Congruence proofs: fill in the missing step or reason
Grade 10 Math Worksheet

Circle the best answer.
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Given: C is the midpoint of SV and of UW. Prove: SW ≅ VU. Ladder: 1. C is the midpoint of SV -- Given; 2. SC ≅ VC -- Definition of midpoint; 3. C is the midpoint of UW -- Given; 4. WC ≅ UC -- Definition of midpoint; 5. ∠SCW ≅ ∠VCU -- Vertical angles theorem; 6. triangle SCW ≅ triangle VCU -- SAS; 7. SW ≅ VU -- ?.
Tala crosses two craft sticks SV and UW at their middles, C. Which reason fills the blank?
- Given
- CPCTC
- Vertical angles theorem
- SAS
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Sketch, not to scale: segments DG and FH cross at Q (D upper left, G lower right, H upper right, F lower left). Marked: arrows on DH and FG; DQ and QG with one tick each. Given: DH ∥ FG, and Q is the midpoint of DG. Prove: HQ ≅ FQ. Ladder: 1. DH ∥ FG -- Given; 2. ∠HDQ ≅ ∠FGQ -- Alternate interior angles theorem; 3. Q is the midpoint of DG -- Given; 4. DQ ≅ GQ -- Definition of midpoint; 5. ∠DQH ≅ ∠GQF -- Vertical angles theorem; 6. triangle DQH ≅ triangle GQF -- ?; 7. HQ ≅ FQ -- CPCTC.
Zee draws a bike frame where bars DG and FH cross at Q, and DH ∥ FG. Which reason fills the blank?
Sketch, not to scale: segments DG and FH cross at Q (D upper left, G lower right, H upper right, F lower left). Marked: arrows on DH and FG; DQ and QG with one tick each. Given: DH ∥ FG, and Q is the midpoint of DG. Prove: HQ ≅ FQ. Ladder: 1. DH ∥ FG — Given; 2. ∠HDQ ≅ ∠FGQ — Alternate interior angles theorem; 3. Q is the midpoint of DG — Given; 4. DQ ≅ GQ — Definition of midpoint; 5. ∠DQH ≅ ∠GQF — Vertical angles theorem; 6. △DQH ≅ △GQF — ?; 7. HQ ≅ FQ — CPCTC. Sketch, not to scale: segments DG and FH cross at Q (D upper left, G lower right, H upper right, F lower left). Marked: arrows on DH and FG; DQ and QG with one tick each. Given: DH ∥ FG, and Q is the midpoint of DG. Prove: HQ ≅ FQ. Ladder: 1. DH ∥ FG — Given; 2. ∠HDQ ≅ ∠FGQ — Alternate interior angles theorem; 3. Q is the midpoint of DG — Given; 4. DQ ≅ GQ — Definition of midpoint; 5. ∠DQH ≅ ∠GQF — Vertical angles theorem; 6. △DQH ≅ △GQF — ?; 7. HQ ≅ FQ — CPCTC. D G H F Q Not to scale. - SSS
- AAS
- SAS
- ASA
Use this
Ladder: 1. SW ∥ UV -- Given; 2. ∠WSC ≅ ∠UVC -- Alternate interior angles theorem; 3. SW ≅ VU -- Given; 4. ∠SCW ≅ ∠VCU -- Vertical angles theorem; 5. triangle SCW ≅ triangle VCU -- ?; 6. WC ≅ UC -- CPCTC.
Ari draws two ramps that cross, SV and UW, meeting at C, with SW ∥ UV. Which reason fills the blank?
Sketch, not to scale: segments SV and UW cross at C (S upper left, V lower right, W upper right, U lower left). Marked: arrows on SW and UV; SW and UV with one tick each. Given: SW ∥ UV and SW ≅ VU. Prove: WC ≅ UC. Ladder: 1. SW ∥ UV — Given; 2. ∠WSC ≅ ∠UVC — Alternate interior angles theorem; 3. SW ≅ VU — Given; 4. ∠SCW ≅ ∠VCU — Vertical angles theorem; 5. △SCW ≅ △VCU — ?; 6. WC ≅ UC — CPCTC. Sketch, not to scale: segments SV and UW cross at C (S upper left, V lower right, W upper right, U lower left). Marked: arrows on SW and UV; SW and UV with one tick each. Given: SW ∥ UV and SW ≅ VU. Prove: WC ≅ UC. Ladder: 1. SW ∥ UV — Given; 2. ∠WSC ≅ ∠UVC — Alternate interior angles theorem; 3. SW ≅ VU — Given; 4. ∠SCW ≅ ∠VCU — Vertical angles theorem; 5. △SCW ≅ △VCU — ?; 6. WC ≅ UC — CPCTC. S W V U C Not to scale. - AAS
- SAS
- HL
- ASA
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triangles CDF and CGF share side CF; D is above CF and G is below, with right angles at D and G. Marked: right-angle boxes at D and G; CD and CG with one tick each. Given: ∠CDF and ∠CGF are right angles, and CD ≅ CG. Prove: DF ≅ GF. Ladder: 1. ∠CDF and ∠CGF are right angles -- Given; 2. triangle CDF and triangle CGF are right triangles -- Definition of right triangle; 3. CD ≅ CG -- Given; 4. CF ≅ CF -- Reflexive property; 5. triangle CDF ≅ triangle CGF -- ?; 6. DF ≅ GF -- CPCTC.
