Reflect over any line and rotate about a point, with coordinate rules
Grade 10 Math Worksheet - Challenge Me

Circle the best answer.
A rotation maps A(3, 1) to A′(1, 3) and B(4, 2) to B′(0, 4). Where is the center, and why does Milo know?
- (2, 3): the midpoint of BB′
- (2, 2): the midpoint of AA′
- (1, 1): on the perpendicular bisectors of AA′ and BB′
- (0, 0): rotations on this grid turn about the origin
Noah reflects a figure across y = x and then across x + y = 2. Which single motion does the same?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. The lines y = x and x + y = 2 are dashed; they meet at (1, 1). Coordinate grid, all four quadrants, each square one unit, origin in the middle. The lines y = x and x + y = 2 are dashed; they meet at (1, 1). −5 −4 −3 −2 −1 1 2 3 4 5 −5 −4 −3 −2 −1 1 2 3 4 5 0 y = x x + y = 2 - A half-turn about the origin
- A turn of 90° about (1, 1)
- A half-turn about (1, 1)
- A slide along the line y = x
Pia reflects a figure across y = x and then across y = x + 4. These lines are parallel. Which single slide does the same?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. The parallel lines y = x and y = x + 4 are dashed. Coordinate grid, all four quadrants, each square one unit, origin in the middle. The parallel lines y = x and y = x + 4 are dashed. −6 −4 −2 2 4 6 −6 −5 −4 −3 −2 −1 1 2 3 4 5 6 7 8 9 10 y = x y = x + 4 - (−4, 4): twice the 2√2 gap, across the lines
- (4, −4): twice the gap, but back toward the first line
- (−2, 2): the gap between the lines
- (0, 8): twice the 4-unit vertical gap
Lines ℓ and m meet at O at angle θ. Ren explains why reflecting across ℓ, then m, turns every point 2θ about O. Which reason is right?
Sketch: lines ℓ and m through O, θ apart; a point P at angle α from ℓ, inside the angle. Sketch: lines ℓ and m through O, θ apart; a point P at angle α from ℓ, inside the angle. l m θ alpha O P - Each reflection turns a point by θ, so the two together make θ + θ
- Two reflections keep orientation, so they make some turn
- The angle between the two images equals θ
- Each keeps OP, and the sweeps add: 2α + 2(θ − α) = 2θ
A figure maps onto itself under reflection across the x-axis and under reflection across the y-axis. Which other motion must Esme find maps it onto itself?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. The figure is not drawn; only the two mirror lines are dashed. Coordinate grid, all four quadrants, each square one unit, origin in the middle. The figure is not drawn; only the two mirror lines are dashed. x y - No other motion is forced
- A turn of 90° about the origin
- A half-turn about the origin
- A reflection across y = x
Two lines of symmetry of a regular pentagon meet at its center at 36°. Jun reflects across one and then the other. What single motion results?
Sketch: a regular pentagon with two of its lines of symmetry drawn, 36° apart at the center. Sketch: a regular pentagon with two of its lines of symmetry drawn, 36° apart at the center. 36° - A reflection across a third line of symmetry of the pentagon
- A turn of 72°, which maps the pentagon onto itself
- A turn of 36° about the center
- A turn of 144° about the center
Kira's parallelogram has unequal sides and no right angles. Which motions, other than doing nothing, map it onto itself?
Sketch: a parallelogram with unequal sides and no right angles, and its diagonals drawn. Sketch: a parallelogram with unequal sides and no right angles, and its diagonals drawn. - A reflection across the line through the midpoints of opposite sides
- A reflection across either diagonal
- A turn of 90° about the center
- Only the half-turn about the point where the diagonals cross
“each square one unit” Triangle A(0, 0), B(4, 0), C(0, 3) must land on P(2, 1), Q(2, 5), R(−1, 1), corner to corner. Which sequence does Luz find fails?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. Triangles ABC and PQR are drawn with their corners labeled. Coordinate grid, all four quadrants, each square one unit, origin in the middle. Triangles ABC and PQR are drawn with their corners labeled. x y 0 A B C P Q R - Turn 90° counterclockwise about the origin, then slide 2 right and 1 up
- Turn 90° counterclockwise about (0.5, 1.5)
- Turn 90° counterclockwise about P(2, 1)
- Slide 2 right and 1 up, then turn 90° counterclockwise about P
Segment AB runs from (1, 2) to (4, 6). Segment CD runs from (−2, 0) to (2, −3). Is there a rigid motion taking A to C and B to D, Milo asks?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. Segments AB and CD are drawn with their ends labeled. Coordinate grid, all four quadrants, each square one unit, origin in the middle. Segments AB and CD are drawn with their ends labeled. x y A B C D - No: just a reflection could do it, and that is not rigid
- Yes: the slide 3 left and 2 down
- Yes: both are 5 long; slide A to C, then turn about C
- No: the slopes differ, so no slide or turn makes them match
Coordinate grid, all four quadrants, each square one unit, origin in the middle. A rigid motion maps A(1, 1), B(5, 1), C(5, 4) to A′(2, −1), B′(2, −5) and C′. Which statement about C′ does Noah find is right?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. Triangle ABC, A′ and B′ are marked; C′ is not. Coordinate grid, all four quadrants, each square one unit, origin in the middle. Triangle ABC, A′ and B′ are marked; C′ is not. x y A B C A' B' 1 unit per square - (2, −8), 3 past B′ in a straight line
- (6, 2), the slide of C by (1, −2)
- (5, −5) alone, since the motion must keep the orientation
- (5, −5) after a turn, or (−1, −5) after a reflection