Angle and parallel-line proofs: fill in the missing reason
Grade 10 Math Worksheet - Challenge Me

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Given: UV ∥ WY. Prove: ∠VSQ and ∠SQY are supplementary. Ladder: 1. UV ∥ WY -- Given; 2. ∠VSQ ≅ ∠SQW -- Alternate interior angles theorem; 3. m∠VSQ = m∠SQW -- Definition of congruent angles; 4. ∠SQY and ∠SQW are supplementary -- Linear pair postulate; 5. m∠SQY + m∠SQW = 180 -- Definition of supplementary angles; 6. m∠SQY + m∠VSQ = 180 -- ?; 7. ∠VSQ and ∠SQY are supplementary -- Definition of supplementary angles.
Bo proves the same-side interior angles theorem on rug stripes UV and WY. Which reason fills the blank?
- Substitution property
- Given
- Vertical angles theorem
- Addition property of equality
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Given: ∠USQ and ∠SQW are supplementary. Prove: UV ∥ WY. Ladder: 1. ∠USQ and ∠SQW are supplementary -- Given; 2. ∠SQW and ∠SQY are supplementary -- Linear pair postulate; 3. ∠USQ ≅ ∠SQY -- ?; 4. UV ∥ WY -- Converse of the alternate interior angles theorem.
Kira checks that tent poles UV and WY are parallel, using a cord HD. Which reason fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠USQ and ∠SQW labeled supplementary. Given: ∠USQ and ∠SQW are supplementary. Prove: UV ∥ WY. Ladder: 1. ∠USQ and ∠SQW are supplementary — Given; 2. ∠SQW and ∠SQY are supplementary — Linear pair postulate; 3. ∠USQ ≅ ∠SQY — ?; 4. UV ∥ WY — Converse of the alternate interior angles theorem. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠USQ and ∠SQW labeled supplementary. Given: ∠USQ and ∠SQW are supplementary. Prove: UV ∥ WY. Ladder: 1. ∠USQ and ∠SQW are supplementary — Given; 2. ∠SQW and ∠SQY are supplementary — Linear pair postulate; 3. ∠USQ ≅ ∠SQY — ?; 4. UV ∥ WY — Converse of the alternate interior angles theorem. ∠USQ and ∠SQW supplementary U V W Y H D S Q Not to scale. - Congruent supplements theorem
- Alternate interior angles theorem
- Congruent complements theorem
- Vertical angles theorem
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Given: UV ∥ WY. Prove: ∠USQ and ∠SQW are supplementary. Ladder: 1. UV ∥ WY -- Given; 2. ∠USQ ≅ ∠WQD -- Corresponding angles postulate; 3. m∠USQ = m∠WQD -- Definition of congruent angles; 4. ? -- Linear pair postulate; 5. m∠SQW + m∠WQD = 180 -- Definition of supplementary angles; 6. m∠SQW + m∠USQ = 180 -- Substitution property; 7. ∠USQ and ∠SQW are supplementary -- Definition of supplementary angles.
