Angle and parallel-line proofs: fill in the missing reason
Grade 10 Math Worksheet

Circle the best answer.
Read this first
Use this
Ladder: 1. Lines CG and DH cross at Q -- Given; 2. ∠CQH and ∠HQG are supplementary -- Linear pair postulate; 3. ∠GQD and ∠HQG are supplementary -- Linear pair postulate; 4. ∠CQH ≅ ∠GQD -- ?.
Ari proves the vertical angles theorem on open scissors, blades along CG and DH. Which reason fills the blank?
- Vertical angles theorem
- Linear pair postulate
- Congruent supplements theorem
- Congruent complements theorem
Use this
Given: lines CG and DH cross at Q. Prove: ∠HQG ≅ ∠DQC. Ladder: 1. Lines CG and DH cross at Q -- Given; 2. ∠HQG and ∠GQD are supplementary -- Linear pair postulate; 3. ∠DQC and ∠GQD are supplementary -- Linear pair postulate; 4. ∠HQG ≅ ∠DQC -- ?.
Bo proves the vertical angles theorem on a kite, sticks along CG and DH. Which reason fills the blank?
Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: none beyond the lines. Given: lines CG and DH cross at Q. Prove: ∠HQG ≅ ∠DQC. Ladder: 1. Lines CG and DH cross at Q — Given; 2. ∠HQG and ∠GQD are supplementary — Linear pair postulate; 3. ∠DQC and ∠GQD are supplementary — Linear pair postulate; 4. ∠HQG ≅ ∠DQC — ?. Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: none beyond the lines. Given: lines CG and DH cross at Q. Prove: ∠HQG ≅ ∠DQC. Ladder: 1. Lines CG and DH cross at Q — Given; 2. ∠HQG and ∠GQD are supplementary — Linear pair postulate; 3. ∠DQC and ∠GQD are supplementary — Linear pair postulate; 4. ∠HQG ≅ ∠DQC — ?. Sketch, not to scale C H G D Q - Angle addition postulate
- Congruent supplements theorem
- Vertical angles theorem
- Congruent complements theorem
Kira proves the alternate exterior angles theorem on train rails UV and WY, crossed by road HD. Which reason fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠HSU ≅ ∠YQD. Ladder: 1. UV ∥ WY — Given; 2. ∠HSU ≅ ∠SQW — ?; 3. ∠SQW ≅ ∠YQD — Vertical angles theorem; 4. ∠HSU ≅ ∠YQD — Transitive property. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠HSU ≅ ∠YQD. Ladder: 1. UV ∥ WY — Given; 2. ∠HSU ≅ ∠SQW — ?; 3. ∠SQW ≅ ∠YQD — Vertical angles theorem; 4. ∠HSU ≅ ∠YQD — Transitive property. U S V W Q Y H D Given: UV ∥ WY. 1. UV ∥ WY -- Given; 2. ∠HSU ≅ ∠SQW -- ?; 3. ∠SQW ≅ ∠YQD -- Vertical angles theorem; 4. ∠HSU ≅ ∠YQD -- Transitive property. Not to scale. - Alternate interior angles theorem
- Corresponding angles postulate
- Given
- Converse of the corresponding angles postulate
Use this
Given: UV ∥ WY. Prove: ∠HSV ≅ ∠WQD. Ladder: 1. UV ∥ WY -- Given; 2. ∠HSV ≅ ∠SQY -- ?; 3. ∠SQY ≅ ∠WQD -- Vertical angles theorem; 4. ∠HSV ≅ ∠WQD -- Transitive property.
Luz proves the alternate exterior angles theorem on map streets UV and WY, crossed by avenue HD. Which reason fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠HSV ≅ ∠WQD. Ladder: 1. UV ∥ WY — Given; 2. ∠HSV ≅ ∠SQY — ?; 3. ∠SQY ≅ ∠WQD — Vertical angles theorem; 4. ∠HSV ≅ ∠WQD — Transitive property. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠HSV ≅ ∠WQD. Ladder: 1. UV ∥ WY — Given; 2. ∠HSV ≅ ∠SQY — ?; 3. ∠SQY ≅ ∠WQD — Vertical angles theorem; 4. ∠HSV ≅ ∠WQD — Transitive property. Sketch, not to scale U V W Y H S Q D - Converse of the corresponding angles postulate
- Same-side interior angles theorem
- Vertical angles theorem
- Corresponding angles postulate
Use this
Given: m∠CQH = 115. Prove: m∠HQG = 65. Ladder: 1. m∠CQH = 115 -- Given; 2. ∠CQH and ∠HQG are supplementary -- Linear pair postulate; 3. m∠CQH + m∠HQG = 180 -- Definition of supplementary angles; 4. 115 + m∠HQG = 180 -- Substitution property; 5. m∠HQG = 65 -- ?.
