Add, subtract and scale vectors
Grade 10 Math Worksheet - Challenge Me

Circle the best answer.
Ground velocity is their sum. Noah's plane has airspeed vector ⟨240, 0⟩ km/h. The wind adds ⟨-70, 168⟩ km/h (182 km/h in all). Which statement about the plane's motion over the ground is correct?
- It moves at 422 km/h, since the plane's 240 and the wind's 182 add
- It moves at 170 km/h and keeps heading east, since just the headwind part counts
- It moves at about 353 km/h, and it heads about 28° south of east
- About 239 km/h, nearly its airspeed, but heading about 45° north of east
A student claims |u − v| = |u| − |v|. With u = ⟨12, 5⟩ and v = ⟨3, 4⟩ that gives 13 − 5 = 8. Kira checks it. What does Kira find?
u = ⟨12, 5⟩ has length 13. v = ⟨3, 4⟩ has length 5. The claim says |u − v| = 8. u = ⟨12, 5⟩ has length 13. v = ⟨3, 4⟩ has length 5. The claim says |u − v| = 8. u = ⟨12, 5⟩ v = ⟨3, 4⟩ x y u has length 13 v has length 5 claim: |u - v| = 8 - The claim fails: u − v = ⟨15, 9⟩ has length about 17.5
- The claim fails: u − v = ⟨9, 1⟩ has length √82, about 9.1, not 8
- The claim holds: 13 − 5 = 8, and both lengths are exact whole numbers
- The claim fails: u − v = ⟨9, 1⟩ has length 82, not 8
A sled track passes through P(1, 2) and Q(7, 5). Ari places flag R(13, k) on the same straight line. Which k works?
Points P(1, 2) and Q(7, 5) lie on one straight line. R(13, k) is also on it. Points P(1, 2) and Q(7, 5) lie on one straight line. R(13, k) is also on it. R(13, k) is also on it. 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 0 1 2 3 4 5 6 7 8 P Q - k = 11
- k = 8
- k = 6
- k = 10
Tala's quilt has corners A(0, 0), B(6, 2), C(10, 7) and D(3, 5) in order. Tala asks if ABCD is a parallelogram. Which reasoning is correct?
Quadrilateral ABCD with A(0, 0), B(6, 2), C(10, 7), D(3, 5). A parallelogram needs AB = DC and AD = BC as vectors. Quadrilateral ABCD with A(0, 0), B(6, 2), C(10, 7), D(3, 5). A parallelogram needs AB = DC and AD = BC as vectors. A parallelogram needs AB = DC and AD = BC as vectors. −1 1 2 3 4 5 6 7 8 9 10 11 −1 1 2 3 4 5 6 7 8 0 A B C D - Yes: AB + BC = AD + DC = ⟨10, 7⟩, so the sides add the same
- No: AB = ⟨6, 2⟩ but DC = ⟨7, 2⟩, so opposite sides are not equal vectors
- Yes: AB and DC both rise 2 units, so those two sides must be parallel
- No: the diagonals AC and BD have different lengths, and a parallelogram's must match
Pia's two rocket paths ⟨3, k⟩ and ⟨-12, 20⟩ lie along one line. Which k works, and do the paths point the same way?
Vectors ⟨3, k⟩ and ⟨-12, 20⟩ are on one line, so one is a scalar multiple of the other. Vectors ⟨3, k⟩ and ⟨-12, 20⟩ are on one line, so one is a scalar multiple of the other. Vectors ?3, k? and ?-12, 20? are on one line, so one is a scalar multiple of the other. ?-12, 20? - k = -5; they point opposite ways, because the multiplier is -1/4
- k = 5; they point the same way, because 20 ÷ 4 = 5
- k = -80; they point opposite ways, because -12 ÷ 3 = -4
- k = -5; they point the same way, because a multiplier below 1 just shrinks
Zee's quilt is parallelogram ABCD with A at the origin, AB = u = ⟨6, 0⟩ and AD = v = ⟨2, 4⟩. M is the midpoint of side DC. Which vector is AM?