Esme proves the same-side interior angles theorem a second way, on map streets UV and WY. Which statement fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠USQ and ∠SQW are supplementary. Ladder: 1. UV ∥ WY — Given; 2. ∠USQ ≅ ∠WQD — Corresponding angles postulate; 3. m∠USQ = m∠WQD — Definition of congruent angles; 4. ? — Linear pair postulate; 5. m∠SQW + m∠WQD = 180 — Definition of supplementary angles; 6. m∠SQW + m∠USQ = 180 — Substitution property; 7. ∠USQ and ∠SQW are supplementary — Definition of supplementary angles. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠USQ and ∠SQW are supplementary. Ladder: 1. UV ∥ WY — Given; 2. ∠USQ ≅ ∠WQD — Corresponding angles postulate; 3. m∠USQ = m∠WQD — Definition of congruent angles; 4. ? — Linear pair postulate; 5. m∠SQW + m∠WQD = 180 — Definition of supplementary angles; 6. m∠SQW + m∠USQ = 180 — Substitution property; 7. ∠USQ and ∠SQW are supplementary — Definition of supplementary angles. Sketch, not to scale U S V W Q Y H D - ∠SQW and ∠WQD are complementary
- ∠SQW ≅ ∠WQD
- ∠USQ and ∠SQW are supplementary
- ∠SQW and ∠WQD are supplementary
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Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠VSQ and ∠SQY are supplementary. Ladder: 1. UV ∥ WY -- Given; 2. ∠VSQ ≅ ∠YQD -- Corresponding angles postulate; 3. m∠VSQ = m∠YQD -- Definition of congruent angles; 4. ? -- Linear pair postulate; 5. m∠SQY + m∠YQD = 180 -- Definition of supplementary angles; 6. m∠SQY + m∠VSQ = 180 -- Substitution property; 7. ∠VSQ and ∠SQY are supplementary -- Definition of supplementary angles.
Jun proves the same-side interior angles theorem a second way, on window bars UV and WY. Which statement fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠VSQ and ∠SQY are supplementary. Ladder: 1. UV ∥ WY — Given; 2. ∠VSQ ≅ ∠YQD — Corresponding angles postulate; 3. m∠VSQ = m∠YQD — Definition of congruent angles; 4. ? — Linear pair postulate; 5. m∠SQY + m∠YQD = 180 — Definition of supplementary angles; 6. m∠SQY + m∠VSQ = 180 — Substitution property; 7. ∠VSQ and ∠SQY are supplementary — Definition of supplementary angles. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠VSQ and ∠SQY are supplementary. Ladder: 1. UV ∥ WY — Given; 2. ∠VSQ ≅ ∠YQD — Corresponding angles postulate; 3. m∠VSQ = m∠YQD — Definition of congruent angles; 4. ? — Linear pair postulate; 5. m∠SQY + m∠YQD = 180 — Definition of supplementary angles; 6. m∠SQY + m∠VSQ = 180 — Substitution property; 7. ∠VSQ and ∠SQY are supplementary — Definition of supplementary angles. U V W Y H S Q D Not to scale. - ∠VSQ and ∠SQY are supplementary
- ∠SQY ≅ ∠YQD
- ∠SQY and ∠YQD are supplementary
- ∠SQY and ∠YQD are complementary
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Sketch, not to scale: rays QC, QD, QF and QG come out of point Q in that order, turning one way. Marked: right-angle boxes at ∠CQF and ∠DQG. Given: ∠CQF and ∠DQG are right angles. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQF and ∠DQG are right angles -- Given; 2. m∠CQF = 90 and m∠DQG = 90 -- Definition of right angle; 3. ? -- Angle addition postulate; 4. m∠DQF + m∠FQG = m∠DQG -- Angle addition postulate; 5. m∠CQD + m∠DQF = 90 and m∠DQF + m∠FQG = 90 -- Substitution property; 6. ∠CQD and ∠DQF are complementary, and so are ∠DQF and ∠FQG -- Definition of complementary angles; 7. ∠CQD ≅ ∠FQG -- Congruent complements theorem.
Milo folds a paper fan whose folds are rays QC, QD, QF and QG. Which statement fills the blank?
