Congruence proofs: fill in the missing step or reason
Grade 10 Math Worksheet - Building Confidence

Circle the best answer.
Ren checks whether two pizza slices CDF and GHQ match. Which reason fills the blank?
- Given
- SSS
- ASA
- SAS
Tala checks whether two tent flaps CDF and GHQ match. Which reason fills the blank?
Sketch, not to scale: triangles CDF and GHQ side by side, with C and G at the top. Marked: arcs at D and H; double arcs at F and Q; DF and HQ with one tick each. Given: ∠CDF ≅ ∠GHQ, DF ≅ HQ and ∠DFC ≅ ∠HQG. Prove: △CDF ≅ △GHQ. Ladder: 1. ∠CDF ≅ ∠GHQ, DF ≅ HQ and ∠DFC ≅ ∠HQG — Given; 2. △CDF ≅ △GHQ — ?. Sketch, not to scale: triangles CDF and GHQ side by side, with C and G at the top. Marked: arcs at D and H; double arcs at F and Q; DF and HQ with one tick each. Given: ∠CDF ≅ ∠GHQ, DF ≅ HQ and ∠DFC ≅ ∠HQG. Prove: △CDF ≅ △GHQ. Ladder: 1. ∠CDF ≅ ∠GHQ, DF ≅ HQ and ∠DFC ≅ ∠HQG — Given; 2. △CDF ≅ △GHQ — ?. D F C H Q G Not to scale - ASA
- AAS
- Given
- SAS
Read this first
Use this
Given: CD ≅ CG and DF ≅ GF. Prove: triangle CDF ≅ triangle CGF. Ladder: 1. CD ≅ CG -- Given; 2. DF ≅ GF -- Given; 3. CF ≅ CF -- ?; 4. triangle CDF ≅ triangle CGF -- SSS.
Bo builds a kite from two triangles, CDF and CGF, that share stick CF. Which reason fills the blank?
Sketch, not to scale: triangles CDF and CGF share side CF; D is above CF and G is below. Marked: CD and CG with one tick each; DF and GF with two ticks each. Given: CD ≅ CG and DF ≅ GF. Prove: △CDF ≅ △CGF. Ladder: 1. CD ≅ CG — Given; 2. DF ≅ GF — Given; 3. CF ≅ CF — ?; 4. △CDF ≅ △CGF — SSS. Sketch, not to scale: triangles CDF and CGF share side CF; D is above CF and G is below. Marked: CD and CG with one tick each; DF and GF with two ticks each. Given: CD ≅ CG and DF ≅ GF. Prove: △CDF ≅ △CGF. Ladder: 1. CD ≅ CG — Given; 2. DF ≅ GF — Given; 3. CF ≅ CF — ?; 4. △CDF ≅ △CGF — SSS. C D F G Not to scale. - Given
- Symmetric property
- Reflexive property
- CPCTC
Esme sews two triangle sails, SVU and SWU, that share edge SU. Which reason fills the blank?
Sketch, not to scale: triangles SVU and SWU share side SU; V is above SU and W is below. Marked: SV and SW with one tick each; VU and WU with two ticks each. Given: SV ≅ SW and VU ≅ WU. Prove: △SVU ≅ △SWU. Ladder: 1. SV ≅ SW — Given; 2. VU ≅ WU — Given; 3. SU ≅ SU — ?; 4. △SVU ≅ △SWU — SSS. Sketch, not to scale: triangles SVU and SWU share side SU; V is above SU and W is below. Marked: SV and SW with one tick each; VU and WU with two ticks each. Given: SV ≅ SW and VU ≅ WU. Prove: △SVU ≅ △SWU. Ladder: 1. SV ≅ SW — Given; 2. VU ≅ WU — Given; 3. SU ≅ SU — ?; 4. △SVU ≅ △SWU — SSS. Sketch, not to scale: triangles SVU and SWU share side SU; V is above SU and W is below. S U V W Given: SV ≅ SW and VU ≅ WU. Prove: triangle SVU ≅ triangle SWU. 1. SV ≅ SW -- Given 2. VU ≅ WU -- Given 3. SU ≅ SU -- ? 4. triangle SVU ≅ triangle SWU -- SSS - Given
- CPCTC
- Reflexive property
- Transitive property
Jun builds a kite whose stick QS splits the top angle evenly. Which reason fills the blank?