Bo builds a kite from two right triangles, CDF and CGF, that share stick CF. Which reason fills the blank?
Sketch, not to scale: triangles CDF and CGF share side CF; D is above CF and G is below, with right angles at D and G. Marked: right-angle boxes at D and G; CD and CG with one tick each. Given: ∠CDF and ∠CGF are right angles, and CD ≅ CG. Prove: DF ≅ GF. Ladder: 1. ∠CDF and ∠CGF are right angles — Given; 2. △CDF and △CGF are right triangles — Definition of right triangle; 3. CD ≅ CG — Given; 4. CF ≅ CF — Reflexive property; 5. △CDF ≅ △CGF — ?; 6. DF ≅ GF — CPCTC. Sketch, not to scale: triangles CDF and CGF share side CF; D is above CF and G is below, with right angles at D and G. Marked: right-angle boxes at D and G; CD and CG with one tick each. Given: ∠CDF and ∠CGF are right angles, and CD ≅ CG. Prove: DF ≅ GF. Ladder: 1. ∠CDF and ∠CGF are right angles — Given; 2. △CDF and △CGF are right triangles — Definition of right triangle; 3. CD ≅ CG — Given; 4. CF ≅ CF — Reflexive property; 5. △CDF ≅ △CGF — ?; 6. DF ≅ GF — CPCTC. Sketch C D F G Not to scale. - HL
- SSA
- ASA
- SAS
Use this
Given: ∠SUW and ∠SYW are right angles, and SU ≅ SY. Prove: UW ≅ YW. Ladder: 1. ∠SUW and ∠SYW are right angles -- Given; 2. triangle SUW and triangle SYW are right triangles -- Definition of right triangle; 3. SU ≅ SY -- Given; 4. SW ≅ SW -- Reflexive property; 5. triangle SUW ≅ triangle SYW -- ?; 6. UW ≅ YW -- CPCTC.
Esme folds paper into two right triangles, SUW and SYW, that share fold SW. Which reason fills the blank?
Sketch, not to scale: triangles SUW and SYW share side SW; U is above SW and Y is below, with right angles at U and Y. Marked: right-angle boxes at U and Y; SU and SY with one tick each. Given: ∠SUW and ∠SYW are right angles, and SU ≅ SY. Prove: UW ≅ YW. Ladder: 1. ∠SUW and ∠SYW are right angles — Given; 2. △SUW and △SYW are right triangles — Definition of right triangle; 3. SU ≅ SY — Given; 4. SW ≅ SW — Reflexive property; 5. △SUW ≅ △SYW — ?; 6. UW ≅ YW — CPCTC. Sketch, not to scale: triangles SUW and SYW share side SW; U is above SW and Y is below, with right angles at U and Y. Marked: right-angle boxes at U and Y; SU and SY with one tick each. Given: ∠SUW and ∠SYW are right angles, and SU ≅ SY. Prove: UW ≅ YW. Ladder: 1. ∠SUW and ∠SYW are right angles — Given; 2. △SUW and △SYW are right triangles — Definition of right triangle; 3. SU ≅ SY — Given; 4. SW ≅ SW — Reflexive property; 5. △SUW ≅ △SYW — ?; 6. UW ≅ YW — CPCTC. S U W Y Not to scale. - HL
- SAS
- AAS
- SSA
Jun opens garden shears so the blades HU and YD cross at their middles, F. Which statement fills the blank?
