Similarity proofs: fill in the missing step or reason
Grade 10 Math Worksheet

Circle the best answer.
Read this first
Use this
Given: DH ∥ FG. Prove: DQ/GQ = HQ/FQ. Ladder: 1. DH ∥ FG -- Given; 2. ∠HDQ ≅ ∠FGQ -- Alternate interior angles theorem; 3. ∠DQH ≅ ∠GQF -- Vertical angles theorem; 4. triangle DQH ~ triangle GQF -- AA similarity postulate; 5. DQ/GQ = HQ/FQ -- ?.
Bo draws a bike frame where bars DG and FH cross at Q, with DH ∥ FG. Which reason fills the blank?
- AA similarity postulate
- Definition of similar triangles
- Triangle proportionality theorem
- Given
Use this
Given: HD ∥ YU. Prove: HF/UF = DF/YF. Ladder: 1. HD ∥ YU -- Given; 2. ∠DHF ≅ ∠YUF -- Alternate interior angles theorem; 3. ∠HFD ≅ ∠UFY -- Vertical angles theorem; 4. triangle HFD ~ triangle UFY -- ?; 5. HF/UF = DF/YF -- Definition of similar triangles.
Jun opens scissors with blades HU and YD crossing at F, with HD ∥ YU. Which reason fills the blank?
Sketch, not to scale: segments HU and YD cross at F (H upper left, U lower right, D upper right, Y lower left). Marked: arrows on HD and YU. Given: HD ∥ YU. Prove: HF/UF = DF/YF. Ladder: 1. HD ∥ YU — Given; 2. ∠DHF ≅ ∠YUF — Alternate interior angles theorem; 3. ∠HFD ≅ ∠UFY — Vertical angles theorem; 4. △HFD ~ △UFY — ?; 5. HF/UF = DF/YF — Definition of similar triangles. Sketch, not to scale: segments HU and YD cross at F (H upper left, U lower right, D upper right, Y lower left). Marked: arrows on HD and YU. Given: HD ∥ YU. Prove: HF/UF = DF/YF. Ladder: 1. HD ∥ YU — Given; 2. ∠DHF ≅ ∠YUF — Alternate interior angles theorem; 3. ∠HFD ≅ ∠UFY — Vertical angles theorem; 4. △HFD ~ △UFY — ?; 5. HF/UF = DF/YF — Definition of similar triangles. HD ∥ YU H U D Y F Not to scale. - AA similarity postulate
- SAS similarity theorem
- AAS
- Vertical angles theorem
Use this
Ladder: 1. WC ∥ GD -- Given; 2. ∠CWS ≅ ∠GDS -- Alternate interior angles theorem; 3. ∠WSC ≅ ∠DSG -- Vertical angles theorem; 4. triangle WSC ~ triangle DSG -- ?; 5. WS/DS = CS/GS -- Definition of similar triangles.
Kira draws two ramps WD and GC that cross at S, with WC ∥ GD. Which reason fills the blank?
Sketch, not to scale: segments WD and GC cross at S (W upper left, D lower right, C upper right, G lower left). Marked: arrows on WC and GD. Given: WC ∥ GD. Prove: WS/DS = CS/GS. Ladder: 1. WC ∥ GD — Given; 2. ∠CWS ≅ ∠GDS — Alternate interior angles theorem; 3. ∠WSC ≅ ∠DSG — Vertical angles theorem; 4. △WSC ~ △DSG — ?; 5. WS/DS = CS/GS — Definition of similar triangles. Sketch, not to scale: segments WD and GC cross at S (W upper left, D lower right, C upper right, G lower left). Marked: arrows on WC and GD. Given: WC ∥ GD. Prove: WS/DS = CS/GS. Ladder: 1. WC ∥ GD — Given; 2. ∠CWS ≅ ∠GDS — Alternate interior angles theorem; 3. ∠WSC ≅ ∠DSG — Vertical angles theorem; 4. △WSC ~ △DSG — ?; 5. WS/DS = CS/GS — Definition of similar triangles. W C S D G Given: WC ∥ GD. Prove: WS/DS = CS/GS. Not to scale. - AA similarity postulate
- Vertical angles theorem
- SSS similarity theorem
- ASA
Luz measures a stripe VQ across a road sign HCS, level with its base CS. Which reason fills the blank?
Sketch, not to scale: triangle HCS with H at the top and base CS; V is on HC, Q is on HS, and segment VQ is drawn. Marked: arrows on VQ and CS; HV = 4, VC = 3, HQ = 8. Given: VQ ∥ CS, HV = 4, VC = 3 and HQ = 8. Prove: QS = 6. Ladder: 1. VQ ∥ CS — Given; 2. HV/VC = HQ/QS — Triangle proportionality theorem; 3. 4/3 = 8/QS — Substitution property; 4. 4 · QS = 24 — ?; 5. QS = 6 — Division property of equality. Sketch, not to scale: triangle HCS with H at the top and base CS; V is on HC, Q is on HS, and segment VQ is drawn. Marked: arrows on VQ and CS; HV = 4, VC = 3, HQ = 8. Given: VQ ∥ CS, HV = 4, VC = 3 and HQ = 8. Prove: QS = 6. Ladder: 1. VQ ∥ CS — Given; 2. HV/VC = HQ/QS — Triangle proportionality theorem; 3. 4/3 = 8/QS — Substitution property; 4. 4 · QS = 24 — ?; 5. QS = 6 — Division property of equality. C S H V Q 4 3 8 Not to scale - Cross products property
- Triangle proportionality theorem
- Substitution property
- Division property of equality
Milo measures a cord DW across a tent front YFG, level with the floor FG. Which reason fills the blank?
