Similarity proofs: fill in the missing step or reason
Grade 10 Math Worksheet - Building Confidence

Circle the best answer.
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Marked: matching arcs at U and D. Given: ∠CUV ≅ ∠CDF and ∠UCV ≅ ∠DCF. Prove: triangle CUV ~ triangle CDF. Ladder: 1. ∠CUV ≅ ∠CDF and ∠UCV ≅ ∠DCF -- Given; 2. triangle CUV ~ triangle CDF -- ?.
Bo cuts a small triangle CUV off the tip of a pizza slice CDF. Which reason fills the blank?
- Given
- AA similarity postulate
- ASA
- SSS similarity theorem
Jun ties a cord CF across a tent front QDH, level with the floor DH. Which reason fills the blank?
Sketch, not to scale: triangle QDH with Q at the top and base DH; C is on QD, F is on QH, and segment CF is drawn. Marked: arrows on CF and DH. Given: CF ∥ DH. Prove: QC/CD = QF/FH. Ladder: 1. CF ∥ DH — Given; 2. QC/CD = QF/FH — ?. Sketch, not to scale: triangle QDH with Q at the top and base DH; C is on QD, F is on QH, and segment CF is drawn. Marked: arrows on CF and DH. Given: CF ∥ DH. Prove: QC/CD = QF/FH. Ladder: 1. CF ∥ DH — Given; 2. QC/CD = QF/FH — ?. D H Q C F Not to scale - Midsegment theorem
- Triangle proportionality theorem
- Converse of the triangle proportionality theorem
- Given
Luz paints a stripe VQ across a road sign HCS that cuts its sides in the same ratio. Which reason fills the blank?
Sketch, not to scale: triangle HCS with H at the top and base CS; V is on HC, Q is on HS, and segment VQ is drawn. Marked: no arrows. Given: HV/VC = HQ/QS. Prove: ∠HVQ ≅ ∠HCS. Ladder: 1. HV/VC = HQ/QS — Given; 2. VQ ∥ CS — ?; 3. ∠HVQ ≅ ∠HCS — Corresponding angles postulate. Sketch, not to scale: triangle HCS with H at the top and base CS; V is on HC, Q is on HS, and segment VQ is drawn. Marked: no arrows. Given: HV/VC = HQ/QS. Prove: ∠HVQ ≅ ∠HCS. Ladder: 1. HV/VC = HQ/QS — Given; 2. VQ ∥ CS — ?; 3. ∠HVQ ≅ ∠HCS — Corresponding angles postulate. C S H V Q Not to scale - Given
- Midsegment theorem
- Triangle proportionality theorem
- Converse of the triangle proportionality theorem
Milo draws a line DW across a pyramid face YFG that cuts its sides in the same ratio. Which reason fills the blank?
Sketch, not to scale: triangle YFG with Y at the top and base FG; D is on YF, W is on YG, and segment DW is drawn. Marked: no arrows. Given: YD/DF = YW/WG. Prove: ∠YDW ≅ ∠YFG. Ladder: 1. YD/DF = YW/WG — Given; 2. DW ∥ FG — ?; 3. ∠YDW ≅ ∠YFG — Corresponding angles postulate. Sketch, not to scale: triangle YFG with Y at the top and base FG; D is on YF, W is on YG, and segment DW is drawn. Marked: no arrows. Given: YD/DF = YW/WG. Prove: ∠YDW ≅ ∠YFG. Ladder: 1. YD/DF = YW/WG — Given; 2. DW ∥ FG — ?; 3. ∠YDW ≅ ∠YFG — Corresponding angles postulate. F G Y D W Not to scale - Triangle proportionality theorem
- Given
- Corresponding angles postulate
- Converse of the triangle proportionality theorem
Use this
Given: HU ∥ QC. Prove: triangle WHU ~ triangle WQC. Ladder: 1. HU ∥ QC -- Given; 2. ∠WHU ≅ ∠WQC -- Corresponding angles postulate; 3. ∠WUH ≅ ∠WCQ -- Corresponding angles postulate; 4. triangle WHU ~ triangle WQC -- ?.