Pia opens scissors so one angle at the pivot Q measures 115°. Which reason fills the blank?
Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: ∠CQH labeled 115°. Given: m∠CQH = 115. Prove: m∠HQG = 65. Ladder: 1. m∠CQH = 115 — Given; 2. ∠CQH and ∠HQG are supplementary — Linear pair postulate; 3. m∠CQH + m∠HQG = 180 — Definition of supplementary angles; 4. 115 + m∠HQG = 180 — Substitution property; 5. m∠HQG = 65 — ?. Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: ∠CQH labeled 115°. Given: m∠CQH = 115. Prove: m∠HQG = 65. Ladder: 1. m∠CQH = 115 — Given; 2. ∠CQH and ∠HQG are supplementary — Linear pair postulate; 3. m∠CQH + m∠HQG = 180 — Definition of supplementary angles; 4. 115 + m∠HQG = 180 — Substitution property; 5. m∠HQG = 65 — ?. Sketch, not to scale 115° Q C H G D - Addition property of equality
- Given
- Substitution property
- Subtraction property of equality
Use this
Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: ∠GQD labeled 128°. Given: m∠GQD = 128. Prove: m∠DQC = 52. Ladder: 1. m∠GQD = 128 -- Given; 2. ∠GQD and ∠DQC are supplementary -- Linear pair postulate; 3. m∠GQD + m∠DQC = 180 -- Definition of supplementary angles; 4. 128 + m∠DQC = 180 -- Substitution property; 5. m∠DQC = 52 -- ?.
Ren sets kite sticks CG and DH so one angle at Q measures 128°. Which reason fills the blank?
Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: ∠GQD labeled 128°. Given: m∠GQD = 128. Prove: m∠DQC = 52. Ladder: 1. m∠GQD = 128 — Given; 2. ∠GQD and ∠DQC are supplementary — Linear pair postulate; 3. m∠GQD + m∠DQC = 180 — Definition of supplementary angles; 4. 128 + m∠DQC = 180 — Substitution property; 5. m∠DQC = 52 — ?. Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: ∠GQD labeled 128°. Given: m∠GQD = 128. Prove: m∠DQC = 52. Ladder: 1. m∠GQD = 128 — Given; 2. ∠GQD and ∠DQC are supplementary — Linear pair postulate; 3. m∠GQD + m∠DQC = 180 — Definition of supplementary angles; 4. 128 + m∠DQC = 180 — Substitution property; 5. m∠DQC = 52 — ?. CG DH 128° C G D H Q Not to scale. - Subtraction property of equality
- Addition property of equality
- Given
- Definition of supplementary angles
Use this
Given: lines CG and DH cross at Q. Prove: ∠CQH ≅ ∠GQD. Ladder: 1. Lines CG and DH cross at Q -- Given; 2. ∠CQH and ∠DQC are supplementary -- Linear pair postulate; 3. ? -- Linear pair postulate; 4. ∠CQH ≅ ∠GQD -- Congruent supplements theorem.
Esme proves the vertical angles theorem with two crossed pencils along CG and DH. Which statement fills the blank?
Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: none beyond the lines. Given: lines CG and DH cross at Q. Prove: ∠CQH ≅ ∠GQD. Ladder: 1. Lines CG and DH cross at Q — Given; 2. ∠CQH and ∠DQC are supplementary — Linear pair postulate; 3. ? — Linear pair postulate; 4. ∠CQH ≅ ∠GQD — Congruent supplements theorem. Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: none beyond the lines. Given: lines CG and DH cross at Q. Prove: ∠CQH ≅ ∠GQD. Ladder: 1. Lines CG and DH cross at Q — Given; 2. ∠CQH and ∠DQC are supplementary — Linear pair postulate; 3. ? — Linear pair postulate; 4. ∠CQH ≅ ∠GQD — Congruent supplements theorem. C H G D Q Not to scale. - ∠GQD ≅ ∠DQC
- ∠GQD and ∠DQC are complementary
- ∠GQD and ∠DQC are supplementary
- ∠CQH ≅ ∠GQD
Use this
Marked: none beyond the lines. Given: lines CG and DH cross at Q. Prove: ∠HQG ≅ ∠DQC. Ladder: 1. Lines CG and DH cross at Q -- Given; 2. ∠HQG and ∠CQH are supplementary -- Linear pair postulate; 3. ? -- Linear pair postulate; 4. ∠HQG ≅ ∠DQC -- Congruent supplements theorem.