Parallelogram ABCD with A(0, 0), B(6, 0), D(2, 4) and C(8, 4). M is the midpoint of DC. Parallelogram ABCD with A(0, 0), B(6, 0), D(2, 4) and C(8, 4). M is the midpoint of DC. M is the midpoint of DC. −1 1 2 3 4 5 6 7 8 9 −1 1 2 3 4 5 0 A B D C - ⟨-1, 4⟩, which is v − ½u
- ⟨5, 4⟩, which is v + ½u
- ⟨4, 2⟩, which is ½(u + v)
- ⟨7, 2⟩, which is u + ½v
Two vectors satisfy u + v = ⟨5, 1⟩ and u − v = ⟨1, 7⟩. Jun's car and trailer move with u + v = ⟨5, 1⟩ and u − v = ⟨1, 7⟩. Which pair gives u and v?
- u = ⟨3, 4⟩ and v = ⟨2, -3⟩
- u = ⟨2, -3⟩ and v = ⟨3, 4⟩
- u = ⟨3, 4⟩ and v = ⟨-2, 3⟩
- u = ⟨6, 8⟩ and v = ⟨4, -6⟩
Milo's drone log shows positions from the start of (4, 3), (8, 6) and (12, 10) km after 1, 2 and 3 hours. Milo claims constant velocity. What does the log show?
Positions in km from the start (0, 0): after 1 hour (4, 3); after 2 hours (8, 6); after 3 hours (12, 10). Positions in km from the start (0, 0): after 1 hour (4, 3); after 2 hours (8, 6); after 3 hours (12, 10). Positions in km from the start 0 4 8 12 3 6 10 km from start km (0, 0) after 1 hour (4, 3) after 2 hours (8, 6) after 3 hours (12, 10) - Not constant: the distances from the start are 5, 10 and about 15.6 km, so they grow
- Constant: the first two hours match, so the third reading must be a small error
- Not constant: the hourly slides are ⟨4, 3⟩, ⟨4, 3⟩ and ⟨4, 4⟩, so hour 3 differs
- Constant: the run grows by exactly 4 km in each hour
Kira's triangle has corners P(0, 0), Q(9, 3) and R(3, 6). Kira says G(4, 3) is two-thirds of the way along the median from P. Which check settles it?
Triangle PQR with P(0, 0), Q(9, 3), R(3, 6). The median from P goes to M, the midpoint of QR. Triangle PQR with P(0, 0), Q(9, 3), R(3, 6). The median from P goes to M, the midpoint of QR. 0 1 2 3 4 5 6 7 8 9 10 0 1 2 3 4 5 6 7 P Q R Triangle PQR. The median from P goes to M, the midpoint of QR. - Add the corners: P + Q + R = (12, 9), which is not G, so the claim fails
- ½ of side PQ is ⟨4.5, 1.5⟩, which is not G, so the claim fails
- Find M = ½(Q + R) = (6, 4.5); then ⅔ of ⟨6, 4.5⟩ is ⟨4, 3⟩, so the claim holds
- Find M = (6, 4.5); ½ of that is (3, 2.25), not G, so the claim fails
Read this first
Use this
|u| = 5, |v| = 10. u + v = ⟨-2, 11⟩, so |u + v|² = 4 + 121 = 125.
Luz tests u = ⟨4, 3⟩ and v = ⟨-6, 8⟩. Their lengths are 5 and 10, and |u + v| = √125. What does 5² + 10² = 125 show?
- u and v are perpendicular, so u + v closes a right triangle with legs 5 and 10
- Nothing: 125 is a coincidence that depends on these particular numbers
- u and v point the same way, so the lengths add and |u + v| = 15
- u and v point opposite ways, so |u + v| = 10 − 5 = 5, the lengths' difference