Noah cuts a small triangle WHU off a sandwich half WQC, cutting level with the edge QC. Which reason fills the blank?
Sketch, not to scale: triangle WQC with W at the top and base QC; H is on WQ, U is on WC, and segment HU is drawn. Marked: arrows on HU and QC. Given: HU ∥ QC. Prove: △WHU ~ △WQC. Ladder: 1. HU ∥ QC — Given; 2. ∠WHU ≅ ∠WQC — Corresponding angles postulate; 3. ∠WUH ≅ ∠WCQ — Corresponding angles postulate; 4. △WHU ~ △WQC — ?. Sketch, not to scale: triangle WQC with W at the top and base QC; H is on WQ, U is on WC, and segment HU is drawn. Marked: arrows on HU and QC. Given: HU ∥ QC. Prove: △WHU ~ △WQC. Ladder: 1. HU ∥ QC — Given; 2. ∠WHU ≅ ∠WQC — Corresponding angles postulate; 3. ∠WUH ≅ ∠WCQ — Corresponding angles postulate; 4. △WHU ~ △WQC — ?. W Q C H U Not to scale. - SSS similarity theorem
- AA similarity postulate
- Given
- ASA
Use this
Given: YG ∥ SV. Prove: triangle DYG ~ triangle DSV. Ladder: 1. YG ∥ SV -- Given; 2. ∠DYG ≅ ∠DSV -- Corresponding angles postulate; 3. ∠DGY ≅ ∠DVS -- Corresponding angles postulate; 4. triangle DYG ~ triangle DSV -- ?.
Pia cuts a small triangle DYG off a pizza slice DSV, cutting level with the crust SV. Which reason fills the blank?
Sketch, not to scale: triangle DSV with D at the top and base SV; Y is on DS, G is on DV, and segment YG is drawn. Marked: arrows on YG and SV. Given: YG ∥ SV. Prove: △DYG ~ △DSV. Ladder: 1. YG ∥ SV — Given; 2. ∠DYG ≅ ∠DSV — Corresponding angles postulate; 3. ∠DGY ≅ ∠DVS — Corresponding angles postulate; 4. △DYG ~ △DSV — ?. Sketch, not to scale: triangle DSV with D at the top and base SV; Y is on DS, G is on DV, and segment YG is drawn. Marked: arrows on YG and SV. Given: YG ∥ SV. Prove: △DYG ~ △DSV. Ladder: 1. YG ∥ SV — Given; 2. ∠DYG ≅ ∠DSV — Corresponding angles postulate; 3. ∠DGY ≅ ∠DVS — Corresponding angles postulate; 4. △DYG ~ △DSV — ?. Sketch, not to scale D S V Y G - Given
- Triangle proportionality theorem
- AAS
- AA similarity postulate
Ren ties a cord UV across a tent front CDF, level with the floor DF. Which statement fills the blank?
Sketch, not to scale: triangle CDF with C at the top and base DF; U is on CD, V is on CF, and segment UV is drawn. Marked: arrows on UV and DF. Given: UV ∥ DF. Prove: △CUV ~ △CDF. Ladder: 1. UV ∥ DF — Given; 2. ? — Corresponding angles postulate; 3. ∠CVU ≅ ∠CFD — Corresponding angles postulate; 4. △CUV ~ △CDF — AA similarity postulate. Sketch, not to scale: triangle CDF with C at the top and base DF; U is on CD, V is on CF, and segment UV is drawn. Marked: arrows on UV and DF. Given: UV ∥ DF. Prove: △CUV ~ △CDF. Ladder: 1. UV ∥ DF — Given; 2. ? — Corresponding angles postulate; 3. ∠CVU ≅ ∠CFD — Corresponding angles postulate; 4. △CUV ~ △CDF — AA similarity postulate. C D F U V Given: UV ∥ DF. Prove: triangle CUV ~ triangle CDF. 1. UV ∥ DF -- Given; 2. ? -- Corresponding angles postulate; 3. ∠CVU ≅ ∠CFD -- Corresponding angles postulate; 4. triangle CUV ~ triangle CDF -- AA similarity postulate. Not to scale. - ∠CUV ≅ ∠CDF
- ∠CUV ≅ ∠CFD
- ∠CUV ≅ ∠UVC
- △CUV ~ △CDF
Use this
Given: GH ∥ WY. Prove: triangle SGH ~ triangle SWY. Ladder: 1. GH ∥ WY -- Given; 2. ∠SGH ≅ ∠SWY -- Corresponding angles postulate; 3. ? -- Corresponding angles postulate; 4. triangle SGH ~ triangle SWY -- AA similarity postulate.