Sketch, not to scale: triangles QUS and QYS share side QS; U is above QS and Y is below. Marked: QU and QY with one tick each. Given: QU ≅ QY, and QS bisects ∠UQY. Prove: △QUS ≅ △QYS. Ladder: 1. QU ≅ QY — Given; 2. QS bisects ∠UQY — Given; 3. ∠UQS ≅ ∠YQS — ?; 4. QS ≅ QS — Reflexive property; 5. △QUS ≅ △QYS — SAS. Sketch, not to scale: triangles QUS and QYS share side QS; U is above QS and Y is below. Marked: QU and QY with one tick each. Given: QU ≅ QY, and QS bisects ∠UQY. Prove: △QUS ≅ △QYS. Ladder: 1. QU ≅ QY — Given; 2. QS bisects ∠UQY — Given; 3. ∠UQS ≅ ∠YQS — ?; 4. QS ≅ QS — Reflexive property; 5. △QUS ≅ △QYS — SAS. Sketch, not to scale: triangles QUS and QYS share side QS; U is above QS and Y is below Q S U Y Marked: QU and QY with one tick each. Given: QU ≅ QY, and QS bisects ∠UQY. Prove: triangle QUS ≅ triangle QYS. Not to scale. Ladder Statement Reason 1 QU ≅ QY Given 2 QS bisects ∠UQY Given 3 ∠UQS ≅ ∠YQS ? 4 QS ≅ QS Reflexive property 5 triangle QUS ≅ triangle QYS SAS - Vertical angles theorem
- CPCTC
- Definition of angle bisector
- Definition of midpoint
Use this
Sketch, not to scale: triangles FCH and FVH share side FH; C is above FH and V is below. Marked: FC and FV with one tick each. Given: FC ≅ FV, and FH bisects ∠CFV. Prove: triangle FCH ≅ triangle FVH. Ladder: 1. FC ≅ FV -- Given; 2. FH bisects ∠CFV -- Given; 3. ∠CFH ≅ ∠VFH -- ?; 4. FH ≅ FH -- Reflexive property; 5. triangle FCH ≅ triangle FVH -- SAS.
Kira sets a tent pole FH that splits the angle at F evenly. Which reason fills the blank?
Sketch, not to scale: triangles FCH and FVH share side FH; C is above FH and V is below. Marked: FC and FV with one tick each. Given: FC ≅ FV, and FH bisects ∠CFV. Prove: △FCH ≅ △FVH. Ladder: 1. FC ≅ FV — Given; 2. FH bisects ∠CFV — Given; 3. ∠CFH ≅ ∠VFH — ?; 4. FH ≅ FH — Reflexive property; 5. △FCH ≅ △FVH — SAS. Sketch, not to scale: triangles FCH and FVH share side FH; C is above FH and V is below. Marked: FC and FV with one tick each. Given: FC ≅ FV, and FH bisects ∠CFV. Prove: △FCH ≅ △FVH. Ladder: 1. FC ≅ FV — Given; 2. FH bisects ∠CFV — Given; 3. ∠CFH ≅ ∠VFH — ?; 4. FH ≅ FH — Reflexive property; 5. △FCH ≅ △FVH — SAS. F H C V Not to scale. - Definition of midpoint
- CPCTC
- Vertical angles theorem
- Definition of angle bisector
Luz sews two triangle patches, HCY and HQY, that share seam HY. Which statement fills the blank?
Sketch, not to scale: triangles HCY and HQY share side HY; C is above HY and Q is below. Marked: HC and HQ with one tick each; CY and QY with two ticks each. Given: HC ≅ HQ and CY ≅ QY. Prove: △HCY ≅ △HQY. Ladder: 1. HC ≅ HQ — Given; 2. CY ≅ QY — Given; 3. ? — Reflexive property; 4. △HCY ≅ △HQY — SSS. Sketch, not to scale: triangles HCY and HQY share side HY; C is above HY and Q is below. Marked: HC and HQ with one tick each; CY and QY with two ticks each. Given: HC ≅ HQ and CY ≅ QY. Prove: △HCY ≅ △HQY. Ladder: 1. HC ≅ HQ — Given; 2. CY ≅ QY — Given; 3. ? — Reflexive property; 4. △HCY ≅ △HQY — SSS. H Y C Q Given: HC ≅ HQ and CY ≅ QY. Prove: triangle HCY ≅ triangle HQY. Ladder: 1. HC ≅ HQ -- Given; 2. CY ≅ QY -- Given; 3. ? -- Reflexive property; 4. triangle HCY ≅ triangle HQY -- SSS. Not to scale. - HC ≅ HY
- HY ≅ HY
- CY ≅ HQ
- △HCY ≅ △HQY
Milo folds paper so triangles DGW and DSW share fold DW. Which statement fills the blank?
