Sequences of transformations, including glide reflections
Grade 10 Math Worksheet

Circle the best answer, or write your answer on the line.
Read this first
Use this
Coordinate grid, all four quadrants, 20 squares across. △PQR: P(1, 1), Q(4, 1), R(1, 3). Its image: P′(1, 0), Q′(1, 3), R′(-1, 0). Both are drawn.
Bo moved a triangle on a grid with two moves in a row. Which two moves, in order, carry it onto its image?
- A slide 2 right and 1 down, then a 90° counterclockwise turn about the origin
- A 90° clockwise turn about the origin, then a slide 2 right and 1 down
- A 90° counterclockwise turn about the origin, then a slide 2 right and 1 down
- A 90° counterclockwise turn about the origin, then a slide 1 down
Coordinate grid, all four quadrants, 20 squares across. Both are drawn. Kira moved a triangle on a grid with two moves in a row. Which two moves, in order, carry it onto its image?
- A flip across the y-axis, then a slide 7 right and 3 down
- A slide 1 right and 3 down, then a flip across the y-axis
- A flip across the y-axis, then a slide 1 right and 3 down
- A flip across the x-axis, then a slide 1 right and 3 down
Coordinate grid, all four quadrants, 20 squares across. Jun moved a triangle on a grid with two moves in a row. Which two moves, in order, carry it onto its image?
Coordinate grid, all four quadrants, 20 squares across. △GHJ: G(2, -1), H(5, -1), J(2, -4). Its image: G′(-3, 7), H′(-6, 7), J′(-3, 10). Both are drawn. Coordinate grid, all four quadrants, 20 squares across. △GHJ: G(2, -1), H(5, -1), J(2, -4). Its image: G′(-3, 7), H′(-6, 7), J′(-3, 10). Both are drawn. x y G(2, -1) H(5, -1) J(2, -4) G'(-3, 7) H'(-6, 7) J'(-3, 10) - A slide 1 left and 6 up, then a 180° turn about the origin
- A 180° turn about the origin, then a slide 1 left and 6 up
- A 180° turn about the origin, then a slide 5 left and 8 up
- A 90° counterclockwise turn about the origin, then a slide 1 left and 6 up
Luz moved a triangle on a grid with two moves in a row. Which two moves, in order, carry it onto its image?
Coordinate grid, all four quadrants, 20 squares across. △KLM: K(1, 2), L(4, 2), M(4, 5). Its image: K′(0, -2), L′(0, 1), M′(3, 1). Both are drawn. Coordinate grid, all four quadrants, 20 squares across. △KLM: K(1, 2), L(4, 2), M(4, 5). Its image: K′(0, -2), L′(0, 1), M′(3, 1). Both are drawn. 20 squares across x y K(1, 2) L(4, 2) M(4, 5) K'(0, -2) L'(0, 1) M'(3, 1) - A flip across the line y = x, then a slide 1 left and 4 down
- A slide 2 left and 3 down, then a flip across the line y = x
- A flip across the line y = x, then a slide 2 left and 3 down
- A flip across the line y = -x, then a slide 2 left and 3 down
Zee's tile pattern uses a glide reflection: a slide along the mirror line y = k, then a flip across it. Corner P(-2, 5) lands on P′(7, -1). What is k?
Coordinate grid, all four quadrants, 20 squares across. P(-2, 5) and its image P′(7, -1) are marked. The slide length and the mirror line are not given. Coordinate grid, all four quadrants, 20 squares across. P(-2, 5) and its image P′(7, -1) are marked. The slide length and the mirror line are not given. 20 squares across x y P(-2, 5) P'(7, -1) The slide length and the mirror line are not given. Ari's tile pattern uses a glide reflection: a slide along the mirror line y = k, then a flip across it. Corner P(2, -4) lands on P′(-5, 6). What is k?
Coordinate grid, all four quadrants, 20 squares across. P(2, -4) and its image P′(-5, 6) are marked. The slide length and the mirror line are not given. Coordinate grid, all four quadrants, 20 squares across. P(2, -4) and its image P′(-5, 6) are marked. The slide length and the mirror line are not given. x y -10 -5 0 5 10 8 4 0 -4 -8 20 squares across P(2, -4) P'(-5, 6) Tala tests whether order matters. Image 1: flip a design across the y-axis, then slide it 6 units right. Image 2: slide first, then flip. How do the images compare?
A design with corner (x, y). Image 1 is made by flip, then slide. Image 2 is made by slide, then flip. Both use a flip across the y-axis and a slide 6 units right. A design with corner (x, y). Image 1 is made by flip, then slide. Image 2 is made by slide, then flip. Both use a flip across the y-axis and a slide 6 units right. Image 1 6 units right y-axis A design with corner (x, y). Image 1 is made by flip, then slide. Both use a flip across the y-axis and a slide 6 units right. Not to scale. Image 2 6 units right y-axis Image 2 is made by slide, then flip. Both use a flip across the y-axis and a slide 6 units right. Not to scale. - The same image, because a slide and a flip are both rigid motions
- Different: image 1 is 6 units to the right of image 2
- Different: image 1 is 12 units to the left of image 2
- Different: image 1 is 12 units to the right of image 2
Ren wants A to land on D, B on E and C on F, using only turns and slides. Which statement is right?
Coordinate grid, all four quadrants, 20 squares across. △ABC: A(0, 0), B(4, 0), C(0, 3). △DEF: D(2, 1), E(2, 5), F(5, 1). Going A to B to C turns left. Going D to E to F turns right. Coordinate grid, all four quadrants, 20 squares across. △ABC: A(0, 0), B(4, 0), C(0, 3). △DEF: D(2, 1), E(2, 5), F(5, 1). Going A to B to C turns left. Going D to E to F turns right. x y −10 −8 −6 −4 −2 2 4 6 8 10 −10 −8 −6 −4 −2 2 4 6 8 10 0 turns left turns right A B C D E F Coordinate grid, all four quadrants, 20 squares across. triangle ABC: A(0, 0), B(4, 0), C(0, 3). triangle DEF: D(2, 1), E(2, 5), F(5, 1). - It can be done: slide A onto D, then turn 90° counterclockwise about D
- It can be done: the three side lengths match, and turns and slides keep lengths
- It cannot be done: △DEF is bigger than △ABC
- It cannot be done: the triangles are congruent, but a flip is needed to reverse the turn direction
Use this
AB = DE = 5 cm. ∠B = ∠E = 40°. BC = EF = 7 cm. A on D uses AB = DE.
Pia moves △ABC so B lands on E and A lands on D, flipping if needed so C is on the same side of line DE as F. Which fact puts C exactly on F?
- AB = DE again: it already put A on D, so it also puts C on F
- BC = EF alone: equal lengths put C exactly on F
- ∠B = ∠E alone: equal angles put C exactly on F
- ∠B = ∠E puts C on ray EF, and BC = EF stops C at F
Kira moves △ABC so A lands on D and B on E, with C on the same side of DE as F. Which facts put C exactly on F?
AB = DE = 6 cm. ∠A = ∠D = 50°. ∠B = ∠E = 60°. A on D and B on E use AB = DE. AB = DE = 6 cm. ∠A = ∠D = 50°. ∠B = ∠E = 60°. A on D and B on E use AB = DE. A B C D E F 6 cm 6 cm 50° 60° 50° 60° AB = DE - ∠A = ∠D alone: C is on ray DF, which is enough to fix C at F
- Both angle pairs: C is on ray DF and on ray EF, and those rays meet only at F
- AB = DE again: it already put A on D and B on E, so C follows
- ∠C = ∠F: the third angles are equal, so C lands on F