Angle and parallel-line proofs: fill in the missing reason
Grade 10 Math Worksheet - Challenge Me

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Given: UV ∥ WY. Prove: ∠USQ and ∠SQW are supplementary. Ladder: 1. UV ∥ WY -- Given; 2. ∠USQ ≅ ∠SQY -- Alternate interior angles theorem; 3. m∠USQ = m∠SQY -- Definition of congruent angles; 4. ∠SQW and ∠SQY are supplementary -- Linear pair postulate; 5. m∠SQW + m∠SQY = 180 -- Definition of supplementary angles; 6. m∠SQW + m∠USQ = 180 -- ?; 7. ∠USQ and ∠SQW are supplementary -- Definition of supplementary angles.
Ari proves the same-side interior angles theorem on train rails UV and WY. Which reason fills the blank?
- Substitution property
- Definition of supplementary angles
- Linear pair postulate
- Transitive property
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Given: UV ∥ WY. Prove: ∠VSQ and ∠SQY are supplementary. Ladder: 1. UV ∥ WY -- Given; 2. ∠VSQ ≅ ∠SQW -- Alternate interior angles theorem; 3. m∠VSQ = m∠SQW -- Definition of congruent angles; 4. ∠SQY and ∠SQW are supplementary -- Linear pair postulate; 5. m∠SQY + m∠SQW = 180 -- Definition of supplementary angles; 6. m∠SQY + m∠VSQ = 180 -- ?; 7. ∠VSQ and ∠SQY are supplementary -- Definition of supplementary angles.
Bo proves the same-side interior angles theorem on rug stripes UV and WY. Which reason fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠VSQ and ∠SQY are supplementary. Ladder: 1. UV ∥ WY — Given; 2. ∠VSQ ≅ ∠SQW — Alternate interior angles theorem; 3. m∠VSQ = m∠SQW — Definition of congruent angles; 4. ∠SQY and ∠SQW are supplementary — Linear pair postulate; 5. m∠SQY + m∠SQW = 180 — Definition of supplementary angles; 6. m∠SQY + m∠VSQ = 180 — ?; 7. ∠VSQ and ∠SQY are supplementary — Definition of supplementary angles. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠VSQ and ∠SQY are supplementary. Ladder: 1. UV ∥ WY — Given; 2. ∠VSQ ≅ ∠SQW — Alternate interior angles theorem; 3. m∠VSQ = m∠SQW — Definition of congruent angles; 4. ∠SQY and ∠SQW are supplementary — Linear pair postulate; 5. m∠SQY + m∠SQW = 180 — Definition of supplementary angles; 6. m∠SQY + m∠VSQ = 180 — ?; 7. ∠VSQ and ∠SQY are supplementary — Definition of supplementary angles. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. U V S W Y Q H D - Given
- Substitution property
- Addition property of equality
- Vertical angles theorem
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Given: ∠USQ and ∠SQW are supplementary. Prove: UV ∥ WY. Ladder: 1. ∠USQ and ∠SQW are supplementary -- Given; 2. ∠SQW and ∠SQY are supplementary -- Linear pair postulate; 3. ∠USQ ≅ ∠SQY -- ?; 4. UV ∥ WY -- Converse of the alternate interior angles theorem.
Kira checks that tent poles UV and WY are parallel, using a cord HD. Which reason fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠USQ and ∠SQW labeled supplementary. Given: ∠USQ and ∠SQW are supplementary. Prove: UV ∥ WY. Ladder: 1. ∠USQ and ∠SQW are supplementary — Given; 2. ∠SQW and ∠SQY are supplementary — Linear pair postulate; 3. ∠USQ ≅ ∠SQY — ?; 4. UV ∥ WY — Converse of the alternate interior angles theorem. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠USQ and ∠SQW labeled supplementary. Given: ∠USQ and ∠SQW are supplementary. Prove: UV ∥ WY. Ladder: 1. ∠USQ and ∠SQW are supplementary — Given; 2. ∠SQW and ∠SQY are supplementary — Linear pair postulate; 3. ∠USQ ≅ ∠SQY — ?; 4. UV ∥ WY — Converse of the alternate interior angles theorem. ∠USQ and ∠SQW supplementary U V W Y H D S Q Not to scale. - Alternate interior angles theorem
