Reflect over any line and rotate about a point, with coordinate rules
Grade 10 Math Worksheet

Circle the best answer.
Kira claims that reflecting across y = x and then turning 90° counterclockwise about the origin gives the same result in either order. Test it on D(3, 1). Which verdict is right?
- Wrong: a reflection then a turn is not a rigid motion
- Wrong: D lands on (−3, 1) one way and (3, −1) the other
- Right: both orders send D to (−3, 1)
- Right: both moves keep lengths, so the two results must match
Triangle A(1, 1), B(4, 1), C(1, 3) must land on A′(−1, −1), B′(−4, −1), C′(−1, −3), corner to corner. Which sequence does Luz find fails?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. Triangles ABC and A′B′C′ are drawn with their corners labeled. Coordinate grid, all four quadrants, each square one unit, origin in the middle. Triangles ABC and A′B′C′ are drawn with their corners labeled. x y origin each square one unit A B C A' B' C' - Reflect across y = x, then across y = −x
- A half-turn about the origin
- Reflect across the x-axis, then across the y-axis
- Reflect across the y-axis, then across y = x
Triangle ABC reads A, B, C clockwise. Its congruent image reads A′, B′, C′ counterclockwise. Which kind of sequence could Milo use to map ABC onto A′B′C′?
Two congruent triangles, ABC and A′B′C′, are sketched apart; arrows show ABC clockwise and A′B′C′ counterclockwise. Two congruent triangles, ABC and A′B′C′, are sketched apart; arrows show ABC clockwise and A′B′C′ counterclockwise. ABC clockwise A'B'C' counterclockwise A B C A' B' C' Not to scale. - A slide alone
- One reflection, perhaps followed by a slide
- Two reflections, one after the other
- A rotation about one of the corners of triangle ABC
Noah maps quadrilateral ABCD onto PQRS by a dilation with factor 2 and then a rotation, and says the shapes are congruent. Which verdict is right?
Quadrilateral ABCD and a larger quadrilateral PQRS are sketched; the dilation and the rotation are written beside them. Quadrilateral ABCD and a larger quadrilateral PQRS are sketched; the dilation and the rotation are written beside them. A B C D dilation rotation P Q R S - Shown: the shapes have the same angles, so they are congruent
- Not shown: a dilation with factor 2 doubles every length
- Shown: the rotation is rigid, so the two shapes are congruent
- Not shown: the rotation changes the angles of ABCD
Pia turns a figure 90° counterclockwise about the origin and then reflects it across the x-axis. Which single motion does the same?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. Point (3, 1) is marked to test the motions. Coordinate grid, all four quadrants, each square one unit, origin in the middle. Point (3, 1) is marked to test the motions. −10 −8 −6 −4 −2 2 4 6 8 10 −10 −9 −8 −7 −6 −5 −4 −3 −2 −1 1 2 3 4 5 6 7 8 9 10 - A turn of 90° clockwise about the origin
- A reflection across y = −x
- A half-turn about the origin
- A reflection across y = x
Ren reflects any point (x, y) across x = 1 and then across x = 4. Which line of algebra shows the result is one slide?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. The mirror lines x = 1 and x = 4 are dashed. Coordinate grid, all four quadrants, each square one unit, origin in the middle. The mirror lines x = 1 and x = 4 are dashed. −10 −8 −6 −4 −2 2 4 6 8 10 −10 −9 −8 −7 −6 −5 −4 −3 −2 −1 1 2 3 4 5 6 7 8 9 10 x = 1 x = 4 - x → 2 − x → 8 + x, a slide of 8
- x → 2 − x → 8 − (2 − x) = x + 6, a slide 6 right
- x → 2 − x → 2 − (8 − x) = x − 6, a slide 6 left
- x → 2 − x → 8 − x, a slide of 3, the gap
Zee wants two reflections across vertical lines that together slide every point 8 units right. Which pair works?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. Vertical lines can be drawn at any x. Coordinate grid, all four quadrants, each square one unit, origin in the middle. Vertical lines can be drawn at any x. −10 −8 −6 −4 −2 2 4 6 8 10 −10 −9 −8 −7 −6 −5 −4 −3 −2 −1 1 2 3 4 5 6 7 8 9 10 Vertical lines can be drawn at any x. - y = 1, then y = 5
- x = 1, then x = 9
- x = 1, then x = 5
- x = 5, then x = 1
A rigid motion maps A(0, 0) to A′(2, 1) and B(3, 4) to B′. Which point does Esme find could be B′?
Coordinate grid, all four quadrants, each square one unit, origin in the middle. A(0, 0), B(3, 4) and A′(2, 1) are marked. Coordinate grid, all four quadrants, each square one unit, origin in the middle. A(0, 0), B(3, 4) and A′(2, 1) are marked. −6 −5 −4 −3 −2 −1 1 2 3 4 5 6 −6 −5 −4 −3 −2 −1 1 2 3 4 5 6 0 A B A' - (5, 4)
- (6, 4)
- (7, 2)
- (4, 5)
Lines ℓ and m are perpendicular and meet at P. Jun turns both 30° about a point O, not P. What must be true of the images ℓ′ and m′?
Sketch: lines ℓ ⊥ m meeting at P, and a separate point O; the turn is 30° counterclockwise. Sketch: lines ℓ ⊥ m meeting at P, and a separate point O; the turn is 30° counterclockwise. l m 30° counterclockwise P O - They meet at 30° plus 90°, 120°
- They are perpendicular and meet at P′, the image of P
- They are perpendicular just when O is P
- They are parallel to ℓ and m and still meet at the point P
AB = DE, AC = DF and ∠A = ∠D. Kira slides A onto D, then turns until ray AB lies on ray DE. Why does C then land on F?
Sketch: triangles ABC and DEF with AB = DE, AC = DF and ∠A = ∠D marked. Sketch: triangles ABC and DEF with AB = DE, AC = DF and ∠A = ∠D marked. A B C D E F - C lands on F, or on F's mirror image in DE; a reflection in DE then fixes it
- C lands on F once BC = EF is checked as well, as in SSS
- C must land on F, since rigid motions keep lengths and angles
- C lands on F because the two triangles have equal areas