Sketch, not to scale: segments HU and YD cross at F (H upper left, U lower right, D upper right, Y lower left). Marked: HF and FU with one tick each; DF and FY with two ticks each. Given: F is the midpoint of HU and of YD. Prove: HD ≅ UY. Ladder: 1. F is the midpoint of HU — Given; 2. HF ≅ UF — Definition of midpoint; 3. F is the midpoint of YD — Given; 4. DF ≅ YF — Definition of midpoint; 5. ∠HFD ≅ ∠UFY — Vertical angles theorem; 6. ? — SAS; 7. HD ≅ UY — CPCTC. Sketch, not to scale: segments HU and YD cross at F (H upper left, U lower right, D upper right, Y lower left). Marked: HF and FU with one tick each; DF and FY with two ticks each. Given: F is the midpoint of HU and of YD. Prove: HD ≅ UY. Ladder: 1. F is the midpoint of HU — Given; 2. HF ≅ UF — Definition of midpoint; 3. F is the midpoint of YD — Given; 4. DF ≅ YF — Definition of midpoint; 5. ∠HFD ≅ ∠UFY — Vertical angles theorem; 6. ? — SAS; 7. HD ≅ UY — CPCTC. H U D Y F Given: F is the midpoint of HU and of YD. Prove: HD ≅ UY. 1. F is the midpoint of HU -- Given; 2. HF ≅ UF -- Definition of midpoint; 3. F is the midpoint of YD -- Given; 4. DF ≅ YF -- Definition of midpoint; 5. ∠HFD ≅ ∠UFY -- Vertical angles theorem; 6. ? -- SAS; 7. HD ≅ UY -- CPCTC. Not to scale. - △HFD ≅ △YFU
- △HFD ≅ △UFY
- △HFD ≅ △HFY
- HD ≅ UY
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Given: HD ∥ YU, and F is the midpoint of HU. Prove: DF ≅ YF. Ladder: 1. HD ∥ YU -- Given; 2. ? -- Alternate interior angles theorem; 3. F is the midpoint of HU -- Given; 4. HF ≅ UF -- Definition of midpoint; 5. ∠HFD ≅ ∠UFY -- Vertical angles theorem; 6. triangle HFD ≅ triangle UFY -- ASA; 7. DF ≅ YF -- CPCTC.
Kira draws a bike rack where bars HU and YD cross at F, and HD ∥ YU. Which statement fills the blank?
Sketch, not to scale: segments HU and YD cross at F (H upper left, U lower right, D upper right, Y lower left). Marked: arrows on HD and YU; HF and FU with one tick each. Given: HD ∥ YU, and F is the midpoint of HU. Prove: DF ≅ YF. Ladder: 1. HD ∥ YU — Given; 2. ? — Alternate interior angles theorem; 3. F is the midpoint of HU — Given; 4. HF ≅ UF — Definition of midpoint; 5. ∠HFD ≅ ∠UFY — Vertical angles theorem; 6. △HFD ≅ △UFY — ASA; 7. DF ≅ YF — CPCTC. Sketch, not to scale: segments HU and YD cross at F (H upper left, U lower right, D upper right, Y lower left). Marked: arrows on HD and YU; HF and FU with one tick each. Given: HD ∥ YU, and F is the midpoint of HU. Prove: DF ≅ YF. Ladder: 1. HD ∥ YU — Given; 2. ? — Alternate interior angles theorem; 3. F is the midpoint of HU — Given; 4. HF ≅ UF — Definition of midpoint; 5. ∠HFD ≅ ∠UFY — Vertical angles theorem; 6. △HFD ≅ △UFY — ASA; 7. DF ≅ YF — CPCTC. H U Y D F Not to scale. - ∠DHF ≅ ∠HDF
- DF ≅ YF
- ∠DHF ≅ ∠UYF
- ∠DHF ≅ ∠YUF
Luz sews two right-triangle patches, QHV and QDV, that share seam QV. Which statement fills the blank?