Sketch, not to scale: rays QC, QD, QF and QG come out of point Q in that order, turning one way. Marked: right-angle boxes at ∠CQF and ∠DQG. Given: ∠CQF and ∠DQG are right angles. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQF and ∠DQG are right angles — Given; 2. m∠CQF = 90 and m∠DQG = 90 — Definition of right angle; 3. ? — Angle addition postulate; 4. m∠DQF + m∠FQG = m∠DQG — Angle addition postulate; 5. m∠CQD + m∠DQF = 90 and m∠DQF + m∠FQG = 90 — Substitution property; 6. ∠CQD and ∠DQF are complementary, and so are ∠DQF and ∠FQG — Definition of complementary angles; 7. ∠CQD ≅ ∠FQG — Congruent complements theorem. Sketch, not to scale: rays QC, QD, QF and QG come out of point Q in that order, turning one way. Marked: right-angle boxes at ∠CQF and ∠DQG. Given: ∠CQF and ∠DQG are right angles. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQF and ∠DQG are right angles — Given; 2. m∠CQF = 90 and m∠DQG = 90 — Definition of right angle; 3. ? — Angle addition postulate; 4. m∠DQF + m∠FQG = m∠DQG — Angle addition postulate; 5. m∠CQD + m∠DQF = 90 and m∠DQF + m∠FQG = 90 — Substitution property; 6. ∠CQD and ∠DQF are complementary, and so are ∠DQF and ∠FQG — Definition of complementary angles; 7. ∠CQD ≅ ∠FQG — Congruent complements theorem. Q C D F G Not to scale. - m∠CQD + m∠DQF = m∠CQF
- m∠CQD + m∠DQF = 180
- ∠CQD ≅ ∠FQG
- m∠CQD + m∠FQG = m∠CQG
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Given: ∠UQW and ∠VQY are right angles. Prove: ∠UQV ≅ ∠WQY. Ladder: 1. ∠UQW and ∠VQY are right angles -- Given; 2. m∠UQW = 90 and m∠VQY = 90 -- Definition of right angle; 3. m∠UQV + m∠VQW = m∠UQW -- Angle addition postulate; 4. ? -- Angle addition postulate; 5. m∠UQV + m∠VQW = 90 and m∠VQW + m∠WQY = 90 -- Substitution property; 6. ∠UQV and ∠VQW are complementary, and so are ∠VQW and ∠WQY -- Definition of complementary angles; 7. ∠UQV ≅ ∠WQY -- Congruent complements theorem.
Noah draws four sun rays QU, QV, QW and QY from one center Q. Which statement fills the blank?
Sketch, not to scale: rays QU, QV, QW and QY come out of point Q in that order, turning one way. Marked: right-angle boxes at ∠UQW and ∠VQY. Given: ∠UQW and ∠VQY are right angles. Prove: ∠UQV ≅ ∠WQY. Ladder: 1. ∠UQW and ∠VQY are right angles — Given; 2. m∠UQW = 90 and m∠VQY = 90 — Definition of right angle; 3. m∠UQV + m∠VQW = m∠UQW — Angle addition postulate; 4. ? — Angle addition postulate; 5. m∠UQV + m∠VQW = 90 and m∠VQW + m∠WQY = 90 — Substitution property; 6. ∠UQV and ∠VQW are complementary, and so are ∠VQW and ∠WQY — Definition of complementary angles; 7. ∠UQV ≅ ∠WQY — Congruent complements theorem. Sketch, not to scale: rays QU, QV, QW and QY come out of point Q in that order, turning one way. Marked: right-angle boxes at ∠UQW and ∠VQY. Given: ∠UQW and ∠VQY are right angles. Prove: ∠UQV ≅ ∠WQY. Ladder: 1. ∠UQW and ∠VQY are right angles — Given; 2. m∠UQW = 90 and m∠VQY = 90 — Definition of right angle; 3. m∠UQV + m∠VQW = m∠UQW — Angle addition postulate; 4. ? — Angle addition postulate; 5. m∠UQV + m∠VQW = 90 and m∠VQW + m∠WQY = 90 — Substitution property; 6. ∠UQV and ∠VQW are complementary, and so are ∠VQW and ∠WQY — Definition of complementary angles; 7. ∠UQV ≅ ∠WQY — Congruent complements theorem. ∠UQW ∠VQY Q U V W Y Not to scale. - m∠UQV + m∠WQY = m∠UQY