Sketch, not to scale: triangle YFG with Y at the top and base FG; D is on YF, W is on YG, and segment DW is drawn. Marked: arrows on DW and FG; YD = 5, DF = 2, YW = 20. Given: DW ∥ FG, YD = 5, DF = 2 and YW = 20. Prove: WG = 8. Ladder: 1. DW ∥ FG — Given; 2. YD/DF = YW/WG — Triangle proportionality theorem; 3. 5/2 = 20/WG — Substitution property; 4. 5 · WG = 40 — ?; 5. WG = 8 — Division property of equality. Sketch, not to scale: triangle YFG with Y at the top and base FG; D is on YF, W is on YG, and segment DW is drawn. Marked: arrows on DW and FG; YD = 5, DF = 2, YW = 20. Given: DW ∥ FG, YD = 5, DF = 2 and YW = 20. Prove: WG = 8. Ladder: 1. DW ∥ FG — Given; 2. YD/DF = YW/WG — Triangle proportionality theorem; 3. 5/2 = 20/WG — Substitution property; 4. 5 · WG = 40 — ?; 5. WG = 8 — Division property of equality. F G Y D W 5 2 20 Not to scale - Cross products property
- Division property of equality
- Distributive property
- Definition of similar triangles
Use this
Given: YF ∥ VC. Prove: YH/CH = FH/VH. Ladder: 1. YF ∥ VC -- Given; 2. ? -- Alternate interior angles theorem; 3. ∠YHF ≅ ∠CHV -- Vertical angles theorem; 4. triangle YHF ~ triangle CHV -- AA similarity postulate; 5. YH/CH = FH/VH -- Definition of similar triangles.
Noah draws scissors whose blades YC and VF cross at H, with YF ∥ VC. Which statement fills the blank?
Sketch, not to scale: segments YC and VF cross at H (Y upper left, C lower right, F upper right, V lower left). Marked: arrows on YF and VC. Given: YF ∥ VC. Prove: YH/CH = FH/VH. Ladder: 1. YF ∥ VC — Given; 2. ? — Alternate interior angles theorem; 3. ∠YHF ≅ ∠CHV — Vertical angles theorem; 4. △YHF ~ △CHV — AA similarity postulate; 5. YH/CH = FH/VH — Definition of similar triangles. Sketch, not to scale: segments YC and VF cross at H (Y upper left, C lower right, F upper right, V lower left). Marked: arrows on YF and VC. Given: YF ∥ VC. Prove: YH/CH = FH/VH. Ladder: 1. YF ∥ VC — Given; 2. ? — Alternate interior angles theorem; 3. ∠YHF ≅ ∠CHV — Vertical angles theorem; 4. △YHF ~ △CHV — AA similarity postulate; 5. YH/CH = FH/VH — Definition of similar triangles. Y F C V H Not to scale. - ∠FYH ≅ ∠VCH
- YH/CH = FH/VH
- ∠FYH ≅ ∠YFH
- ∠FYH ≅ ∠CVH
Ren measures a cut HU across a sandwich half WQC, level with the edge QC. Which statement fills the blank?
Sketch, not to scale: triangle WQC with W at the top and base QC; H is on WQ, U is on WC, and segment HU is drawn. Marked: arrows on HU and QC; WH = 3, HQ = 5, WU = 9. Given: HU ∥ QC, WH = 3, HQ = 5 and WU = 9. Prove: UC = 15. Ladder: 1. HU ∥ QC — Given; 2. WH/HQ = WU/UC — Triangle proportionality theorem; 3. ? — Substitution property; 4. 3 · UC = 45 — Cross products property; 5. UC = 15 — Division property of equality. Sketch, not to scale: triangle WQC with W at the top and base QC; H is on WQ, U is on WC, and segment HU is drawn. Marked: arrows on HU and QC; WH = 3, HQ = 5, WU = 9. Given: HU ∥ QC, WH = 3, HQ = 5 and WU = 9. Prove: UC = 15. Ladder: 1. HU ∥ QC — Given; 2. WH/HQ = WU/UC — Triangle proportionality theorem; 3. ? — Substitution property; 4. 3 · UC = 45 — Cross products property; 5. UC = 15 — Division property of equality. Q C W H U 3 5 9 Not to scale - UC = 15
- 3/5 = UC/9
- 3/8 = 9/UC
- 3/5 = 9/UC
Use this
Given: CY ∥ QW. Prove: CV/WV = YV/QV. Ladder: 1. CY ∥ QW -- Given; 2. ∠YCV ≅ ∠QWV -- Alternate interior angles theorem; 3. ∠CVY ≅ ∠WVQ -- Vertical angles theorem; 4. triangle CVY ~ triangle WVQ -- AA similarity postulate; 5. ? -- Definition of similar triangles.