Jun proves the vertical angles theorem with scissors opened wide. Which statement fills the blank?
Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: none beyond the lines. Given: lines CG and DH cross at Q. Prove: ∠HQG ≅ ∠DQC. Ladder: 1. Lines CG and DH cross at Q — Given; 2. ∠HQG and ∠CQH are supplementary — Linear pair postulate; 3. ? — Linear pair postulate; 4. ∠HQG ≅ ∠DQC — Congruent supplements theorem. Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: none beyond the lines. Given: lines CG and DH cross at Q. Prove: ∠HQG ≅ ∠DQC. Ladder: 1. Lines CG and DH cross at Q — Given; 2. ∠HQG and ∠CQH are supplementary — Linear pair postulate; 3. ? — Linear pair postulate; 4. ∠HQG ≅ ∠DQC — Congruent supplements theorem. C H G D Q Not to scale. - ∠HQG ≅ ∠DQC
- ∠DQC and ∠CQH are complementary
- ∠DQC ≅ ∠CQH
- ∠DQC and ∠CQH are supplementary
Use this
Given: UV ∥ WY. Prove: ∠VSQ ≅ ∠SQW. Ladder: 1. UV ∥ WY -- Given; 2. ∠VSQ ≅ ∠YQD -- Corresponding angles postulate; 3. ? -- Vertical angles theorem; 4. ∠VSQ ≅ ∠SQW -- Transitive property.
Noah proves the alternate interior angles theorem on window bars UV and WY, crossed by brace HD. Which statement fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠VSQ ≅ ∠SQW. Ladder: 1. UV ∥ WY — Given; 2. ∠VSQ ≅ ∠YQD — Corresponding angles postulate; 3. ? — Vertical angles theorem; 4. ∠VSQ ≅ ∠SQW — Transitive property. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY. Given: UV ∥ WY. Prove: ∠VSQ ≅ ∠SQW. Ladder: 1. UV ∥ WY — Given; 2. ∠VSQ ≅ ∠YQD — Corresponding angles postulate; 3. ? — Vertical angles theorem; 4. ∠VSQ ≅ ∠SQW — Transitive property. ∠VSQ ∠YQD ∠SQW U V W Y H D S Q Not to scale. - ∠YQD ≅ ∠SQW
- ∠VSQ ≅ ∠SQY
- ∠VSQ ≅ ∠SQW
- ∠YQD ≅ ∠SQY
Use this
Given: UV ∥ WY and m∠HSV = 62. Prove: m∠SQY = 62. Ladder: 1. UV ∥ WY -- Given; 2. m∠HSV = 62 -- Given; 3. ? -- Corresponding angles postulate; 4. m∠SQY = m∠HSV -- Definition of congruent angles; 5. m∠SQY = 62 -- Substitution property.
Tala measures 62° where road HD meets train rail UV. Which statement fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY; ∠HSV labeled 62°. Given: UV ∥ WY and m∠HSV = 62. Prove: m∠SQY = 62. Ladder: 1. UV ∥ WY — Given; 2. m∠HSV = 62 — Given; 3. ? — Corresponding angles postulate; 4. m∠SQY = m∠HSV — Definition of congruent angles; 5. m∠SQY = 62 — Substitution property. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY; ∠HSV labeled 62°. Given: UV ∥ WY and m∠HSV = 62. Prove: m∠SQY = 62. Ladder: 1. UV ∥ WY — Given; 2. m∠HSV = 62 — Given; 3. ? — Corresponding angles postulate; 4. m∠SQY = m∠HSV — Definition of congruent angles; 5. m∠SQY = 62 — Substitution property. 62° U V W Y H S Q D Not to scale. - UV ∥ WY
- m∠SQY = 62
- ∠HSV ≅ ∠YQD
- ∠HSV ≅ ∠SQY