Competition, predators and prey, and partnerships

Grade 7 Science Worksheet

NameDate

Circle the best answer.

  1. Read this first

    Table (model data)

    Percent of the plot covered. Week 1: Grass A 40, Grass B 10. Week 2: A 35, B 25. Week 3: A 25, B 40. Week 4: A 15, B 55.

  2. Ari measures how much of a plot two grasses cover. Which interaction does the pattern fit, and why?

    • Mutualism, because both grasses are growing in the same plot over the weeks of the study.
    • Competition, because as Grass B gained cover, Grass A lost cover from the same plot.
    • Commensalism, because Grass A is not changed while Grass B gains more and more cover.
    • Parasitism, because Grass B is living on Grass A and taking things from it as it grows.
  3. Table (model data)

    Plants and bees per hectare. Year 1: 20 plants, 8 bees. Year 2: 28 plants, 12 bees. Year 3: 40 plants, 20 bees. Year 4: 55 plants, 30 bees.

  4. Bo counts flowering plants and bees in a meadow for four years. Which interaction does the pattern fit best?

    • Competition, because the plants and the bees are both using the same meadow.
    • Mutualism, because both populations rose together over the four years.
    • Parasitism, because the bees rose while the plants were being used up.
    • Commensalism, because the plants gain while the bees stay the same.
  5. Table (model data)

    30 oaks in each group. Oaks with ferns on branches: yearly growth 21 cm. Oaks without ferns: yearly growth 21 cm. Ferns found on bare rock: 4 per 20 ledges.

  6. Jun compares oaks with and without ferns on their branches. What does the table best support?

    • Ferns gain a place to grow while oak growth is the same, which fits commensalism.
    • Ferns harm the oaks, since the oaks have ferns growing along their branches throughout the year.
    • Ferns and oaks compete, since both are plants living in the same woods near each other.
    • Ferns help the oaks grow, since the oaks with ferns grew just as well as the others.
  7. Bean plant height after 6 weeks. Plots with root bacteria: 30 cm. Plots without root bacteria: 12 cm. Bean plants grow with bacteria in their roots that give them nitrogen. Luz removes the bacteria from one plot. What will most likely happen to the beans there?

    • They should grow more, since the roots will have more room for water.
    • They should grow the same, since roots do not need help from other living things.
    • They should grow more, since the bacteria were taking nitrogen from the beans.
    • They should grow less, since they lose the nitrogen the bacteria gave them.
  8. Table (model data)

    Kind A plants per bed. Week 1: 40. Week 2: 36. Week 3: 32. Kind B plants per bed rose from 10 to 30 in those same weeks.

  9. Kind A and Kind B share a bed and use the same resources. Milo pulls out Kind B after week 3. What will the Kind A line most likely do?

    • Kind A should stay at 32 plants, since plant counts stop changing after the third week.
    • Kind A should keep falling at the same speed, since Kind B had no effect on Kind A to begin with.
    • Kind A should fall faster, since Kind B was helping Kind A grow and is now gone from the bed.
    • Kind A should stop falling and start to rise, since it no longer shares resources with Kind B.
  10. Year 1: 2 clumps, oak growth 20 cm. Year 3: 4 clumps, 17 cm. Year 5: 7 clumps, 13 cm. Noah tracks an oak and its mistletoe. If the clumps keep rising to 10 by year 7, what will the oak's yearly growth most likely be?

    • Lower than 13 cm, since more mistletoe takes more water and minerals from the oak.
    • Back near 20 cm, since trees recover when more mistletoe grows on them over the years.
    • Exactly 13 cm, since growth stays at the last measured value however many clumps grow.
    • Higher than 13 cm, since more clumps share the load of taking water and minerals from the oak.
  11. Table (model data)

    Lettuce leaf area. Plot A: week 1: 8, week 2: 14, week 3: 18, week 4: 26, week 5: 34. Plot B: week 1: 8, week 2: 14, week 3: 18, week 4: 19, week 5: 17. Same sun and watering.

  12. Pia compares two lettuce plots. Weeds were pulled from Plot A in week 3 but left in Plot B. What does the difference show?

