Sequences of transformations, including glide reflections
Grade 10 Math Worksheet

Circle the best answer, or write your answer on the line.
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Coordinate grid, all four quadrants, 20 squares across. △PQR: P(1, 1), Q(4, 1), R(1, 3). Its image: P′(1, 0), Q′(1, 3), R′(-1, 0). Both are drawn.
Bo moved a triangle on a grid with two moves in a row. Which two moves, in order, carry it onto its image?
- A slide 2 right and 1 down, then a 90° counterclockwise turn about the origin
- A 90° counterclockwise turn about the origin, then a slide 1 down
- A 90° counterclockwise turn about the origin, then a slide 2 right and 1 down
- A 90° clockwise turn about the origin, then a slide 2 right and 1 down
Coordinate grid, all four quadrants, 20 squares across. Jun moved a triangle on a grid with two moves in a row. Which two moves, in order, carry it onto its image?
- A 180° turn about the origin, then a slide 1 left and 6 up
- A 180° turn about the origin, then a slide 5 left and 8 up
- A slide 1 left and 6 up, then a 180° turn about the origin
- A 90° counterclockwise turn about the origin, then a slide 1 left and 6 up
Luz moved a triangle on a grid with two moves in a row. Which two moves, in order, carry it onto its image?
Coordinate grid, all four quadrants, 20 squares across. △KLM: K(1, 2), L(4, 2), M(4, 5). Its image: K′(0, -2), L′(0, 1), M′(3, 1). Both are drawn. Coordinate grid, all four quadrants, 20 squares across. △KLM: K(1, 2), L(4, 2), M(4, 5). Its image: K′(0, -2), L′(0, 1), M′(3, 1). Both are drawn. 20 squares across x y K(1, 2) L(4, 2) M(4, 5) K'(0, -2) L'(0, 1) M'(3, 1) - A flip across the line y = x, then a slide 2 left and 3 down
- A slide 2 left and 3 down, then a flip across the line y = x
- A flip across the line y = -x, then a slide 2 left and 3 down
- A flip across the line y = x, then a slide 1 left and 4 down
Coordinate grid, all four quadrants, 20 squares across. Milo moved a triangle on a grid with two moves in a row. Which two moves, in order, carry it onto its image?
Coordinate grid, all four quadrants, 20 squares across. △NPQ: N(-4, -1), P(-1, -1), Q(-4, 2). Its image: N′(-1, 1), P′(2, 1), Q′(-1, -2). Both are drawn. Coordinate grid, all four quadrants, 20 squares across. △NPQ: N(-4, -1), P(-1, -1), Q(-4, 2). Its image: N′(-1, 1), P′(2, 1), Q′(-1, -2). Both are drawn. N(-4, -1) P(-1, -1) Q(-4, 2) N'(-1, 1) P'(2, 1) Q'(-1, -2) - A slide 3 right and 2 down, then a flip across the line y = 1
- A flip across the line y = 1, then a slide 3 right and 2 down
- A flip across the line y = -1, then a slide 3 right and 2 down
- A flip across the line y = 1, then a slide 3 right and 2 up
Zee's tile pattern uses a glide reflection: a slide along the mirror line y = k, then a flip across it. Corner P(-2, 5) lands on P′(7, -1). What is k?
Coordinate grid, all four quadrants, 20 squares across. P(-2, 5) and its image P′(7, -1) are marked. The slide length and the mirror line are not given. Coordinate grid, all four quadrants, 20 squares across. P(-2, 5) and its image P′(7, -1) are marked. The slide length and the mirror line are not given. 20 squares across x y P(-2, 5) P'(7, -1) Tala tests whether order matters. Image 1: flip a design across the y-axis, then slide it 6 units right. Image 2: slide first, then flip. How do the images compare?
A design with corner (x, y). Image 1 is made by flip, then slide. Image 2 is made by slide, then flip. Both use a flip across the y-axis and a slide 6 units right. A design with corner (x, y). Image 1 is made by flip, then slide. Image 2 is made by slide, then flip. Both use a flip across the y-axis and a slide 6 units right. Image 1 6 units right y-axis A design with corner (x, y). Image 1 is made by flip, then slide. Both use a flip across the y-axis and a slide 6 units right. Not to scale. Image 2 6 units right y-axis Image 2 is made by slide, then flip. Both use a flip across the y-axis and a slide 6 units right. Not to scale. - Different: image 1 is 12 units to the right of image 2
- Different: image 1 is 12 units to the left of image 2
- The same image, because a slide and a flip are both rigid motions
- Different: image 1 is 6 units to the right of image 2
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A design with corner (x, y). Image 1 is made by the half turn, then the flip. Image 2 is made by the flip, then the half turn.
Esme asks whether order matters for a 180° turn about the origin and a flip across the y-axis. Image 1: turn, then flip. Image 2: flip, then turn. How do the images compare?
- Different: order matters when one of the moves is a flip
- The same: both orders send (x, y) to (x, -y)
- Different: the two images are mirror images across the x-axis
- The same: both orders send (x, y) to (-x, -y)
Ren wants A to land on D, B on E and C on F, using only turns and slides. Which statement is right?
Coordinate grid, all four quadrants, 20 squares across. △ABC: A(0, 0), B(4, 0), C(0, 3). △DEF: D(2, 1), E(2, 5), F(5, 1). Going A to B to C turns left. Going D to E to F turns right. Coordinate grid, all four quadrants, 20 squares across. △ABC: A(0, 0), B(4, 0), C(0, 3). △DEF: D(2, 1), E(2, 5), F(5, 1). Going A to B to C turns left. Going D to E to F turns right. x y −10 −8 −6 −4 −2 2 4 6 8 10 −10 −8 −6 −4 −2 2 4 6 8 10 0 turns left turns right A B C D E F Coordinate grid, all four quadrants, 20 squares across. triangle ABC: A(0, 0), B(4, 0), C(0, 3). triangle DEF: D(2, 1), E(2, 5), F(5, 1). - It cannot be done: △DEF is bigger than △ABC
- It cannot be done: the triangles are congruent, but a flip is needed to reverse the turn direction
- It can be done: slide A onto D, then turn 90° counterclockwise about D
- It can be done: the three side lengths match, and turns and slides keep lengths
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AB = DE = 5 cm. ∠B = ∠E = 40°. BC = EF = 7 cm. A on D uses AB = DE.
Pia moves △ABC so B lands on E and A lands on D, flipping if needed so C is on the same side of line DE as F. Which fact puts C exactly on F?
- ∠B = ∠E alone: equal angles put C exactly on F
- BC = EF alone: equal lengths put C exactly on F
- ∠B = ∠E puts C on ray EF, and BC = EF stops C at F
- AB = DE again: it already put A on D, so it also puts C on F
Kira moves △ABC so A lands on D and B on E, with C on the same side of DE as F. Which facts put C exactly on F?
AB = DE = 6 cm. ∠A = ∠D = 50°. ∠B = ∠E = 60°. A on D and B on E use AB = DE. AB = DE = 6 cm. ∠A = ∠D = 50°. ∠B = ∠E = 60°. A on D and B on E use AB = DE. A B C D E F 6 cm 6 cm 50° 60° 50° 60° AB = DE - Both angle pairs: C is on ray DF and on ray EF, and those rays meet only at F
- ∠C = ∠F: the third angles are equal, so C lands on F
- AB = DE again: it already put A on D and B on E, so C follows
- ∠A = ∠D alone: C is on ray DF, which is enough to fix C at F