Optimization problems

Grade 12 Math Worksheet

NameDate

Circle the best answer, or write your answer on the line.

  1. Esme uses 66 m of fence to make two pens side by side: three fences of length x and two of length y. What x gives the most total area?

  2. Jun uses 72 m of fence to make two pens side by side: three fences of length x and two of length y. What x gives the most total area?

  3. Milo cuts a square of side x from each corner of a 12 cm square card and folds up an open box. What x gives the largest volume?

  4. Noah cuts a square of side x from each corner of a 18 cm square card and folds up an open box. What x gives the largest volume?

  5. Ren cuts a square of side x from each corner of a 30 cm square card and folds up an open box. What x gives the largest volume?

  6. Zee cuts a square of side x from each corner of a 24 cm square card and folds up an open box. What x gives the largest volume?

  7. A(x) = 30x − x² has A′(15) = 0, and A″(x) = −2. What can Tala conclude about x = 15?

    • A″ < 0 there, so x = 15 gives a maximum
    • A″ < 0 there, so x = 15 gives a minimum
    • A′(15) = 0 is enough to call x = 15 a maximum
  8. C(x) = 2x + 50/x has C′(5) = 0, and C″(5) = 0.8. What can Esme conclude about x = 5?

    • C″ > 0 there, so x = 5 gives a maximum
    • C′(5) = 0 is enough to call x = 5 a minimum
    • C″ > 0 there, so x = 5 gives a minimum
  9. Jun's box volume V(x) = 4x³ − 48x² + 144x has V′(2) = 0, and V″(2) = −48. What does that show about x = 2?

    • V″ < 0 there, so x = 2 gives a maximum
    • V″ < 0 there, so x = 2 gives a minimum
    • V′(2) = 0 is enough to call x = 2 a maximum
  10. D(x) = x² − 8x + 20 has D′(4) = 0, and D″(x) = 2. What can Kira conclude about x = 4?

    • D′(4) = 0 is enough to call x = 4 a minimum
    • D″ > 0 there, so x = 4 gives a maximum
    • D″ > 0 there, so x = 4 gives a minimum
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Optimization problems

Answer Key - Grade 12 Math Worksheet

Circle the best answer, or write your answer on the line.

  1. Esme uses 66 m of fence to make two pens side by side: three fences of length x and two of length y. What x gives the most total area?

    11
  2. Jun uses 72 m of fence to make two pens side by side: three fences of length x and two of length y. What x gives the most total area?

    12
  3. Milo cuts a square of side x from each corner of a 12 cm square card and folds up an open box. What x gives the largest volume?

    2
  4. Noah cuts a square of side x from each corner of a 18 cm square card and folds up an open box. What x gives the largest volume?

    3
  5. Ren cuts a square of side x from each corner of a 30 cm square card and folds up an open box. What x gives the largest volume?

    5
  6. Zee cuts a square of side x from each corner of a 24 cm square card and folds up an open box. What x gives the largest volume?

    4
  7. A(x) = 30x − x² has A′(15) = 0, and A″(x) = −2. What can Tala conclude about x = 15?

    • A″ < 0 there, so x = 15 gives a maximum
    • A″ < 0 there, so x = 15 gives a minimum
    • A′(15) = 0 is enough to call x = 15 a maximum
  8. C(x) = 2x + 50/x has C′(5) = 0, and C″(5) = 0.8. What can Esme conclude about x = 5?

    • C″ > 0 there, so x = 5 gives a maximum
    • C′(5) = 0 is enough to call x = 5 a minimum
    • C″ > 0 there, so x = 5 gives a minimum
  9. Jun's box volume V(x) = 4x³ − 48x² + 144x has V′(2) = 0, and V″(2) = −48. What does that show about x = 2?

    • V″ < 0 there, so x = 2 gives a maximum
    • V″ < 0 there, so x = 2 gives a minimum
    • V′(2) = 0 is enough to call x = 2 a maximum
  10. D(x) = x² − 8x + 20 has D′(4) = 0, and D″(x) = 2. What can Kira conclude about x = 4?

    • D′(4) = 0 is enough to call x = 4 a minimum
    • D″ > 0 there, so x = 4 gives a maximum
    • D″ > 0 there, so x = 4 gives a minimum