- Vertical angles theorem
- Congruent complements theorem
- Congruent supplements theorem
Luz checks that a door's edges UV and WY are parallel, using a ribbon HD. Which reason fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠VSQ and ∠SQY labeled supplementary. Given: ∠VSQ and ∠SQY are supplementary. Prove: UV ∥ WY. Ladder: 1. ∠VSQ and ∠SQY are supplementary — Given; 2. ∠SQY and ∠SQW are supplementary — Linear pair postulate; 3. ∠VSQ ≅ ∠SQW — ?; 4. UV ∥ WY — Converse of the alternate interior angles theorem. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠VSQ and ∠SQY labeled supplementary. Given: ∠VSQ and ∠SQY are supplementary. Prove: UV ∥ WY. Ladder: 1. ∠VSQ and ∠SQY are supplementary — Given; 2. ∠SQY and ∠SQW are supplementary — Linear pair postulate; 3. ∠VSQ ≅ ∠SQW — ?; 4. UV ∥ WY — Converse of the alternate interior angles theorem. ∠VSQ ∠SQY ∠SQW U V W Y H S Q D 1. ∠VSQ and ∠SQY are supplementary -- Given 2. ∠SQY and ∠SQW are supplementary -- Linear pair postulate 3. ∠VSQ ≅ ∠SQW -- ? 4. UV ∥ WY -- Converse of the alternate interior angles theorem Not to scale. - Congruent complements theorem
- Vertical angles theorem
- Congruent supplements theorem
- Alternate interior angles theorem
Use this
Given: UV ∥ WY. Prove: ∠USQ and ∠SQW are supplementary. Ladder: 1. UV ∥ WY -- Given; 2. ∠USQ ≅ ∠WQD -- Corresponding angles postulate; 3. m∠USQ = m∠WQD -- Definition of congruent angles; 4. ? -- Linear pair postulate; 5. m∠SQW + m∠WQD = 180 -- Definition of supplementary angles; 6. m∠SQW + m∠USQ = 180 -- Substitution property; 7. ∠USQ and ∠SQW are supplementary -- Definition of supplementary angles.
Esme proves the same-side interior angles theorem a second way, on map streets UV and WY. Which statement fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠USQ and ∠SQW are supplementary. Ladder: 1. UV ∥ WY — Given; 2. ∠USQ ≅ ∠WQD — Corresponding angles postulate; 3. m∠USQ = m∠WQD — Definition of congruent angles; 4. ? — Linear pair postulate; 5. m∠SQW + m∠WQD = 180 — Definition of supplementary angles; 6. m∠SQW + m∠USQ = 180 — Substitution property; 7. ∠USQ and ∠SQW are supplementary — Definition of supplementary angles. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠USQ and ∠SQW are supplementary. Ladder: 1. UV ∥ WY — Given; 2. ∠USQ ≅ ∠WQD — Corresponding angles postulate; 3. m∠USQ = m∠WQD — Definition of congruent angles; 4. ? — Linear pair postulate; 5. m∠SQW + m∠WQD = 180 — Definition of supplementary angles; 6. m∠SQW + m∠USQ = 180 — Substitution property; 7. ∠USQ and ∠SQW are supplementary — Definition of supplementary angles. Sketch, not to scale U S V W Q Y H D - ∠USQ and ∠SQW are supplementary
- ∠SQW ≅ ∠WQD
- ∠SQW and ∠WQD are supplementary
- ∠SQW and ∠WQD are complementary
Use this
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠VSQ and ∠SQY are supplementary. Ladder: 1. UV ∥ WY -- Given; 2. ∠VSQ ≅ ∠YQD -- Corresponding angles postulate; 3. m∠VSQ = m∠YQD -- Definition of congruent angles; 4. ? -- Linear pair postulate; 5. m∠SQY + m∠YQD = 180 -- Definition of supplementary angles; 6. m∠SQY + m∠VSQ = 180 -- Substitution property; 7. ∠VSQ and ∠SQY are supplementary -- Definition of supplementary angles.