Tala sews a seam GH across a sail SWY, level with the bottom edge WY. Which statement fills the blank?
Sketch, not to scale: triangle SWY with S at the top and base WY; G is on SW, H is on SY, and segment GH is drawn. Marked: arrows on GH and WY. Given: GH ∥ WY. Prove: △SGH ~ △SWY. Ladder: 1. GH ∥ WY — Given; 2. ∠SGH ≅ ∠SWY — Corresponding angles postulate; 3. ? — Corresponding angles postulate; 4. △SGH ~ △SWY — AA similarity postulate. Sketch, not to scale: triangle SWY with S at the top and base WY; G is on SW, H is on SY, and segment GH is drawn. Marked: arrows on GH and WY. Given: GH ∥ WY. Prove: △SGH ~ △SWY. Ladder: 1. GH ∥ WY — Given; 2. ∠SGH ≅ ∠SWY — Corresponding angles postulate; 3. ? — Corresponding angles postulate; 4. △SGH ~ △SWY — AA similarity postulate. S W Y G H Not to scale. - △SGH ~ △SWY
- ∠SHG ≅ ∠GSH
- ∠SHG ≅ ∠SWY
- ∠SHG ≅ ∠SYW
Zee draws a beam CF across a roof QDH, level with the base DH. Which statement fills the blank?
Sketch, not to scale: triangle QDH with Q at the top and base DH; C is on QD, F is on QH, and segment CF is drawn. Marked: arrows on CF and DH. Given: CF ∥ DH. Prove: QC · FH = CD · QF. Ladder: 1. CF ∥ DH — Given; 2. ? — Triangle proportionality theorem; 3. QC · FH = CD · QF — Cross products property. Sketch, not to scale: triangle QDH with Q at the top and base DH; C is on QD, F is on QH, and segment CF is drawn. Marked: arrows on CF and DH. Given: CF ∥ DH. Prove: QC · FH = CD · QF. Ladder: 1. CF ∥ DH — Given; 2. ? — Triangle proportionality theorem; 3. QC · FH = CD · QF — Cross products property. D H Q C F Not to scale - QC · FH = CD · QF
- QC/CD = QF/FH
- QC/QD = CF/FH
- QC/CD = HF/QF
Ari paints a stripe SY across a road sign GUW, level with the base UW. Which statement fills the blank?
Sketch, not to scale: triangle GUW with G at the top and base UW; S is on GU, Y is on GW, and segment SY is drawn. Marked: arrows on SY and UW. Given: SY ∥ UW. Prove: GS · YW = SU · GY. Ladder: 1. SY ∥ UW — Given; 2. ? — Triangle proportionality theorem; 3. GS · YW = SU · GY — Cross products property. Sketch, not to scale: triangle GUW with G at the top and base UW; S is on GU, Y is on GW, and segment SY is drawn. Marked: arrows on SY and UW. Given: SY ∥ UW. Prove: GS · YW = SU · GY. Ladder: 1. SY ∥ UW — Given; 2. ? — Triangle proportionality theorem; 3. GS · YW = SU · GY — Cross products property. U W G S Y Not to scale - GS · YW = SU · GY
- GS/SU = GY/YW
- GS/SU = YW/GY
- GS/GU = SY/YW