- ∠UQV ≅ ∠WQY
- m∠VQW + m∠WQY = m∠VQY
- m∠VQW + m∠WQY = 180
Tala proves the converse of the alternate exterior angles theorem on quilt stripes UV and WY. Which statement and reason fill the blanks?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠HSU and ∠YQD with one arc each. Given: ∠HSU ≅ ∠YQD. Prove: UV ∥ WY. Ladder: 1. ∠HSU ≅ ∠YQD — Given; 2. ∠VSQ ≅ ∠HSU — Vertical angles theorem; 3. ? — ?; 4. UV ∥ WY — Converse of the corresponding angles postulate. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠HSU and ∠YQD with one arc each. Given: ∠HSU ≅ ∠YQD. Prove: UV ∥ WY. Ladder: 1. ∠HSU ≅ ∠YQD — Given; 2. ∠VSQ ≅ ∠HSU — Vertical angles theorem; 3. ? — ?; 4. UV ∥ WY — Converse of the corresponding angles postulate. U S V W Q Y H D Given: ∠HSU ≅ ∠YQD Prove: UV ∥ WY Not to scale. statement reason 1. ∠HSU ≅ ∠YQD Given 2. ∠VSQ ≅ ∠HSU Vertical angles theorem 3. ? ? 4. UV ∥ WY Converse of the corresponding angles postulate - ∠HSU ≅ ∠VSQ — Reflexive property
- ∠VSQ ≅ ∠YQD — Corresponding angles postulate
- ∠VSQ ≅ ∠YQD — Symmetric property
- ∠VSQ ≅ ∠YQD — Transitive property
Use this
Given: ∠HSV ≅ ∠WQD. Prove: UV ∥ WY. Ladder: 1. ∠HSV ≅ ∠WQD -- Given; 2. ∠USQ ≅ ∠HSV -- Vertical angles theorem; 3. ? -- ?; 4. UV ∥ WY -- Converse of the corresponding angles postulate.
Zee proves the converse of the alternate exterior angles theorem on train rails UV and WY. Which statement and reason fill the blanks?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠HSV and ∠WQD with one arc each. Given: ∠HSV ≅ ∠WQD. Prove: UV ∥ WY. Ladder: 1. ∠HSV ≅ ∠WQD — Given; 2. ∠USQ ≅ ∠HSV — Vertical angles theorem; 3. ? — ?; 4. UV ∥ WY — Converse of the corresponding angles postulate. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠HSV and ∠WQD with one arc each. Given: ∠HSV ≅ ∠WQD. Prove: UV ∥ WY. Ladder: 1. ∠HSV ≅ ∠WQD — Given; 2. ∠USQ ≅ ∠HSV — Vertical angles theorem; 3. ? — ?; 4. UV ∥ WY — Converse of the corresponding angles postulate. U V W Y H D S Q Not to scale. - ∠USQ ≅ ∠WQD — Symmetric property
- ∠USQ ≅ ∠WQD — Corresponding angles postulate
- ∠HSV ≅ ∠USQ — Reflexive property
- ∠USQ ≅ ∠WQD — Transitive property
Use this
Given: ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF -- Given; 2. m∠CQD + m∠DQF = 90 -- Definition of complementary angles; 3. m∠FQG + m∠DQF = 90 -- Definition of complementary angles; 4. m∠CQD + m∠DQF = m∠FQG + m∠DQF -- Substitution property; 5. ? -- ?; 6. ∠CQD ≅ ∠FQG -- Definition of congruent angles.
Pia proves the congruent complements theorem on a paper fan with folds QC, QD, QF and QG. Which statement and reason fill the blanks?
