Use congruent triangles to find missing sides and angles
Grade 10 Math Worksheet - Building Confidence

Circle the best answer.
Ari wants to say ∠B = ∠E for the two triangles on the card. Which justification works?
- SSS proves △ABC ≅ △DEF, then ∠B = ∠E by CPCTC
- ∠B and ∠E look the same size in the picture
- CPCTC alone: the three side pairs match, so the angle pairs match
- Nothing yet: no pair of angles is marked equal
Bo wants to say AC = DF from the card. Which statement is right?
Triangles ABC and DEF, not to scale. Ticks show AB = DE and BC = EF. One angle pair, ∠A = ∠D, is marked; ∠A is not between the marked sides. Triangles ABC and DEF, not to scale. Ticks show AB = DE and BC = EF. One angle pair, ∠A = ∠D, is marked; ∠A is not between the marked sides. A B C D E F Triangles ABC and DEF, not to scale. Ticks show AB = DE and BC = EF. One angle pair, ∠A = ∠D, is marked; ∠A is not between the marked sides. - AC = DF is not proved: SSA is not a congruence rule
- SSA gives △ABC ≅ △DEF, so AC = DF follows by CPCTC
- AC = DF, since the triangles look the same size
- Two sides and an angle match, so AC = DF by CPCTC
Esme says BC = EF because all three angle pairs match. Which reply is right?
Triangles ABC and DEF, not to scale. ∠A = ∠D, ∠B = ∠E and ∠C = ∠F are marked. No sides are marked. Triangles ABC and DEF, not to scale. ∠A = ∠D, ∠B = ∠E and ∠C = ∠F are marked. No sides are marked. not to scale A B C D E F - Not proved: equal angles only make similar triangles
- Proved if both triangles are drawn the same size
- Proved: matching angles are corresponding parts, so BC = EF by CPCTC
- Proved: AAA is a congruence rule, so BC = EF by CPCTC
Jun wants to say AB = CB. Which justification works?
Triangles ABD and CBD share side BD. Ticks show AD = CD and ∠ADB = ∠CDB. Triangles ABD and CBD share side BD. Ticks show AD = CD and ∠ADB = ∠CDB. A B C D - ∠ADB = ∠CDB, so the sides opposite are equal by CPCTC
- Not enough: one pair of sides is marked equal
- BD = BD (shared); SAS gives △ABD ≅ △CBD, so AB = CB
- ASA gives △ABD ≅ △CBD, so AB = CB by CPCTC
Kira needs the reason for line 3 of a proof. Which reason is right?
Segment AB with midpoint M. Line 3 of a proof says AM = MB. Segment AB with midpoint M. Line 3 of a proof says AM = MB. A M B Segment AB with midpoint M. Line 3 of a proof says AM = MB. - Reflexive property: a segment equals itself
- Given: the picture shows M in the middle
- Definition of midpoint: M splits AB in half
- CPCTC: the two segments are corresponding parts
A proof has shown triangle ABC ≅ triangle DEF by SAS. The next line says ∠C = ∠F. Noah needs the reason for the next line after proving a congruence. Which reason is right?
A proof has shown △ABC ≅ △DEF by SAS. The next line says ∠C = ∠F. A proof has shown △ABC ≅ △DEF by SAS. The next line says ∠C = ∠F. A B C D E F Not to scale. - Given: the angles are marked in the picture
- SAS: the rule that was just used to show the triangles congruent
- CPCTC: corresponding parts of congruent triangles are congruent
- Vertical angles are equal
not to scale. Pia wants to prove △ABC ≅ △DEF by SAS. Which one more fact is needed?
Triangles ABC and DEF, not to scale. AB = DE and ∠A = ∠D are marked. Triangles ABC and DEF, not to scale. AB = DE and ∠A = ∠D are marked. A B C D E F - AC = DF, next to the marked angle
- BC = EF, which makes SSA, not a rule
- AC = EF, which pairs the wrong sides
- ∠B = ∠E, which makes ASA, not SAS
Ren wants to prove △PQR ≅ △XYZ by ASA. Which one more fact is needed?
Triangles PQR and XYZ, not to scale. ∠P = ∠X and ∠Q = ∠Y are marked. Triangles PQR and XYZ, not to scale. ∠P = ∠X and ∠Q = ∠Y are marked. P Q R X Y Z - PR = XZ, which makes AAS, not ASA
- ∠R = ∠Z, because three angles are enough
- PQ = XY, between the two marked angles
- PQ = XZ, which pairs the wrong sides
Triangles ABC and DEF, not to scale. Tala wants to prove △ABC ≅ △DEF by SSS. Which one more fact is needed?
Triangles ABC and DEF, not to scale. AB = DE and BC = EF are marked. Triangles ABC and DEF, not to scale. AB = DE and BC = EF are marked. A B C D E F - ∠A = ∠D, which makes SSA, not a rule
- AC = DF
- ∠B = ∠E, which makes SAS, not SSS
- AC = DE, which pairs the wrong sides
Zee wants to prove △ABC ≅ △DEF by HL. Which one more fact is needed?
Right triangles ABC and DEF with right angles at C and F. The hypotenuses are marked equal, AB = DE. Right triangles ABC and DEF with right angles at C and F. The hypotenuses are marked equal, AB = DE. A B C AB = DE D E F - AC = DF, a pair of legs
- ∠A = ∠D, which makes AAS, not HL
- ∠C = ∠F, the right angles
- BC = DE, a leg and a hypotenuse