Jun proves the same-side interior angles theorem a second way, on window bars UV and WY. Which statement fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠VSQ and ∠SQY are supplementary. Ladder: 1. UV ∥ WY — Given; 2. ∠VSQ ≅ ∠YQD — Corresponding angles postulate; 3. m∠VSQ = m∠YQD — Definition of congruent angles; 4. ? — Linear pair postulate; 5. m∠SQY + m∠YQD = 180 — Definition of supplementary angles; 6. m∠SQY + m∠VSQ = 180 — Substitution property; 7. ∠VSQ and ∠SQY are supplementary — Definition of supplementary angles. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠VSQ and ∠SQY are supplementary. Ladder: 1. UV ∥ WY — Given; 2. ∠VSQ ≅ ∠YQD — Corresponding angles postulate; 3. m∠VSQ = m∠YQD — Definition of congruent angles; 4. ? — Linear pair postulate; 5. m∠SQY + m∠YQD = 180 — Definition of supplementary angles; 6. m∠SQY + m∠VSQ = 180 — Substitution property; 7. ∠VSQ and ∠SQY are supplementary — Definition of supplementary angles. U V W Y H S Q D Not to scale. - ∠SQY ≅ ∠YQD
- ∠SQY and ∠YQD are supplementary
- ∠VSQ and ∠SQY are supplementary
- ∠SQY and ∠YQD are complementary
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Sketch, not to scale: rays QC, QD, QF and QG come out of point Q in that order, turning one way. Marked: right-angle boxes at ∠CQF and ∠DQG. Given: ∠CQF and ∠DQG are right angles. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQF and ∠DQG are right angles -- Given; 2. m∠CQF = 90 and m∠DQG = 90 -- Definition of right angle; 3. ? -- Angle addition postulate; 4. m∠DQF + m∠FQG = m∠DQG -- Angle addition postulate; 5. m∠CQD + m∠DQF = 90 and m∠DQF + m∠FQG = 90 -- Substitution property; 6. ∠CQD and ∠DQF are complementary, and so are ∠DQF and ∠FQG -- Definition of complementary angles; 7. ∠CQD ≅ ∠FQG -- Congruent complements theorem.
Milo folds a paper fan whose folds are rays QC, QD, QF and QG. Which statement fills the blank?
Sketch, not to scale: rays QC, QD, QF and QG come out of point Q in that order, turning one way. Marked: right-angle boxes at ∠CQF and ∠DQG. Given: ∠CQF and ∠DQG are right angles. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQF and ∠DQG are right angles — Given; 2. m∠CQF = 90 and m∠DQG = 90 — Definition of right angle; 3. ? — Angle addition postulate; 4. m∠DQF + m∠FQG = m∠DQG — Angle addition postulate; 5. m∠CQD + m∠DQF = 90 and m∠DQF + m∠FQG = 90 — Substitution property; 6. ∠CQD and ∠DQF are complementary, and so are ∠DQF and ∠FQG — Definition of complementary angles; 7. ∠CQD ≅ ∠FQG — Congruent complements theorem. Sketch, not to scale: rays QC, QD, QF and QG come out of point Q in that order, turning one way. Marked: right-angle boxes at ∠CQF and ∠DQG. Given: ∠CQF and ∠DQG are right angles. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQF and ∠DQG are right angles — Given; 2. m∠CQF = 90 and m∠DQG = 90 — Definition of right angle; 3. ? — Angle addition postulate; 4. m∠DQF + m∠FQG = m∠DQG — Angle addition postulate; 5. m∠CQD + m∠DQF = 90 and m∠DQF + m∠FQG = 90 — Substitution property; 6. ∠CQD and ∠DQF are complementary, and so are ∠DQF and ∠FQG — Definition of complementary angles; 7. ∠CQD ≅ ∠FQG — Congruent complements theorem. Q C D F G Not to scale. - m∠CQD + m∠DQF = m∠CQF
- ∠CQD ≅ ∠FQG
- m∠CQD + m∠DQF = 180
- m∠CQD + m∠FQG = m∠CQG
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Given: ∠UQW and ∠VQY are right angles. Prove: ∠UQV ≅ ∠WQY. Ladder: 1. ∠UQW and ∠VQY are right angles -- Given; 2. m∠UQW = 90 and m∠VQY = 90 -- Definition of right angle; 3. m∠UQV + m∠VQW = m∠UQW -- Angle addition postulate; 4. ? -- Angle addition postulate; 5. m∠UQV + m∠VQW = 90 and m∠VQW + m∠WQY = 90 -- Substitution property; 6. ∠UQV and ∠VQW are complementary, and so are ∠VQW and ∠WQY -- Definition of complementary angles; 7. ∠UQV ≅ ∠WQY -- Congruent complements theorem.
Noah draws four sun rays QU, QV, QW and QY from one center Q. Which statement fills the blank?