    • Lettuce grew more where the weeds were left, so the weeds were helping the lettuce along.
    • Lettuce grew more where the weeds were pulled, so the weeds were competing with the lettuce.
    • Plot A got more sun than Plot B, so the sun explains why Plot A grew more than Plot B did.
    • The plots were the same until week 5, so the weeds made no difference to the lettuce at the end.
  13. Table (model data)

    Seedling height after 8 weeks in three pots each. With the fungus: 14, 16, 15 cm. Without the fungus: 7, 9, 8 cm. Same soil, water and light.

  14. Ren grows pine seedlings with and without a root fungus. What do the pot results best show?

    • The seedlings with the fungus grew taller in each pot, so the fungus may help the seedlings.
    • The pots differ in some ways, so the fungus could not have changed the height of the seedlings.
    • The seedlings without the fungus grew taller in each pot, so the fungus harmed the seedlings.
    • The fungus makes the soil warmer, which is why the seedlings with it grew taller than the others.
  15. Table (model data)

    Average mass of one plant after 6 weeks. 1 seed per pot: 12 g. 2 seeds per pot: 9 g. 4 seeds per pot: 5 g. Same soil, water and light in every pot.

  16. Tala grows beans in pots with different numbers of seeds. What does the table best show?

    • Pots with more seeds got more light, which explains the mass of each plant in the pots.
    • Each plant grew larger as more seeds shared a pot, which fits a partnership among the plants.
    • The pots show no pattern, since the mass of one plant changed in each of the pots.
    • Each plant grew smaller as more seeds shared a pot, which fits crowding and competition.
  17. Table (model data)

    Host growth over 4 weeks. Hosts with dodder: 9 cm. Hosts without dodder: 15 cm. Dodder cannot grow without a host.

  18. Zee compares host plants with and without dodder, a plant that wraps around its host and takes water from it. What does the table show?

    • The hosts with dodder grew less, so the dodder gains from the host while the host loses.
    • The hosts with dodder grew the same, since both groups were measured over the same 4 weeks.
    • The hosts with dodder grew less, so the host gains from the dodder and the dodder loses.
    • The hosts with dodder grew less, so the dodder and the host are partners that both gain.
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Competition, predators and prey, and partnerships

Answer Key - Grade 7 Science Worksheet

Circle the best answer.

  1. Read this first

    Table (model data)

    Percent of the plot covered. Week 1: Grass A 40, Grass B 10. Week 2: A 35, B 25. Week 3: A 25, B 40. Week 4: A 15, B 55.

  2. Ari measures how much of a plot two grasses cover. Which interaction does the pattern fit, and why?

    • Mutualism, because both grasses are growing in the same plot over the weeks of the study.
    • Competition, because as Grass B gained cover, Grass A lost cover from the same plot.
    • Commensalism, because Grass A is not changed while Grass B gains more and more cover.
    • Parasitism, because Grass B is living on Grass A and taking things from it as it grows.
  3. Table (model data)

    Plants and bees per hectare. Year 1: 20 plants, 8 bees. Year 2: 28 plants, 12 bees. Year 3: 40 plants, 20 bees. Year 4: 55 plants, 30 bees.

  4. Bo counts flowering plants and bees in a meadow for four years. Which interaction does the pattern fit best?

    • Competition, because the plants and the bees are both using the same meadow.
    • Mutualism, because both populations rose together over the four years.
    • Parasitism, because the bees rose while the plants were being used up.
    • Commensalism, because the plants gain while the bees stay the same.
  5. Table (model data)

    30 oaks in each group. Oaks with ferns on branches: yearly growth 21 cm. Oaks without ferns: yearly growth 21 cm. Ferns found on bare rock: 4 per 20 ledges.

  6. Jun compares oaks with and without ferns on their branches. What does the table best support?

    • Ferns gain a place to grow while oak growth is the same, which fits commensalism.
    • Ferns harm the oaks, since the oaks have ferns growing along their branches throughout the year.
    • Ferns and oaks compete, since both are plants living in the same woods near each other.
    • Ferns help the oaks grow, since the oaks with ferns grew just as well as the others.
  7. Bean plant height after 6 weeks. Plots with root bacteria: 30 cm. Plots without root bacteria: 12 cm. Bean plants grow with bacteria in their roots that give them nitrogen. Luz removes the bacteria from one plot. What will most likely happen to the beans there?