Sketch, not to scale: triangles QHV and QDV share side QV; H is above QV and D is below, with right angles at H and D. Marked: right-angle boxes at H and D; QH and QD with one tick each. Given: ∠QHV and ∠QDV are right angles, and QH ≅ QD. Prove: HV ≅ DV. Ladder: 1. ∠QHV and ∠QDV are right angles — Given; 2. ? — Definition of right triangle; 3. QH ≅ QD — Given; 4. QV ≅ QV — Reflexive property; 5. △QHV ≅ △QDV — HL; 6. HV ≅ DV — CPCTC. Sketch, not to scale: triangles QHV and QDV share side QV; H is above QV and D is below, with right angles at H and D. Marked: right-angle boxes at H and D; QH and QD with one tick each. Given: ∠QHV and ∠QDV are right angles, and QH ≅ QD. Prove: HV ≅ DV. Ladder: 1. ∠QHV and ∠QDV are right angles — Given; 2. ? — Definition of right triangle; 3. QH ≅ QD — Given; 4. QV ≅ QV — Reflexive property; 5. △QHV ≅ △QDV — HL; 6. HV ≅ DV — CPCTC. Given: ∠QHV and ∠QDV are right angles, and QH ≅ QD. Prove: HV ≅ DV. Q V H D Ladder: 1. ∠QHV and ∠QDV are right angles -- Given; 2. ? -- Definition of right triangle; 3. QH ≅ QD -- Given; 4. QV ≅ QV -- Reflexive property; 5. triangle QHV ≅ triangle QDV -- HL; 6. HV ≅ DV -- CPCTC. Not to scale. - QV ⊥ HD
- △QHV and △QDV are right triangles
- HV ≅ DV
- △QHV ≅ △QDV
Noah crosses craft sticks WD and GC at S, with WC ∥ GD and WC ≅ DG. Which statement fills the blank?
Sketch, not to scale: segments WD and GC cross at S (W upper left, D lower right, C upper right, G lower left). Marked: arrows on WC and GD; WC and GD with one tick each. Given: WC ∥ GD and WC ≅ DG. Prove: CS ≅ GS. Ladder: 1. WC ∥ GD — Given; 2. ∠CWS ≅ ∠GDS — Alternate interior angles theorem; 3. WC ≅ DG — Given; 4. ? — Vertical angles theorem; 5. △WSC ≅ △DSG — AAS; 6. CS ≅ GS — CPCTC. Sketch, not to scale: segments WD and GC cross at S (W upper left, D lower right, C upper right, G lower left). Marked: arrows on WC and GD; WC and GD with one tick each. Given: WC ∥ GD and WC ≅ DG. Prove: CS ≅ GS. Ladder: 1. WC ∥ GD — Given; 2. ∠CWS ≅ ∠GDS — Alternate interior angles theorem; 3. WC ≅ DG — Given; 4. ? — Vertical angles theorem; 5. △WSC ≅ △DSG — AAS; 6. CS ≅ GS — CPCTC. Prove: CS ≅ GS W D C G S Given: WC ∥ GD; WC ≅ DG. 1. WC ∥ GD -- Given 2. ∠CWS ≅ ∠GDS -- Alternate interior angles theorem 3. WC ≅ DG -- Given 4. ? -- Vertical angles theorem 5. triangle WSC ≅ triangle DSG -- AAS 6. CS ≅ GS -- CPCTC Not to scale. - ∠WSC ≅ ∠DSG
- CS ≅ GS
- ∠WSC ≅ ∠WSG
- ∠WSC ≅ ∠SWC
Pia draws scissors whose blades YC and VF cross at H, with YF ∥ VC. Which statement fills the blank?
Sketch, not to scale: segments YC and VF cross at H (Y upper left, C lower right, F upper right, V lower left). Marked: arrows on YF and VC; YH and HC with one tick each. Given: YF ∥ VC, and H is the midpoint of YC. Prove: FH ≅ VH. Ladder: 1. YF ∥ VC — Given; 2. ∠FYH ≅ ∠VCH — Alternate interior angles theorem; 3. H is the midpoint of YC — Given; 4. ? — Definition of midpoint; 5. ∠YHF ≅ ∠CHV — Vertical angles theorem; 6. △YHF ≅ △CHV — ASA; 7. FH ≅ VH — CPCTC. Sketch, not to scale: segments YC and VF cross at H (Y upper left, C lower right, F upper right, V lower left). Marked: arrows on YF and VC; YH and HC with one tick each. Given: YF ∥ VC, and H is the midpoint of YC. Prove: FH ≅ VH. Ladder: 1. YF ∥ VC — Given; 2. ∠FYH ≅ ∠VCH — Alternate interior angles theorem; 3. H is the midpoint of YC — Given; 4. ? — Definition of midpoint; 5. ∠YHF ≅ ∠CHV — Vertical angles theorem; 6. △YHF ≅ △CHV — ASA; 7. FH ≅ VH — CPCTC. Y C F V H Not to scale. 1. YF ∥ VC Given 2. ∠FYH ≅ ∠VCH Alternate interior angles theorem 3. H is the midpoint of YC Given 4. YH ≅ HC Definition of midpoint 5. ∠YHF ≅ ∠CHV Vertical angles theorem 6. triangle YHF ≅ triangle CHV ASA 7. FH ≅ VH CPCTC - FH ≅ VH
- YH ≅ CH
- YH ≅ FH
- YC ≅ VF