Sketch, not to scale: rays QC, QD, QF and QG come out of point Q in that order, turning one way. Marked: ∠CQD and ∠DQF labeled complementary; ∠FQG and ∠DQF labeled complementary. Given: ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF — Given; 2. m∠CQD + m∠DQF = 90 — Definition of complementary angles; 3. m∠FQG + m∠DQF = 90 — Definition of complementary angles; 4. m∠CQD + m∠DQF = m∠FQG + m∠DQF — Substitution property; 5. ? — ?; 6. ∠CQD ≅ ∠FQG — Definition of congruent angles. Sketch, not to scale: rays QC, QD, QF and QG come out of point Q in that order, turning one way. Marked: ∠CQD and ∠DQF labeled complementary; ∠FQG and ∠DQF labeled complementary. Given: ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF. Prove: ∠CQD ≅ ∠FQG. Ladder: 1. ∠CQD and ∠DQF are complementary, and so are ∠FQG and ∠DQF — Given; 2. m∠CQD + m∠DQF = 90 — Definition of complementary angles; 3. m∠FQG + m∠DQF = 90 — Definition of complementary angles; 4. m∠CQD + m∠DQF = m∠FQG + m∠DQF — Substitution property; 5. ? — ?; 6. ∠CQD ≅ ∠FQG — Definition of congruent angles. ∠CQD and ∠DQF complementary; ∠FQG and ∠DQF complementary Q C D F G Not to scale. - m∠CQD = m∠FQG — Subtraction property of equality
- m∠CQD = m∠DQF — Subtraction property of equality
- m∠CQD = m∠FQG — Addition property of equality
- ∠CQD ≅ ∠FQG — Congruent complements theorem
Use this
Given: ∠UQV and ∠VQW are complementary, and so are ∠WQY and ∠VQW. Prove: ∠UQV ≅ ∠WQY. Ladder: 1. ∠UQV and ∠VQW are complementary, and so are ∠WQY and ∠VQW -- Given; 2. m∠UQV + m∠VQW = 90 -- Definition of complementary angles; 3. m∠WQY + m∠VQW = 90 -- Definition of complementary angles; 4. m∠UQV + m∠VQW = m∠WQY + m∠VQW -- Substitution property; 5. ? -- ?; 6. ∠UQV ≅ ∠WQY -- Definition of congruent angles.
Ren proves the congruent complements theorem on sun rays QU, QV, QW and QY. Which statement and reason fill the blanks?
Sketch, not to scale: rays QU, QV, QW and QY come out of point Q in that order, turning one way. Marked: ∠UQV and ∠VQW labeled complementary; ∠WQY and ∠VQW labeled complementary. Given: ∠UQV and ∠VQW are complementary, and so are ∠WQY and ∠VQW. Prove: ∠UQV ≅ ∠WQY. Ladder: 1. ∠UQV and ∠VQW are complementary, and so are ∠WQY and ∠VQW — Given; 2. m∠UQV + m∠VQW = 90 — Definition of complementary angles; 3. m∠WQY + m∠VQW = 90 — Definition of complementary angles; 4. m∠UQV + m∠VQW = m∠WQY + m∠VQW — Substitution property; 5. ? — ?; 6. ∠UQV ≅ ∠WQY — Definition of congruent angles. Sketch, not to scale: rays QU, QV, QW and QY come out of point Q in that order, turning one way. Marked: ∠UQV and ∠VQW labeled complementary; ∠WQY and ∠VQW labeled complementary. Given: ∠UQV and ∠VQW are complementary, and so are ∠WQY and ∠VQW. Prove: ∠UQV ≅ ∠WQY. Ladder: 1. ∠UQV and ∠VQW are complementary, and so are ∠WQY and ∠VQW — Given; 2. m∠UQV + m∠VQW = 90 — Definition of complementary angles; 3. m∠WQY + m∠VQW = 90 — Definition of complementary angles; 4. m∠UQV + m∠VQW = m∠WQY + m∠VQW — Substitution property; 5. ? — ?; 6. ∠UQV ≅ ∠WQY — Definition of congruent angles. ∠UQV and ∠VQW complementary; ∠WQY and ∠VQW complementary Q U V W Y Not to scale. - m∠UQV = m∠WQY — Addition property of equality
- m∠UQV = m∠VQW — Subtraction property of equality
- m∠UQV = m∠WQY — Subtraction property of equality
- ∠UQV ≅ ∠WQY — Congruent complements theorem