    • They should grow more, since the roots will have more room for water.
    • They should grow the same, since roots do not need help from other living things.
    • They should grow more, since the bacteria were taking nitrogen from the beans.
    • They should grow less, since they lose the nitrogen the bacteria gave them.
  8. Table (model data)

    Kind A plants per bed. Week 1: 40. Week 2: 36. Week 3: 32. Kind B plants per bed rose from 10 to 30 in those same weeks.

  9. Kind A and Kind B share a bed and use the same resources. Milo pulls out Kind B after week 3. What will the Kind A line most likely do?

    • Kind A should stay at 32 plants, since plant counts stop changing after the third week.
    • Kind A should keep falling at the same speed, since Kind B had no effect on Kind A to begin with.
    • Kind A should fall faster, since Kind B was helping Kind A grow and is now gone from the bed.
    • Kind A should stop falling and start to rise, since it no longer shares resources with Kind B.
  10. Year 1: 2 clumps, oak growth 20 cm. Year 3: 4 clumps, 17 cm. Year 5: 7 clumps, 13 cm. Noah tracks an oak and its mistletoe. If the clumps keep rising to 10 by year 7, what will the oak's yearly growth most likely be?

    • Lower than 13 cm, since more mistletoe takes more water and minerals from the oak.
    • Back near 20 cm, since trees recover when more mistletoe grows on them over the years.
    • Exactly 13 cm, since growth stays at the last measured value however many clumps grow.
    • Higher than 13 cm, since more clumps share the load of taking water and minerals from the oak.
  11. Table (model data)

    Lettuce leaf area. Plot A: week 1: 8, week 2: 14, week 3: 18, week 4: 26, week 5: 34. Plot B: week 1: 8, week 2: 14, week 3: 18, week 4: 19, week 5: 17. Same sun and watering.

  12. Pia compares two lettuce plots. Weeds were pulled from Plot A in week 3 but left in Plot B. What does the difference show?

    • Lettuce grew more where the weeds were left, so the weeds were helping the lettuce along.
    • Lettuce grew more where the weeds were pulled, so the weeds were competing with the lettuce.
    • Plot A got more sun than Plot B, so the sun explains why Plot A grew more than Plot B did.
    • The plots were the same until week 5, so the weeds made no difference to the lettuce at the end.
  13. Table (model data)

    Seedling height after 8 weeks in three pots each. With the fungus: 14, 16, 15 cm. Without the fungus: 7, 9, 8 cm. Same soil, water and light.

  14. Ren grows pine seedlings with and without a root fungus. What do the pot results best show?

    • The seedlings with the fungus grew taller in each pot, so the fungus may help the seedlings.
    • The pots differ in some ways, so the fungus could not have changed the height of the seedlings.
    • The seedlings without the fungus grew taller in each pot, so the fungus harmed the seedlings.
    • The fungus makes the soil warmer, which is why the seedlings with it grew taller than the others.
  15. Table (model data)

    Average mass of one plant after 6 weeks. 1 seed per pot: 12 g. 2 seeds per pot: 9 g. 4 seeds per pot: 5 g. Same soil, water and light in every pot.

  16. Tala grows beans in pots with different numbers of seeds. What does the table best show?

    • Pots with more seeds got more light, which explains the mass of each plant in the pots.
    • Each plant grew larger as more seeds shared a pot, which fits a partnership among the plants.
    • The pots show no pattern, since the mass of one plant changed in each of the pots.
    • Each plant grew smaller as more seeds shared a pot, which fits crowding and competition.
  17. Table (model data)

    Host growth over 4 weeks. Hosts with dodder: 9 cm. Hosts without dodder: 15 cm. Dodder cannot grow without a host.

  18. Zee compares host plants with and without dodder, a plant that wraps around its host and takes water from it. What does the table show?

    • The hosts with dodder grew less, so the dodder gains from the host while the host loses.
    • The hosts with dodder grew the same, since both groups were measured over the same 4 weeks.
    • The hosts with dodder grew less, so the host gains from the dodder and the dodder loses.
    • The hosts with dodder grew less, so the dodder and the host are partners that both gain.