Volume of combined solids
Grade 10 Math Worksheet

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Sketch, not to scale.
Ari finds a bucket's volume (radii 6 and 3 cm, height 8 cm) as a big cone minus a small cone, using 1/2 = h/(h + 8). What licenses that ratio?
- The parallel cut makes the cones similar, so heights match radii
- The two cones have the same height, so their height ratio is 1 and nothing is left to find
- The bucket looks like a cone with straight sides, so the ratio holds by eye alone
- The bucket's average radius, 4.5, gives the small cone's height after a rescale
A cone is 12 cm tall with radius 6 cm. Bo cuts off the top 4 cm parallel to the base and says the top cone is 1/27 of the whole. What licenses 1/27?
A cone 12 cm tall with base radius 6 cm. A flat cut parallel to the base removes the top 4 cm as a smaller cone. Sketch, not to scale. A cone 12 cm tall with base radius 6 cm. A flat cut parallel to the base removes the top 4 cm as a smaller cone. Sketch, not to scale. top 4 cm 12 cm base radius 6 cm - The top looks small on the page, about one tenth of the whole cone by eye
- The top cone's base area is 1/9 of the whole, so its volume is also 1/9 of it
- The top cone is similar with scale 1/3, so its volume is 1/3 of the whole cone
- It is similar with scale 1/3, so volume scales by (1/3)³
A cone and a square pyramid both have base area 30 cm² and height 12 cm. Esme wants to show equal volumes without using volume formulas. Which argument works?
A cone and a square pyramid, each with base area 30 cm² and height 12 cm. Sketch, not to scale. A cone and a square pyramid, each with base area 30 cm² and height 12 cm. Sketch, not to scale. A cone and a square pyramid, each with base area 30 cm² and height 12 cm Not to scale. - Equal slice areas at every height, so Cavalieri gives equal volumes
- Both come to a point at the top, so their volumes must be equal by that shape
- Both have the same slant height, so their volumes are equal because slant decides
- Both have base area 30, and the base area alone decides the volume of a solid
A rock is lowered into a cylinder 10 cm across. The water level rises 2 cm. Sketch, not to scale. A rock sinks into a cylinder 10 cm across and the water rises 2 cm. Jun says the rock's volume is the base area times the rise. What licenses that?
A rock is lowered into a cylinder 10 cm across. The water level rises 2 cm. Sketch, not to scale. A rock is lowered into a cylinder 10 cm across. The water level rises 2 cm. Sketch, not to scale. 10 cm across 2 cm - The rock's volume equals one third of the base area times the rise, as for a cone
- The rock's volume equals the area of a circle 10 cm in radius times the rise
- The rock's volume equals the base area times the new depth of the water
- It pushes aside equal water: the tank's base times the rise
Kira says a bucket with radii 6 and 3 cm and height 8 cm has the same volume as a can of average radius 4.5 cm and height 8 cm. Which reply is right?
A bucket (a cone with its tip cut off) with radii 6 cm and 3 cm and height 8 cm, and a can with radius 4.5 cm and height 8 cm. Sketch, not to scale. A bucket (a cone with its tip cut off) with radii 6 cm and 3 cm and height 8 cm, and a can with radius 4.5 cm and height 8 cm. Sketch, not to scale. Sketch, not to scale bucket 3 cm 6 cm 8 cm can 4.5 cm 8 cm - Yes: both have straight sides and the same height, so they hold the same
- Yes: the halfway radius gives the halfway volume of the two cones
- No: the can is 192π, the volume of the big cone alone, and the bucket is less
- No: the bucket is 168π and the can is 162π, since volume follows r²
Luz says doubling every length of a cone doubles its volume. Which reply is right?
A cone, and a second cone with every length doubled. Sketch, not to scale. A cone, and a second cone with every length doubled. Sketch, not to scale. A cone, and a second cone with every length doubled Not to scale. - No: it becomes 4 times as large, like the base area
- No: it becomes 6 times as large, from 3 × 2
- Yes: each length doubled, so the volume doubles
- No: volume scales with the cube, so 8 times as large
Noah says a ball of radius 3 cm is exactly two thirds of the snug cylinder around it (radius 3, height 6). Which reply is right?
A ball of radius 3 cm fits snugly inside a cylinder of radius 3 cm and height 6 cm. Sketch, not to scale. A ball of radius 3 cm fits snugly inside a cylinder of radius 3 cm and height 6 cm. Sketch, not to scale. 3 cm ball 6 cm 3 cm cylinder Not to scale. - No: the ball is one third of the cylinder, like a cone in its can, so less
- Yes: the ball is half the cylinder, which looks right
- Yes: the ball is 36π, the cylinder is 54π, and 36π/54π = 2/3
- No: the ball is π/4 of the cylinder, like a circle in a square, so under 80%
Pia finds a pyramid's volume (base 6 cm square, slant height 5 cm): Line 1: height = 5 − 3 = 2. Line 2: volume = (1/3)(36)(2) = 24. Which line is wrong?
A square pyramid with base 6 cm on a side and slant height 5 cm, measured from the base edge's midpoint to the apex. Sketch, not to scale. A square pyramid with base 6 cm on a side and slant height 5 cm, measured from the base edge's midpoint to the apex. Sketch, not to scale. 5 cm 6 cm slant height 5 cm, measured from the base edge's midpoint to the apex Not to scale. - Neither line is wrong; just the units are missing from the final answer
- Line 2: the pyramid formula has no one third, so the volume is 72
- Line 2: the base area should be 6 × 3 = 18, using half of one side
- Line 1: the height is √(5² − 3²) = 4 by Pythagoras, not 5 − 3
Ren finds a silo's volume (cylinder radius 3 m, height 10 m, half-ball top): Line 1: cylinder 90π. Line 2: half-ball (4/3)π·27 = 36π. Line 3: total 126π. Which line is wrong?
A silo: a cylinder 6 m across and 10 m tall with a half-ball of the same width on top. Sketch, not to scale. A silo: a cylinder 6 m across and 10 m tall with a half-ball of the same width on top. Sketch, not to scale. A silo 10 m 6 m 6 m a cylinder 6 m across and 10 m tall with a half-ball of the same width on top Not to scale. - No line is wrong; just the units are missing from the total
- Line 3: add another 36π for a second half-ball at the bottom of the silo
- Line 2: a half-ball is half a ball, (2/3)π·27 = 18π
- Line 1: the cylinder should use radius 6 because the silo is 6 m across
Zee finds a cone's height (radius 5 cm, volume 100π cm³): Line 1: (1/3)π·25·h = 100π. Line 2: 25h = 100. Line 3: h = 4. Which line is wrong?
A cone with base radius 5 cm and volume 100π cm³. Sketch, not to scale. A cone with base radius 5 cm and volume 100π cm³. Sketch, not to scale. A cone with base radius 5 cm and volume 100pi cm³ 5 cm Not to scale. - Line 3: divide 25h = 100 by 25π, because the π was not removed
- Line 1: the cone formula has no one third, so the equation is wrong from the start
- Line 1: the radius should be 10 cm, as the cone base is wide
- Line 2: times 3 gives 25h = 300, so h = 300 ÷ 25 = 12