is continuous on [0, 4], with f(0) = -3 and f(4) = 5. Pia asks about a zero. Which is true?
- yes: f must cross 0 between 0 and 4
- no zero is possible on [0, 4]
- the IVT does not promise a zero on [0, 4]
f is continuous on [1, 6], with f(1) = 2 and f(6) = 9. Ren asks about a zero. Which is true?
- the IVT does not promise a zero on [1, 6]
- no zero is possible on [1, 6]
- yes: f must cross 0 between 1 and 6
f is continuous on [2, 5], with f(2) = 7 and f(5) = -1. Tala asks about a zero. Which is true?
- no zero is possible on [2, 5]
- the IVT does not promise a zero on [2, 5]
- yes: f must cross 0 between 2 and 5
f is continuous on [0, 3], with f(0) = 4 and f(3) = 10. Zee asks about a zero. Which is true?
- no zero is possible on [0, 3]
- the IVT does not promise a zero on [0, 3]
- yes: f must cross 0 between 0 and 3