Angle and parallel-line proofs: fill in the missing reason
Grade 10 Math Worksheet - Building Confidence

Circle the best answer.
Read this first
Use this
Given: lines CG and DH cross at Q. Prove: ∠CQH ≅ ∠GQD. Ladder: 1. Lines CG and DH cross at Q -- Given; 2. ∠CQH ≅ ∠GQD -- ?.
Ari opens a pair of scissors, and the blades lie along lines CG and DH. Which reason fills the blank?
- Linear pair postulate
- Vertical angles theorem
- Angle addition postulate
- Given
Bo builds a kite whose two sticks lie along lines CG and DH. Which reason fills the blank?
Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: ∠HQG and ∠GQD shaded. Given: lines CG and DH cross at Q. Prove: ∠HQG and ∠GQD are supplementary. Ladder: 1. Lines CG and DH cross at Q — Given; 2. ∠HQG and ∠GQD are supplementary — ?. Sketch, not to scale: lines CG and DH cross at Q (C upper left, H upper right, G lower right, D lower left). Marked: ∠HQG and ∠GQD shaded. Given: lines CG and DH cross at Q. Prove: ∠HQG and ∠GQD are supplementary. Ladder: 1. Lines CG and DH cross at Q — Given; 2. ∠HQG and ∠GQD are supplementary — ?. C H G D Q Ladder: 1. Lines CG and DH cross at Q -- Given; 2. ∠HQG and ∠GQD are supplementary -- ?. Not to scale. - Given
- Linear pair postulate
- Vertical angles theorem
- Definition of complementary angles
Jun sees two stripes UV and WY on a rug, crossed by a seam HD. Which reason fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY; ∠USQ and ∠WQD shaded. Given: UV ∥ WY. Prove: ∠USQ ≅ ∠WQD. Ladder: 1. UV ∥ WY — Given; 2. ∠USQ ≅ ∠WQD — ?. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: parallel arrows on UV and WY; ∠USQ and ∠WQD shaded. Given: UV ∥ WY. Prove: ∠USQ ≅ ∠WQD. Ladder: 1. UV ∥ WY — Given; 2. ∠USQ ≅ ∠WQD — ?. U S V W Q Y H D Given: UV ∥ WY. Prove: ∠USQ ≅ ∠WQD. Ladder: 1. UV ∥ WY -- Given; 2. ∠USQ ≅ ∠WQD -- ?. Not to scale. - Converse of the corresponding angles postulate
- Given
- Corresponding angles postulate
- Alternate exterior angles theorem
Sketch, not to scale
Line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠HSU and ∠SQW with one arc each (no parallel arrows). Given: ∠HSU ≅ ∠SQW. Prove: ∠VSQ ≅ ∠SQW. Ladder: 1. ∠HSU ≅ ∠SQW — Given; 2. ∠VSQ ≅ ∠HSU — Vertical angles theorem; 3. ∠VSQ ≅ ∠SQW — ?.
Kira sketches window bars UV and WY, crossed by a brace HD. Which reason fills the blank?
- Given
- Symmetric property
- Alternate interior angles theorem
- Transitive property
Sketch, not to scale
Line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠USQ and ∠WQD with one arc each (no parallel arrows). Given: ∠USQ ≅ ∠WQD. Prove: ∠HSV ≅ ∠WQD. Ladder: 1. ∠USQ ≅ ∠WQD — Given; 2. ∠HSV ≅ ∠USQ — Vertical angles theorem; 3. ∠HSV ≅ ∠WQD — ?.
Luz traces streets UV and WY on a map, crossed by avenue HD. Which reason fills the blank?
- Given
- Alternate exterior angles theorem
- Reflexive property
- Transitive property
Use this
Given: ∠SQY ≅ ∠USQ. Prove: UV ∥ WY. Ladder: 1. ∠SQY ≅ ∠USQ -- Given; 2. ∠WQD ≅ ∠SQY -- Vertical angles theorem; 3. ∠WQD ≅ ∠USQ -- Transitive property; 4. UV ∥ WY -- ?.
Ren rules lines UV and WY on paper, then crosses them with line HD. Which reason fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠SQY and ∠USQ with one arc each. Given: ∠SQY ≅ ∠USQ. Prove: UV ∥ WY. Ladder: 1. ∠SQY ≅ ∠USQ — Given; 2. ∠WQD ≅ ∠SQY — Vertical angles theorem; 3. ∠WQD ≅ ∠USQ — Transitive property; 4. UV ∥ WY — ?. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠SQY and ∠USQ with one arc each. Given: ∠SQY ≅ ∠USQ. Prove: UV ∥ WY. Ladder: 1. ∠SQY ≅ ∠USQ — Given; 2. ∠WQD ≅ ∠SQY — Vertical angles theorem; 3. ∠WQD ≅ ∠USQ — Transitive property; 4. UV ∥ WY — ?. ∠SQY ∠USQ U V W Y H S Q D Not to scale. - Converse of the corresponding angles postulate
- Given
- Converse of the same-side interior angles theorem
- Corresponding angles postulate
Use this
Given: ∠SQY ≅ ∠HSV. Prove: ∠WQD ≅ ∠HSV. Ladder: 1. ∠SQY ≅ ∠HSV -- Given; 2. ? -- Vertical angles theorem; 3. ∠WQD ≅ ∠HSV -- Transitive property.
