Nets, and views of a solid from the top, front and side
Grade 10 Math Worksheet - Challenge Me

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3 by 3 base of stacked cubes. Columns A, B, C run left to right as seen from the front; rows 1, 2, 3 run from the front to the back. Front view, tallest stack in each column: 3, 1, 1. Right-side view, tallest stack in each row (row 1 on the left): 2, 2, 3.
Ari builds on a 3 by 3 base and records the front and right-side views on the card. What is the least number of cubes the building could have?
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Columns A, B, C run left to right as seen from the front; rows 1, 2, 3 run from the front to the back. Front view, tallest stack in each column: 2, 3, 1. Right-side view, tallest stack in each row (row 1 on the left): 1, 1, 3.
Bo builds on a 3 by 3 base and records the front and right-side views on the card. What is the least number of cubes the building could have?
3 by 3 base of stacked cubes. Columns A, B, C run left to right as seen from the front; rows 1, 2, 3 run from the front to the back. Front view, tallest stack in each column: 2, 3, 1. Right-side view, tallest stack in each row (row 1 on the left): 1, 1, 3. 3 by 3 base of stacked cubes. Columns A, B, C run left to right as seen from the front; rows 1, 2, 3 run from the front to the back. Front view, tallest stack in each column: 2, 3, 1. Right-side view, tallest stack in each row (row 1 on the left): 1, 1, 3. 3 by 3 base A B C 1 2 3 front view A B C right-side view 1 2 3 Esme builds on a 3 by 3 base and records the front and right-side views on the card. What is the least number of cubes the building could have?
3 by 3 base of stacked cubes. Columns A, B, C run left to right as seen from the front; rows 1, 2, 3 run from the front to the back. Front view, tallest stack in each column: 4, 2, 1. Right-side view, tallest stack in each row (row 1 on the left): 3, 3, 4. 3 by 3 base of stacked cubes. Columns A, B, C run left to right as seen from the front; rows 1, 2, 3 run from the front to the back. Front view, tallest stack in each column: 4, 2, 1. Right-side view, tallest stack in each row (row 1 on the left): 3, 3, 4. Front view Right-side view Columns Rows A B C 1 2 3 4 2 1 3 3 4 3 by 3 base Jun makes stack A from 20 coins in a straight column, and stack B by sliding the same coins sideways into a leaning column of the same height. Which reply is justified?
- Equal volumes: slices at the same height have equal area (Cavalieri's principle)
- The stacks are congruent solids, because each slice has the same area at each height, so they match exactly
- Different volumes: the leaning stack is slanted, so it holds less
- Equal surface areas: slices of equal area give equal outsides
Kira compares a right cylinder with radius 3 cm and height 8 cm to a leaning cylinder with radius 3 cm, vertical height 8 cm and slant length 10 cm. Which reply is justified?
- The cylinders are congruent, since their slices match
- Equal surface areas, since both have radius 3 cm and height 8 cm
- Equal volumes, 72π cm³: slices at each height are circles of radius 3 cm
- Different volumes: the leaning cylinder is longer along its slant, so it holds 90π cm³ instead of 72π cm³
Luz has a square prism with base area 36 cm² and a cylinder with base area 36 cm². Both are 5 cm tall. Which reply is justified?
- The solids are congruent, since their slices have equal area
- Equal volumes, 180 cm³ each: slices at every height have equal area
- The cylinder is larger, because a round base of area 36 cm² holds more than a square one
- Equal surface areas, since both bases are 36 cm²
Milo drew two plans for one card. The card shows the front and right-side views. Which reply is justified?
Card: front view, tallest stack in each column from the left: 1, 2, 3; right-side view, tallest stack in each row (row 1 on the left): 3, 1, 2. Plan X, stack heights by row (columns left to right): row 1: 1, 2, 3; row 2: 1, 1, 1; row 3: 1, 2, 2. Plan Y: row 1: 0, 0, 3; row 2: 1, 0, 0; row 3: 0, 2, 0. Card: front view, tallest stack in each column from the left: 1, 2, 3; right-side view, tallest stack in each row (row 1 on the left): 3, 1, 2. Plan X, stack heights by row (columns left to right): row 1: 1, 2, 3; row 2: 1, 1, 1; row 3: 1, 2, 2. Plan Y: row 1: 0, 0, 3; row 2: 1, 0, 0; row 3: 0, 2, 0. Card front view right-side view Plan X row 1 row 2 row 3 1 2 3 1 1 1 1 2 2 Plan Y row 1 row 2 row 3 0 0 3 1 0 0 0 2 0 - Both plans fit the card, with 14 and 6 cubes, so the views do not fix the building
- Plan X does not fit the card, because 8 of its cubes are hidden and the card cannot show them
- Plan Y does not fit the card, because it holds 8 fewer cubes than plan X does
- Both plans fit the card, so both buildings must hold 14 cubes, the count of plan X
Card
Front view, tallest stack in each column from the left: 2, 2, 3; right-side view, tallest stack in each row (row 1 on the left): 2, 3, 1. Plan X, stack heights by row (columns left to right): row 1: 2, 2, 2; row 2: 2, 2, 3; row 3: 1, 1, 1. Plan Y: row 1: 0, 2, 0; row 2: 2, 0, 3; row 3: 0, 0, 1.
Noah drew two plans for one card. The card shows the front and right-side views. Which reply is justified?
- Both plans fit the card, with 16 and 8 cubes, so the views do not fix the building
- Plan X does not fit the card, because 8 of its cubes are hidden and the card cannot show them
- Both plans fit the card, so both buildings must hold 16 cubes, the count of plan X
- Plan Y does not fit the card, because it holds 8 fewer cubes than plan X does
Tala slices a sphere of radius 5 cm with a plane 3 cm from its center. How big is the circle, and why?
- A circle with radius 5 cm, since a slice of the sphere has the sphere's radius
- A circle with radius 4 cm, since 3² + 4² = 5²
- A circle with radius 2 cm, since the radius is 5 − 3 = 2 cm
- A circle with radius 3 cm, since the plane is 3 cm away from the center
Zee compares a hemisphere of radius r with a cylinder (radius r, height r) minus a cone with its apex at the center. Which fact shows their slices at height d match?
- The cylinder minus the cone has a ring of area πr² − πd² at height d
- The cylinder minus the cone has a ring of area π(r − d)² at height d, the square of the difference
- The cone has a slice of area π(r² − d²) at height d, the same as the hemisphere
- The cylinder has a slice of area πr² at height d, so it matches the hemisphere