Kirchhoff's rules for circuits

Grade 11 Science Worksheet - Challenge Me

NameDate

Circle the best answer, or write your answer on the line.

  1. In one loop, a 12 V battery and a 3 V battery face opposite ways, with 6 Ω in total. What current flows, to 0.01 A, Esme?

  2. In one loop, a 9 V battery and a 4 V battery face opposite ways, with 10 Ω in total. What current flows, to 0.01 A, Jun?

  3. A student says the bulb nearest the battery's + end gets more current in a series loop. Which reply fits Kirchhoff's rules, Milo?

    • Yes; the far bulb gets less, since the near one takes some
    • No; parts in one loop carry the same current
    • Yes; current is used up along the loop
  4. A student says each resistor in a series loop gets the battery's full voltage. Which reply fits the loop rule, Noah?

    • No; the drops around the loop add to the battery voltage
    • Yes; voltage is the same at each point of a loop
    • Yes; each resistor drops the full voltage, so they add to double
  5. In the schematic, what current flows in branch R3, Pia?

    • 5 A
    • 3 A
    • 1 A
  6. In the schematic, what is the voltage across R1, and so across the branches, Ren?

    Use the picture in question 5.

    • 6 V across R1, so 12 V across each branch
    • 6 V across R1, so 6 V across each branch
    • 6 V across R1, so 3 V across each branch
  7. In the schematic, what is the resistance of branch R2, Tala?

    Use the picture in question 5.

    • 3 Ω
    • 12 Ω
    • 6 Ω
  8. A solution for the schematic gives 2 A in R2, 2 A in R3 and 3 A through R1. Which rule does it break, Zee?

    Use the picture in question 5.

    • The junction rule: 2 + 2 is not 3
    • The loop rule: 12 V is not 6 V
    • Neither rule; it passes both
  9. A solution for a 9 V loop gives drops of 3 V and 3 V across its only two resistors. Which rule does it break, Ari?

    • Neither rule; the drops are equal
    • The junction rule: current is lost in the loop
    • The loop rule: 9 − 3 − 3 is not 0
  10. A 12 V and a 3 V battery face opposite ways in one loop with 6 Ω. A solution gives 2.5 A. Which check fails, Bo?

    • The loop rule: 12 − 3 − 6 × 2.5 is not 0
    • The junction rule, at a junction it lacks
    • Nothing fails; 15 ÷ 6 = 2.5 A is right
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Kirchhoff's rules for circuits

Answer Key - Grade 11 Science Worksheet - Challenge Me

Circle the best answer, or write your answer on the line.

  1. In one loop, a 12 V battery and a 3 V battery face opposite ways, with 6 Ω in total. What current flows, to 0.01 A, Esme?

    1.5 A
  2. In one loop, a 9 V battery and a 4 V battery face opposite ways, with 10 Ω in total. What current flows, to 0.01 A, Jun?

    0.5 A
  3. A student says the bulb nearest the battery's + end gets more current in a series loop. Which reply fits Kirchhoff's rules, Milo?

    • Yes; the far bulb gets less, since the near one takes some
    • No; parts in one loop carry the same current
    • Yes; current is used up along the loop
  4. A student says each resistor in a series loop gets the battery's full voltage. Which reply fits the loop rule, Noah?

    • No; the drops around the loop add to the battery voltage
    • Yes; voltage is the same at each point of a loop
    • Yes; each resistor drops the full voltage, so they add to double
  5. In the schematic, what current flows in branch R3, Pia?

    • 5 A
    • 3 A
    • 1 A
  6. In the schematic, what is the voltage across R1, and so across the branches, Ren?

    Use the picture in question 5.

    • 6 V across R1, so 12 V across each branch
    • 6 V across R1, so 6 V across each branch
    • 6 V across R1, so 3 V across each branch
  7. In the schematic, what is the resistance of branch R2, Tala?

    Use the picture in question 5.

    • 3 Ω
    • 12 Ω
    • 6 Ω
  8. A solution for the schematic gives 2 A in R2, 2 A in R3 and 3 A through R1. Which rule does it break, Zee?

    Use the picture in question 5.

    • The junction rule: 2 + 2 is not 3
    • The loop rule: 12 V is not 6 V
    • Neither rule; it passes both
  9. A solution for a 9 V loop gives drops of 3 V and 3 V across its only two resistors. Which rule does it break, Ari?

    • Neither rule; the drops are equal
    • The junction rule: current is lost in the loop
    • The loop rule: 9 − 3 − 3 is not 0
  10. A 12 V and a 3 V battery face opposite ways in one loop with 6 Ω. A solution gives 2.5 A. Which check fails, Bo?

    • The loop rule: 12 − 3 − 6 × 2.5 is not 0
    • The junction rule, at a junction it lacks
    • Nothing fails; 15 ÷ 6 = 2.5 A is right