Milo draws a door's edges UV and WY, crossed by a ribbon HD. Which statement fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠SQY and ∠HSV with one arc each (no parallel arrows). Given: ∠SQY ≅ ∠HSV. Prove: ∠WQD ≅ ∠HSV. Ladder: 1. ∠SQY ≅ ∠HSV — Given; 2. ? — Vertical angles theorem; 3. ∠WQD ≅ ∠HSV — Transitive property. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠SQY and ∠HSV with one arc each (no parallel arrows). Given: ∠SQY ≅ ∠HSV. Prove: ∠WQD ≅ ∠HSV. Ladder: 1. ∠SQY ≅ ∠HSV — Given; 2. ? — Vertical angles theorem; 3. ∠WQD ≅ ∠HSV — Transitive property. U V W Y H D S Q Not to scale. - ∠HSV ≅ ∠SQY
- ∠WQD ≅ ∠SQY
- ∠WQD ≅ ∠HSV
- ∠WQD ≅ ∠YQD
Use this
Given: ∠YQD ≅ ∠VSQ. Prove: ∠SQW ≅ ∠VSQ. Ladder: 1. ∠YQD ≅ ∠VSQ -- Given; 2. ? -- Vertical angles theorem; 3. ∠SQW ≅ ∠VSQ -- Transitive property.
Noah draws a bike rack with bars UV and WY, crossed by a pole HD. Which statement fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠YQD and ∠VSQ with one arc each (no parallel arrows). Given: ∠YQD ≅ ∠VSQ. Prove: ∠SQW ≅ ∠VSQ. Ladder: 1. ∠YQD ≅ ∠VSQ — Given; 2. ? — Vertical angles theorem; 3. ∠SQW ≅ ∠VSQ — Transitive property. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠YQD and ∠VSQ with one arc each (no parallel arrows). Given: ∠YQD ≅ ∠VSQ. Prove: ∠SQW ≅ ∠VSQ. Ladder: 1. ∠YQD ≅ ∠VSQ — Given; 2. ? — Vertical angles theorem; 3. ∠SQW ≅ ∠VSQ — Transitive property. U V W Y H D S Q Not to scale. - ∠SQW ≅ ∠SQY
- ∠SQW ≅ ∠VSQ
- ∠VSQ ≅ ∠YQD
- ∠SQW ≅ ∠YQD
Tala draws tent poles UV and WY, joined by a cord HD. Which statement fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠HSV and ∠WQD with one arc each. Given: ∠HSV ≅ ∠WQD. Prove: UV ∥ WY. Ladder: 1. ∠HSV ≅ ∠WQD — Given; 2. ∠USQ ≅ ∠HSV — Vertical angles theorem; 3. ? — Transitive property; 4. UV ∥ WY — Converse of the corresponding angles postulate. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠HSV and ∠WQD with one arc each. Given: ∠HSV ≅ ∠WQD. Prove: UV ∥ WY. Ladder: 1. ∠HSV ≅ ∠WQD — Given; 2. ∠USQ ≅ ∠HSV — Vertical angles theorem; 3. ? — Transitive property; 4. UV ∥ WY — Converse of the corresponding angles postulate. Prove: UV ∥ WY ∠HSV ∠WQD U S V W Q Y H D Given: ∠HSV ≅ ∠WQD. 1. ∠HSV ≅ ∠WQD -- Given 2. ∠USQ ≅ ∠HSV -- Vertical angles theorem 3. ? -- Transitive property 4. UV ∥ WY -- Converse of the corresponding angles postulate. Not to scale. - UV ∥ WY
- ∠USQ ≅ ∠WQD
- ∠USQ ≅ ∠SQY
- ∠WQD ≅ ∠HSV
Use this
Given: ∠YQD ≅ ∠HSU. Prove: UV ∥ WY. Ladder: 1. ∠YQD ≅ ∠HSU -- Given; 2. ∠SQW ≅ ∠YQD -- Vertical angles theorem; 3. ? -- Transitive property; 4. UV ∥ WY -- Converse of the corresponding angles postulate.
Zee sews quilt stripes UV and WY, crossed by a stitch line HD. Which statement fills the blank?
Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠YQD and ∠HSU with one arc each. Given: ∠YQD ≅ ∠HSU. Prove: UV ∥ WY. Ladder: 1. ∠YQD ≅ ∠HSU — Given; 2. ∠SQW ≅ ∠YQD — Vertical angles theorem; 3. ? — Transitive property; 4. UV ∥ WY — Converse of the corresponding angles postulate. Sketch, not to scale: line UV above line WY (U and W on the left), crossed by line HD at S on UV and at Q on WY (H at the top, D at the bottom). Marked: ∠YQD and ∠HSU with one arc each. Given: ∠YQD ≅ ∠HSU. Prove: UV ∥ WY. Ladder: 1. ∠YQD ≅ ∠HSU — Given; 2. ∠SQW ≅ ∠YQD — Vertical angles theorem; 3. ? — Transitive property; 4. UV ∥ WY — Converse of the corresponding angles postulate. U V W Y H D S Q Not to scale. - UV ∥ WY
- ∠SQW ≅ ∠SQY
- ∠HSU ≅ ∠YQD
- ∠SQW ≅ ∠HSU