Sketch, not to scale: triangles DGW and DSW share side DW; G is above DW and S is below. Marked: DG and DS with one tick each; GW and SW with two ticks each. Given: DG ≅ DS and GW ≅ SW. Prove: △DGW ≅ △DSW. Ladder: 1. DG ≅ DS — Given; 2. GW ≅ SW — Given; 3. ? — Reflexive property; 4. △DGW ≅ △DSW — SSS. Sketch, not to scale: triangles DGW and DSW share side DW; G is above DW and S is below. Marked: DG and DS with one tick each; GW and SW with two ticks each. Given: DG ≅ DS and GW ≅ SW. Prove: △DGW ≅ △DSW. Ladder: 1. DG ≅ DS — Given; 2. GW ≅ SW — Given; 3. ? — Reflexive property; 4. △DGW ≅ △DSW — SSS. Given: DG ≅ DS and GW ≅ SW. Prove: triangle DGW ≅ triangle DSW. D W G S Ladder: 1. DG ≅ DS -- Given; 2. GW ≅ SW -- Given; 3. ? -- Reflexive property; 4. triangle DGW ≅ triangle DSW -- SSS. Not to scale. - GW ≅ DS
- DG ≅ DW
- DW ≅ DW
- △DGW ≅ △DSW
Noah builds a kite whose stick WC splits the angle at W evenly. Which statement fills the blank?
Sketch, not to scale: triangles WDC and WYC share side WC; D is above WC and Y is below. Marked: WD and WY with one tick each. Given: WD ≅ WY, and WC bisects ∠DWY. Prove: △WDC ≅ △WYC. Ladder: 1. WD ≅ WY — Given; 2. WC bisects ∠DWY — Given; 3. ? — Definition of angle bisector; 4. WC ≅ WC — Reflexive property; 5. △WDC ≅ △WYC — SAS. Sketch, not to scale: triangles WDC and WYC share side WC; D is above WC and Y is below. Marked: WD and WY with one tick each. Given: WD ≅ WY, and WC bisects ∠DWY. Prove: △WDC ≅ △WYC. Ladder: 1. WD ≅ WY — Given; 2. WC bisects ∠DWY — Given; 3. ? — Definition of angle bisector; 4. WC ≅ WC — Reflexive property; 5. △WDC ≅ △WYC — SAS. Sketch, not to scale W C D Y Triangles WDC and WYC share side WC; D is above WC and Y is below. Given: WD ≅ WY, and WC bisects ∠DWY. Prove: triangle WDC ≅ triangle WYC. Not to scale. Ladder 1. WD ≅ WY Given 2. WC bisects ∠DWY Given 3. ? Definition of angle bisector 4. WC ≅ WC Reflexive property 5. triangle WDC ≅ triangle WYC SAS - DC ≅ YC
- ∠DWC ≅ ∠WDC
- ∠DWC ≅ ∠YWC
- △WDC ≅ △WYC
Pia draws a roof beam GU that splits the angle at G evenly. Which statement fills the blank?
Sketch, not to scale: triangles GFU and GHU share side GU; F is above GU and H is below. Marked: GF and GH with one tick each. Given: GF ≅ GH, and GU bisects ∠FGH. Prove: △GFU ≅ △GHU. Ladder: 1. GF ≅ GH — Given; 2. GU bisects ∠FGH — Given; 3. ? — Definition of angle bisector; 4. GU ≅ GU — Reflexive property; 5. △GFU ≅ △GHU — SAS. Sketch, not to scale: triangles GFU and GHU share side GU; F is above GU and H is below. Marked: GF and GH with one tick each. Given: GF ≅ GH, and GU bisects ∠FGH. Prove: △GFU ≅ △GHU. Ladder: 1. GF ≅ GH — Given; 2. GU bisects ∠FGH — Given; 3. ? — Definition of angle bisector; 4. GU ≅ GU — Reflexive property; 5. △GFU ≅ △GHU — SAS. Sketch G F H U Given: GF ≅ GH, and GU bisects ∠FGH. Prove: triangle GFU ≅ triangle GHU. Ladder: 1. GF ≅ GH -- Given; 2. GU bisects ∠FGH -- Given; 3. ? -- Definition of angle bisector; 4. GU ≅ GU -- Reflexive property; 5. triangle GFU ≅ triangle GHU -- SAS. Not to scale. - FU ≅ HU
- ∠FGU ≅ ∠HGU
- △GFU ≅ △GHU
- ∠FGU ≅ ∠GFU