Find the relationship in a data table and graph
Grade 11 Science Worksheet - Challenge Me

Circle the best answer, or write your answer on the line.
A best-fit line of distance fallen d (m) against t² (s²) has slope 4.9 m/s². How long does a ball take to fall 2 m, to 0.01 s, Ari?
On the Moon, a best-fit line of d (m) against t² (s²) has slope 0.81 m/s². How long does a ball take to fall 2 m, to 0.01 s, Bo?
Read this first
Ball dropped from rest, measured with a sensor (example data)
time (s) distance fallen (m) 0.1 0.05 0.2 0.19 0.3 0.45 0.4 0.79 0.5 1.22 Which plot of these measurements gives a straight line, and about what slope, Jun?
- Distance against time, with a slope near 2.4 m/s
- Distance against time squared, with a slope near 4.9 m/s²
- Distance against time squared, with a slope near 9.8 m/s²
- Time squared against distance, with a slope near 9.8 s²/m
In this table, the 0.30 s reading looks off. What is the best way to handle it, Luz?
- Switch to a straight-line fit of d against t, since it fits better
- Keep it unchanged, since removing any data would be dishonest
- Delete it, since any point that sits away from the fitted line is an error
- Recheck that trial: its d ÷ t² is 5.7 where the others are near 4.9
Stopping distance of a car on a dry road (example data)
speed (m/s) stopping distance (m) 10 8 20 32 Milo says doubling a car's speed doubles its stopping distance. Using the table, agree or disagree?
- Agree: braking force fixes the distance whatever the speed
- Disagree: the distance rose from 8 m to 16 m, twice as much
- Disagree: the distance rose from 8 m to 32 m, four times as much
- Agree: the speed doubled, so the stopping distance doubles along with it
Noah says the graph's straight line shows position is directly proportional to time. Agree or disagree?
- Agree: its slope of 2 m/s is the same everywhere along the line
- Disagree: the line starts at 3 m, so doubling t does not double x
- Disagree: a curved graph is needed to show direct proportion
- Agree: a straight line on a position graph means proportion
Light meter readings from a bare lamp (example data)
distance (m) reading (units) 1 16 2 4 4 1 On a log-log graph of the readings the slope is −2.0. Pia says intensity halves when the distance doubles. Agree or disagree?
- Disagree: slope −2 means doubling the distance divides intensity by 2
- Agree: a negative slope means that doubling the distance halves it
- Disagree: slope −2 means doubling the distance divides intensity by 4
- Agree: the readings fall from 16 to 4, which is halving twice over
Using the table, which relationship fits the planets' orbits, Ren?
Planets' orbits around the Sun (real data, NASA Planetary Fact Sheet). Columns: planet, orbit radius (AU), orbit period (years). Venus, 0.723, 0.615; Earth, 1, 1; Mars, 1.52, 1.88; Jupiter, 5.2, 11.9. Planets' orbits around the Sun (real data, NASA Planetary Fact Sheet). Columns: planet, orbit radius (AU), orbit period (years). Venus, 0.723, 0.615; Earth, 1, 1; Mars, 1.52, 1.88; Jupiter, 5.2, 11.9. Planets' orbits around the Sun (real data, NASA Planetary Fact Sheet) planet orbit radius (AU) orbit period (years) Venus 0.723 0.615 Earth 1 1 Mars 1.52 1.88 Jupiter 5.2 11.9 - T² is proportional to a²; T² ÷ a² is the same for each planet
- T is proportional to a; T ÷ a is the same for each planet
- T² is proportional to a³; T² ÷ a³ is about 1.00 for each planet
- T is proportional to a²; T ÷ a² is the same for each planet
Light meter readings from a bare lamp (example data)
distance (m) reading (units) 1 16 2 4 4 1 Which plot of the light readings gives a straight line through the origin, Tala?
- Reading against distance, with the lamp's strength as the slope
- Reading against 1/distance, with the lamp's strength as slope
- Reading against distance², with the lamp's strength as slope
- Reading against 1/distance², with the lamp's strength as slope
Zee fits a straight line through these two pendulum points and predicts the period at 4 m. What goes wrong?
Pendulum periods used for a straight-line fit (example data). Columns: length (m), period (s). 0.25, 1; 1, 2. Pendulum periods used for a straight-line fit (example data). Columns: length (m), period (s). 0.25, 1; 1, 2. Pendulum periods used for a straight-line fit (example data) length (m) period (s) 0.25 1 1 2 - The line is fine, but the pendulum's length was mismeasured
- The line predicts 6.0 s at 4 m, but T² ∝ L gives 4.0 s
- The line is fine, since a line fits any two points exactly
- The line predicts 3.0 s at 4 m, but T² ∝ L gives 4.0 s