Use congruent triangles to find missing sides and angles
Grade 10 Math Worksheet - Building Confidence

Circle the best answer.
Bo wants to say AC = DF from the card. Which statement is right?
- AC = DF, since the triangles look the same size
- SSA gives △ABC ≅ △DEF, so AC = DF follows by CPCTC
- AC = DF is not proved: SSA is not a congruence rule
- Two sides and an angle match, so AC = DF by CPCTC
Esme says BC = EF because all three angle pairs match. Which reply is right?
Triangles ABC and DEF, not to scale. ∠A = ∠D, ∠B = ∠E and ∠C = ∠F are marked. No sides are marked. Triangles ABC and DEF, not to scale. ∠A = ∠D, ∠B = ∠E and ∠C = ∠F are marked. No sides are marked. not to scale A B C D E F - Not proved: equal angles only make similar triangles
- Proved if both triangles are drawn the same size
- Proved: AAA is a congruence rule, so BC = EF by CPCTC
- Proved: matching angles are corresponding parts, so BC = EF by CPCTC
Jun wants to say AB = CB. Which justification works?
Triangles ABD and CBD share side BD. Ticks show AD = CD and ∠ADB = ∠CDB. Triangles ABD and CBD share side BD. Ticks show AD = CD and ∠ADB = ∠CDB. A B C D - BD = BD (shared); SAS gives △ABD ≅ △CBD, so AB = CB
- ∠ADB = ∠CDB, so the sides opposite are equal by CPCTC
- Not enough: one pair of sides is marked equal
- ASA gives △ABD ≅ △CBD, so AB = CB by CPCTC
Kira needs the reason for line 3 of a proof. Which reason is right?
Segment AB with midpoint M. Line 3 of a proof says AM = MB. Segment AB with midpoint M. Line 3 of a proof says AM = MB. A M B Segment AB with midpoint M. Line 3 of a proof says AM = MB. - Reflexive property: a segment equals itself
- CPCTC: the two segments are corresponding parts
- Given: the picture shows M in the middle
- Definition of midpoint: M splits AB in half
Luz needs the reason for line 4 of a proof. Which reason is right?
Lines AB and CD cross at M. Line 4 of a proof says ∠AMC = ∠BMD. Lines AB and CD cross at M. Line 4 of a proof says ∠AMC = ∠BMD. ∠AMC ∠BMD A M B C D Lines AB and CD cross at M. Line 4 of a proof says ∠AMC = ∠BMD. - Given: the picture shows them equal
- Vertical angles are equal
- CPCTC: the angles are corresponding parts
- Linear pair: the two angles add up to 180°
Milo needs the reason for line 2 of a proof. Which reason is right?
Triangles ABD and CBD share side BD. Line 2 of a proof says BD = BD. Triangles ABD and CBD share side BD. Line 2 of a proof says BD = BD. A B C D Triangles ABD and CBD share side BD. Line 2 of a proof says BD = BD. - CPCTC: the sides are corresponding parts
- Given: two tick marks show they are equal
- Reflexive property: a segment equals itself
- Definition of midpoint: B is halfway along AC
A proof has shown triangle ABC ≅ triangle DEF by SAS. The next line says ∠C = ∠F. Noah needs the reason for the next line after proving a congruence. Which reason is right?
A proof has shown △ABC ≅ △DEF by SAS. The next line says ∠C = ∠F. A proof has shown △ABC ≅ △DEF by SAS. The next line says ∠C = ∠F. A B C D E F Not to scale. - SAS: the rule that was just used to show the triangles congruent
- Given: the angles are marked in the picture
- Vertical angles are equal
- CPCTC: corresponding parts of congruent triangles are congruent
not to scale. Pia wants to prove △ABC ≅ △DEF by SAS. Which one more fact is needed?
Triangles ABC and DEF, not to scale. AB = DE and ∠A = ∠D are marked. Triangles ABC and DEF, not to scale. AB = DE and ∠A = ∠D are marked. A B C D E F - BC = EF, which makes SSA, not a rule
- AC = DF, next to the marked angle
- AC = EF, which pairs the wrong sides
- ∠B = ∠E, which makes ASA, not SAS
Ren wants to prove △PQR ≅ △XYZ by ASA. Which one more fact is needed?
Triangles PQR and XYZ, not to scale. ∠P = ∠X and ∠Q = ∠Y are marked. Triangles PQR and XYZ, not to scale. ∠P = ∠X and ∠Q = ∠Y are marked. P Q R X Y Z - ∠R = ∠Z, because three angles are enough
- PQ = XZ, which pairs the wrong sides
- PQ = XY, between the two marked angles
- PR = XZ, which makes AAS, not ASA
Zee wants to prove △ABC ≅ △DEF by HL. Which one more fact is needed?
Right triangles ABC and DEF with right angles at C and F. The hypotenuses are marked equal, AB = DE. Right triangles ABC and DEF with right angles at C and F. The hypotenuses are marked equal, AB = DE. A B C AB = DE D E F - AC = DF, a pair of legs
- ∠A = ∠D, which makes AAS, not HL
- ∠C = ∠F, the right angles
- BC = DE, a leg and a hypotenuse