Tala crosses craft sticks CW and QY at V, with CY ∥ QW. Which statement fills the blank?
Sketch, not to scale: segments CW and QY cross at V (C upper left, W lower right, Y upper right, Q lower left). Marked: arrows on CY and QW. Given: CY ∥ QW. Prove: CV/WV = YV/QV. Ladder: 1. CY ∥ QW — Given; 2. ∠YCV ≅ ∠QWV — Alternate interior angles theorem; 3. ∠CVY ≅ ∠WVQ — Vertical angles theorem; 4. △CVY ~ △WVQ — AA similarity postulate; 5. ? — Definition of similar triangles. Sketch, not to scale: segments CW and QY cross at V (C upper left, W lower right, Y upper right, Q lower left). Marked: arrows on CY and QW. Given: CY ∥ QW. Prove: CV/WV = YV/QV. Ladder: 1. CY ∥ QW — Given; 2. ∠YCV ≅ ∠QWV — Alternate interior angles theorem; 3. ∠CVY ≅ ∠WVQ — Vertical angles theorem; 4. △CVY ~ △WVQ — AA similarity postulate; 5. ? — Definition of similar triangles. C Y Q W V Not to scale. - CV ≅ WV
- CV/WV = QV/YV
- CY/QW = CV/QV
- CV/WV = YV/QV
Zee draws scissors whose blades FS and HG cross at D, with FG ∥ HS. Which statement fills the blank?
Sketch, not to scale: segments FS and HG cross at D (F upper left, S lower right, G upper right, H lower left). Marked: arrows on FG and HS. Given: FG ∥ HS. Prove: FD/SD = GD/HD. Ladder: 1. FG ∥ HS — Given; 2. ∠GFD ≅ ∠HSD — Alternate interior angles theorem; 3. ∠FDG ≅ ∠SDH — Vertical angles theorem; 4. ? — AA similarity postulate; 5. FD/SD = GD/HD — Definition of similar triangles. Sketch, not to scale: segments FS and HG cross at D (F upper left, S lower right, G upper right, H lower left). Marked: arrows on FG and HS. Given: FG ∥ HS. Prove: FD/SD = GD/HD. Ladder: 1. FG ∥ HS — Given; 2. ∠GFD ≅ ∠HSD — Alternate interior angles theorem; 3. ∠FDG ≅ ∠SDH — Vertical angles theorem; 4. ? — AA similarity postulate; 5. FD/SD = GD/HD — Definition of similar triangles. Sketch, not to scale F S G H D Statement Reason 1. FG ∥ HS Given 2. ∠GFD ≅ ∠HSD Alternate interior angles theorem 3. ∠FDG ≅ ∠SDH Vertical angles theorem 4. ? AA similarity postulate 5. FD/SD = GD/HD Definition of similar triangles - △FDG ≅ △SDH
- △FDG ~ △FDH
- △FDG ~ △SDH
- △FDG ~ △HDS
Use this
Marked: arrows on VU and DQ. Given: VU ∥ DQ. Prove: VW/QW = UW/DW.
Ladder: 1. VU ∥ DQ -- Given; 2. ∠UVW ≅ ∠DQW -- Alternate interior angles theorem; 3. ∠VWU ≅ ∠QWD -- Vertical angles theorem; 4. ? -- AA similarity postulate; 5. VW/QW = UW/DW -- Definition of similar triangles.
Ari ties tent cords VQ and DU that cross at W, with VU ∥ DQ. Which statement fills the blank?
Sketch, not to scale: segments VQ and DU cross at W (V upper left, Q lower right, U upper right, D lower left). Marked: arrows on VU and DQ. Given: VU ∥ DQ. Prove: VW/QW = UW/DW. Ladder: 1. VU ∥ DQ — Given; 2. ∠UVW ≅ ∠DQW — Alternate interior angles theorem; 3. ∠VWU ≅ ∠QWD — Vertical angles theorem; 4. ? — AA similarity postulate; 5. VW/QW = UW/DW — Definition of similar triangles. Sketch, not to scale: segments VQ and DU cross at W (V upper left, Q lower right, U upper right, D lower left). Marked: arrows on VU and DQ. Given: VU ∥ DQ. Prove: VW/QW = UW/DW. Ladder: 1. VU ∥ DQ — Given; 2. ∠UVW ≅ ∠DQW — Alternate interior angles theorem; 3. ∠VWU ≅ ∠QWD — Vertical angles theorem; 4. ? — AA similarity postulate; 5. VW/QW = UW/DW — Definition of similar triangles. V U D Q W Not to scale. - △VWU ~ △VWD
- △VWU ~ △QWD
- △VWU ≅ △QWD
- △VWU ~ △DWQ