Sketch, not to scale: rays QU, QV, QW and QY come out of point Q in that order, turning one way. Marked: right-angle boxes at ∠UQW and ∠VQY. Given: ∠UQW and ∠VQY are right angles. Prove: ∠UQV ≅ ∠WQY. Ladder: 1. ∠UQW and ∠VQY are right angles — Given; 2. m∠UQW = 90 and m∠VQY = 90 — Definition of right angle; 3. m∠UQV + m∠VQW = m∠UQW — Angle addition postulate; 4. ? — Angle addition postulate; 5. m∠UQV + m∠VQW = 90 and m∠VQW + m∠WQY = 90 — Substitution property; 6. ∠UQV and ∠VQW are complementary, and so are ∠VQW and ∠WQY — Definition of complementary angles; 7. ∠UQV ≅ ∠WQY — Congruent complements theorem. Sketch, not to scale: rays QU, QV, QW and QY come out of point Q in that order, turning one way. Marked: right-angle boxes at ∠UQW and ∠VQY. Given: ∠UQW and ∠VQY are right angles. Prove: ∠UQV ≅ ∠WQY. Ladder: 1. ∠UQW and ∠VQY are right angles — Given; 2. m∠UQW = 90 and m∠VQY = 90 — Definition of right angle; 3. m∠UQV + m∠VQW = m∠UQW — Angle addition postulate; 4. ? — Angle addition postulate; 5. m∠UQV + m∠VQW = 90 and m∠VQW + m∠WQY = 90 — Substitution property; 6. ∠UQV and ∠VQW are complementary, and so are ∠VQW and ∠WQY — Definition of complementary angles; 7. ∠UQV ≅ ∠WQY — Congruent complements theorem. ∠UQW ∠VQY Q U V W Y Not to scale. - m∠VQW + m∠WQY = m∠VQY
- ∠UQV ≅ ∠WQY
- m∠UQV + m∠WQY = m∠UQY
- m∠VQW + m∠WQY = 180
Tala proves the converse of the alternate exterior angles theorem on quilt stripes UV and WY. Which statement and reason fill the blanks?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠HSU and ∠YQD with one arc each. Given: ∠HSU ≅ ∠YQD. Prove: UV ∥ WY. Ladder: 1. ∠HSU ≅ ∠YQD — Given; 2. ∠VSQ ≅ ∠HSU — Vertical angles theorem; 3. ? — ?; 4. UV ∥ WY — Converse of the corresponding angles postulate. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠HSU and ∠YQD with one arc each. Given: ∠HSU ≅ ∠YQD. Prove: UV ∥ WY. Ladder: 1. ∠HSU ≅ ∠YQD — Given; 2. ∠VSQ ≅ ∠HSU — Vertical angles theorem; 3. ? — ?; 4. UV ∥ WY — Converse of the corresponding angles postulate. U S V W Q Y H D Given: ∠HSU ≅ ∠YQD Prove: UV ∥ WY Not to scale. statement reason 1. ∠HSU ≅ ∠YQD Given 2. ∠VSQ ≅ ∠HSU Vertical angles theorem 3. ? ? 4. UV ∥ WY Converse of the corresponding angles postulate - ∠HSU ≅ ∠VSQ — Reflexive property
- ∠VSQ ≅ ∠YQD — Corresponding angles postulate
- ∠VSQ ≅ ∠YQD — Symmetric property
- ∠VSQ ≅ ∠YQD — Transitive property
Use this
Given: ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF -- Given; 2. m∠CQD + m∠DQF = 90 -- Definition of complementary angles; 3. m∠FQG + m∠DQF = 90 -- Definition of complementary angles; 4. m∠CQD + m∠DQF = m∠FQG + m∠DQF -- Substitution property; 5. ? -- ?; 6. ∠CQD ≅ ∠FQG -- Definition of congruent angles.
Pia proves the congruent complements theorem on a paper fan with folds QC, QD, QF and QG. Which statement and reason fill the blanks?
Sketch, not to scale: rays QC, QD, QF and QG come out of point Q in that order, turning one way. Marked: ∠CQD and ∠DQF labeled complementary; ∠FQG and ∠DQF labeled complementary. Given: ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF — Given; 2. m∠CQD + m∠DQF = 90 — Definition of complementary angles; 3. m∠FQG + m∠DQF = 90 — Definition of complementary angles; 4. m∠CQD + m∠DQF = m∠FQG + m∠DQF — Substitution property; 5. ? — ?; 6. ∠CQD ≅ ∠FQG — Definition of congruent angles. Sketch, not to scale: rays QC, QD, QF and QG come out of point Q in that order, turning one way. Marked: ∠CQD and ∠DQF labeled complementary; ∠FQG and ∠DQF labeled complementary. Given: ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF — Given; 2. m∠CQD + m∠DQF = 90 — Definition of complementary angles; 3. m∠FQG + m∠DQF = 90 — Definition of complementary angles; 4. m∠CQD + m∠DQF = m∠FQG + m∠DQF — Substitution property; 5. ? — ?; 6. ∠CQD ≅ ∠FQG — Definition of congruent angles. ∠CQD and ∠DQF complementary; ∠FQG and ∠DQF complementary Q C D F G Not to scale. - m∠CQD = m∠DQF — Subtraction property of equality
- m∠CQD = m∠FQG — Subtraction property of equality
- m∠CQD = m∠FQG — Addition property of equality
- ∠CQD ≅ ∠FQG — Congruent complements theorem