Reflect over any line and rotate about a point, with coordinate rules
Grade 10 Math Worksheet - Challenge Me

Circle the best answer.
A rotation maps A(3, 1) to A′(1, 3) and B(4, 2) to B′(0, 4). Where is the center, and why does Milo know?
- (1, 1): on the perpendicular bisectors of AA′ and BB′
- (2, 3): the midpoint of BB′
- (0, 0): rotations on this grid turn about the origin
- (2, 2): the midpoint of AA′
Pia reflects a figure across y = x and then across y = x + 4. These lines are parallel. Which single slide does the same?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. The parallel lines y = x and y = x + 4 are dashed. Coordinate grid, all four quadrants, each square one unit, origin in the middle. The parallel lines y = x and y = x + 4 are dashed. −6 −4 −2 2 4 6 −6 −5 −4 −3 −2 −1 1 2 3 4 5 6 7 8 9 10 y = x y = x + 4 - (−4, 4): twice the 2√2 gap, across the lines
- (4, −4): twice the gap, but back toward the first line
- (−2, 2): the gap between the lines
- (0, 8): twice the 4-unit vertical gap
Lines ℓ and m meet at O at angle θ. Ren explains why reflecting across ℓ, then m, turns every point 2θ about O. Which reason is right?
Sketch: lines ℓ and m through O, θ apart; a point P at angle α from ℓ, inside the angle. Sketch: lines ℓ and m through O, θ apart; a point P at angle α from ℓ, inside the angle. l m θ alpha O P - Each reflection turns a point by θ, so the two together make θ + θ
- Each keeps OP, and the sweeps add: 2α + 2(θ − α) = 2θ
- The angle between the two images equals θ
- Two reflections keep orientation, so they make some turn
A reflection maps P(−1, 4) to P′(5, 2). Which line does Tala find is the mirror line?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. P(−1, 4) and P′(5, 2) are marked; no line is drawn. Coordinate grid, all four quadrants, each square one unit, origin in the middle. P(−1, 4) and P′(5, 2) are marked; no line is drawn. −6 −5 −4 −3 −2 −1 1 2 3 4 5 6 7 8 −5 −4 −3 −2 −1 1 2 3 4 5 6 0 P P' - x = 2, through the midpoint
- y = −x/3 + 11/3, through P and P′
- y = 3x, through the origin
- y = 3x − 3
A rotation about C maps A to A′. Zee says C must lie on the perpendicular bisector of AA′. Which reason is right?
Sketch: points A and A′, segment AA′, and a center C off the segment. Sketch: points A and A′, segment AA′, and a center C off the segment. A A' C - The rotation turns AA′ by 90° about its own midpoint
- C is the midpoint of AA′, so it splits AA′ in half
- AA′ passes through C, which is fixed by the turn
- CA = CA′, since a turn keeps distance to its center
A rotation maps A(0, 4) to A′(4, 0). Which point does Bo show could NOT be its center?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. A(0, 4) and A′(4, 0) are marked. Coordinate grid, all four quadrants, each square one unit, origin in the middle. A(0, 4) and A′(4, 0) are marked. −5 −4 −3 −2 −1 1 2 3 4 5 6 7 −5 −4 −3 −2 −1 1 2 3 4 5 6 7 0 A A' - (2, 2)
- (0, 0)
- (5, 5)
- (3, 1)
A figure maps onto itself under reflection across the x-axis and under reflection across the y-axis. Which other motion must Esme find maps it onto itself?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. The figure is not drawn; only the two mirror lines are dashed. Coordinate grid, all four quadrants, each square one unit, origin in the middle. The figure is not drawn; only the two mirror lines are dashed. x y - A turn of 90° about the origin
- A reflection across y = x
- A half-turn about the origin
- No other motion is forced
Two lines of symmetry of a regular pentagon meet at its center at 36°. Jun reflects across one and then the other. What single motion results?
Sketch: a regular pentagon with two of its lines of symmetry drawn, 36° apart at the center. Sketch: a regular pentagon with two of its lines of symmetry drawn, 36° apart at the center. 36° - A turn of 36° about the center
- A turn of 144° about the center
- A turn of 72°, which maps the pentagon onto itself
- A reflection across a third line of symmetry of the pentagon
Segment AB runs from (1, 2) to (4, 6). Segment CD runs from (−2, 0) to (2, −3). Is there a rigid motion taking A to C and B to D, Milo asks?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. Segments AB and CD are drawn with their ends labeled. Coordinate grid, all four quadrants, each square one unit, origin in the middle. Segments AB and CD are drawn with their ends labeled. x y A B C D - No: the slopes differ, so no slide or turn makes them match
- Yes: both are 5 long; slide A to C, then turn about C
- Yes: the slide 3 left and 2 down
- No: just a reflection could do it, and that is not rigid
Pia reflects across the x-axis and then turns 90° counterclockwise about the origin, and claims the result is one reflection across y = x. Which verdict is right?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. Point (3, 1) is marked to test the claim. Coordinate grid, all four quadrants, each square one unit, origin in the middle. Point (3, 1) is marked to test the claim. −5 −4 −3 −2 −1 1 2 3 4 5 −5 −4 −3 −2 −1 1 2 3 4 5 0 - Wrong: it is a reflection across y = −x
- Wrong: it is a 90° turn about the origin
- Wrong: a reflection and then a turn make a turn
- Right: (x, y) → (x, −y) → (y, x)