Use congruent triangles to find missing sides and angles
Grade 10 Math Worksheet - Building Confidence

Circle the best answer.
Ari wants to say ∠B = ∠E for the two triangles on the card. Which justification works?
- CPCTC alone: the three side pairs match, so the angle pairs match
- SSS proves △ABC ≅ △DEF, then ∠B = ∠E by CPCTC
- Nothing yet: no pair of angles is marked equal
- ∠B and ∠E look the same size in the picture
Esme says BC = EF because all three angle pairs match. Which reply is right?
Triangles ABC and DEF, not to scale. ∠A = ∠D, ∠B = ∠E and ∠C = ∠F are marked. No sides are marked. Triangles ABC and DEF, not to scale. ∠A = ∠D, ∠B = ∠E and ∠C = ∠F are marked. No sides are marked. not to scale A B C D E F - Proved: matching angles are corresponding parts, so BC = EF by CPCTC
- Not proved: equal angles only make similar triangles
- Proved if both triangles are drawn the same size
- Proved: AAA is a congruence rule, so BC = EF by CPCTC
Jun wants to say AB = CB. Which justification works?
Triangles ABD and CBD share side BD. Ticks show AD = CD and ∠ADB = ∠CDB. Triangles ABD and CBD share side BD. Ticks show AD = CD and ∠ADB = ∠CDB. A B C D - Not enough: one pair of sides is marked equal
- BD = BD (shared); SAS gives △ABD ≅ △CBD, so AB = CB
- ASA gives △ABD ≅ △CBD, so AB = CB by CPCTC
- ∠ADB = ∠CDB, so the sides opposite are equal by CPCTC
Luz needs the reason for line 4 of a proof. Which reason is right?
Lines AB and CD cross at M. Line 4 of a proof says ∠AMC = ∠BMD. Lines AB and CD cross at M. Line 4 of a proof says ∠AMC = ∠BMD. ∠AMC ∠BMD A M B C D Lines AB and CD cross at M. Line 4 of a proof says ∠AMC = ∠BMD. - Vertical angles are equal
- Linear pair: the two angles add up to 180°
- CPCTC: the angles are corresponding parts
- Given: the picture shows them equal
Milo needs the reason for line 2 of a proof. Which reason is right?
Triangles ABD and CBD share side BD. Line 2 of a proof says BD = BD. Triangles ABD and CBD share side BD. Line 2 of a proof says BD = BD. A B C D Triangles ABD and CBD share side BD. Line 2 of a proof says BD = BD. - Definition of midpoint: B is halfway along AC
- Given: two tick marks show they are equal
- CPCTC: the sides are corresponding parts
- Reflexive property: a segment equals itself
A proof has shown triangle ABC ≅ triangle DEF by SAS. The next line says ∠C = ∠F. Noah needs the reason for the next line after proving a congruence. Which reason is right?
A proof has shown △ABC ≅ △DEF by SAS. The next line says ∠C = ∠F. A proof has shown △ABC ≅ △DEF by SAS. The next line says ∠C = ∠F. A B C D E F Not to scale. - CPCTC: corresponding parts of congruent triangles are congruent
- Given: the angles are marked in the picture
- Vertical angles are equal
- SAS: the rule that was just used to show the triangles congruent
not to scale. Pia wants to prove △ABC ≅ △DEF by SAS. Which one more fact is needed?
Triangles ABC and DEF, not to scale. AB = DE and ∠A = ∠D are marked. Triangles ABC and DEF, not to scale. AB = DE and ∠A = ∠D are marked. A B C D E F - AC = EF, which pairs the wrong sides
- AC = DF, next to the marked angle
- BC = EF, which makes SSA, not a rule
- ∠B = ∠E, which makes ASA, not SAS
Ren wants to prove △PQR ≅ △XYZ by ASA. Which one more fact is needed?
Triangles PQR and XYZ, not to scale. ∠P = ∠X and ∠Q = ∠Y are marked. Triangles PQR and XYZ, not to scale. ∠P = ∠X and ∠Q = ∠Y are marked. P Q R X Y Z - PQ = XY, between the two marked angles
- PR = XZ, which makes AAS, not ASA
- PQ = XZ, which pairs the wrong sides
- ∠R = ∠Z, because three angles are enough
Triangles ABC and DEF, not to scale. Tala wants to prove △ABC ≅ △DEF by SSS. Which one more fact is needed?
Triangles ABC and DEF, not to scale. AB = DE and BC = EF are marked. Triangles ABC and DEF, not to scale. AB = DE and BC = EF are marked. A B C D E F - ∠B = ∠E, which makes SAS, not SSS
- AC = DF
- ∠A = ∠D, which makes SSA, not a rule
- AC = DE, which pairs the wrong sides
Zee wants to prove △ABC ≅ △DEF by HL. Which one more fact is needed?
Right triangles ABC and DEF with right angles at C and F. The hypotenuses are marked equal, AB = DE. Right triangles ABC and DEF with right angles at C and F. The hypotenuses are marked equal, AB = DE. A B C AB = DE D E F - AC = DF, a pair of legs
- ∠C = ∠F, the right angles
- BC = DE, a leg and a hypotenuse
- ∠A = ∠D, which makes AAS, not HL