Find the relationship in a data table and graph

Grade 11 Science Worksheet

NameDate

Circle the best answer, or write your answer on the line.

  1. A car needs 7.2 m to stop from 10 m/s and 28.8 m from 20 m/s, following a power law. What distance does it need from 30 m/s, Esme?

  2. Jun plots T² (s²) against L (m) for a pendulum. The line through the origin has slope 4.0 s²/m. Using T = 2π√(L/g), what is g?

    • About 0.10 m/s², since g equals the slope divided by 4π²
    • About 4.0 m/s², since the slope of the line is g
    • About 158 m/s², since g equals 4π² times the slope
    • About 9.9 m/s², since the slope is 4π² ÷ g
  3. A braking car's stopping distance d follows d = v² ÷ (2a). Which plot is a straight line, and what is its slope, Kira?

    • v against d, with a slope equal to the acceleration a
    • d against v², with a slope of 1 ÷ (2a)
    • d against 1/v, with a slope equal to twice the acceleration
    • d against v, with a slope equal to the acceleration a
  4. A gas at fixed temperature follows P × V = constant. Which plot of pressure P gives a straight line through the origin, Luz?

    • P against V², with the constant as the slope
    • 1/P against 1/V, with the constant as the slope
    • P against 1/V, with the constant as the slope
    • P against V, with the constant as the slope
  5. Which plot of the table makes a straight line through the origin, Milo?

    • Period squared against length
    • Period against length, since both columns rise together
    • Period against 1/length, since the longer pendulums are slower
    • Period against length squared, since the periods are rounded
  6. Using the table, what length gives a period of 5.0 s, Noah?

    Use the picture in question 5.

    • About 6.25 m, since T² ÷ L stays 4
    • About 12.5 m, since T² ÷ L stays 2
    • About 2.5 m, since period is proportional to length
    • About 1.25 m, since length is the period divided by 4
  7. Pia measured these periods. Do they fit T² = 4L, where T² ÷ L is 4?

    • No: T ÷ L falls from 4.1 to 1.4, so there is no pattern
    • Yes: the period rises each time the length rises, so it fits
    • No: no period equals exactly 2√L, so the model fails
    • Yes: T² ÷ L is between 3.9 and 4.2, within about 5% of 4
  8. A spring's stretch (m) against force (N) has slope 0.02 m/N. What is its spring constant k, the force per meter, Ren?

    • 5 N/m, since k is the slope divided by 10
    • 0.02 N/m, since k equals the slope
    • 0.02 m/N, since the slope already has k's units
    • 50 N/m, since k is the inverse of the slope
  9. Force (N) plotted against acceleration (m/s²) for a cart gives slope 2.5. What does the slope mean, Tala?

    • The cart's weight: 2.5 N
    • The cart's mass: 2.5 kg
    • The cart's inverse mass: 2.5 per kg
    • The cart's speed: 2.5 m/s
  10. The slopes of a position-time curve at 2 s and 6 s are 2 m/s and 6 m/s. What does (6 − 2) ÷ (6 − 2) tell Zee?

    • The average velocity: 1 m/s
    • The average acceleration: 4 m/s²
    • The average acceleration: 1 m/s²
    • The distance moved: 4 m
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Find the relationship in a data table and graph

Answer Key - Grade 11 Science Worksheet

Circle the best answer, or write your answer on the line.

  1. A car needs 7.2 m to stop from 10 m/s and 28.8 m from 20 m/s, following a power law. What distance does it need from 30 m/s, Esme?

    64.8
  2. Jun plots T² (s²) against L (m) for a pendulum. The line through the origin has slope 4.0 s²/m. Using T = 2π√(L/g), what is g?

    • About 0.10 m/s², since g equals the slope divided by 4π²
    • About 4.0 m/s², since the slope of the line is g
    • About 158 m/s², since g equals 4π² times the slope
    • About 9.9 m/s², since the slope is 4π² ÷ g
  3. A braking car's stopping distance d follows d = v² ÷ (2a). Which plot is a straight line, and what is its slope, Kira?

    • v against d, with a slope equal to the acceleration a
    • d against v², with a slope of 1 ÷ (2a)
    • d against 1/v, with a slope equal to twice the acceleration
    • d against v, with a slope equal to the acceleration a
  4. A gas at fixed temperature follows P × V = constant. Which plot of pressure P gives a straight line through the origin, Luz?

    • P against V², with the constant as the slope
    • 1/P against 1/V, with the constant as the slope
    • P against 1/V, with the constant as the slope
    • P against V, with the constant as the slope
  5. Which plot of the table makes a straight line through the origin, Milo?

    • Period squared against length
    • Period against length, since both columns rise together
    • Period against 1/length, since the longer pendulums are slower
    • Period against length squared, since the periods are rounded
  6. Using the table, what length gives a period of 5.0 s, Noah?

    Use the picture in question 5.

    • About 6.25 m, since T² ÷ L stays 4
    • About 12.5 m, since T² ÷ L stays 2
    • About 2.5 m, since period is proportional to length
    • About 1.25 m, since length is the period divided by 4
  7. Pia measured these periods. Do they fit T² = 4L, where T² ÷ L is 4?

    • No: T ÷ L falls from 4.1 to 1.4, so there is no pattern
    • Yes: the period rises each time the length rises, so it fits
    • No: no period equals exactly 2√L, so the model fails
    • Yes: T² ÷ L is between 3.9 and 4.2, within about 5% of 4
  8. A spring's stretch (m) against force (N) has slope 0.02 m/N. What is its spring constant k, the force per meter, Ren?

    • 5 N/m, since k is the slope divided by 10
    • 0.02 N/m, since k equals the slope
    • 0.02 m/N, since the slope already has k's units
    • 50 N/m, since k is the inverse of the slope
  9. Force (N) plotted against acceleration (m/s²) for a cart gives slope 2.5. What does the slope mean, Tala?

    • The cart's weight: 2.5 N
    • The cart's mass: 2.5 kg
    • The cart's inverse mass: 2.5 per kg
    • The cart's speed: 2.5 m/s
  10. The slopes of a position-time curve at 2 s and 6 s are 2 m/s and 6 m/s. What does (6 − 2) ÷ (6 − 2) tell Zee?

    • The average velocity: 1 m/s
    • The average acceleration: 4 m/s²
    • The average acceleration: 1 m/s²
    • The distance moved: 4 m