Enzymes: how they speed reactions, and what pH and temperature do
Grade 9 Science Worksheet - Challenge Me

Circle the best answer.
Enzyme drawing (model, not to scale). Ari’s friend says an enzyme is used up in each reaction, so cells need a fresh enzyme for every substrate. Which response is best?
- Disagree: the enzyme comes out unchanged, so it is reusable
- Agree: the enzyme turns into the product during the reaction
- Agree: part of the enzyme is spent on each substrate it meets
- Disagree: an enzyme stays far away from the substrate
Bo’s friend says an enzyme speeds a reaction by giving the substrate the energy it needs. Use the diagram. Which response is best?
Energy diagram (model data, not to scale). Reaction progress across. Energy (energy units) up, 0 to 120, a mark every 20. Every curve starts at 45 on the left and ends at 25 on the right. Without the enzyme climbs to a peak at 105. With the enzyme climbs to a peak at 65. Energy diagram (model data, not to scale). Reaction progress across. Energy (energy units) up, 0 to 120, a mark every 20. Every curve starts at 45 on the left and ends at 25 on the right. Without the enzyme climbs to a peak at 105. With the enzyme climbs to a peak at 65. Energy diagram (model data, not to scale) 0 20 40 60 80 100 120 Reaction progress Energy (energy units) Without the enzyme With the enzyme - Agree: the enzyme stores energy and hands it to the reaction
- Disagree: it lowers the activation energy, so less is needed
- Agree: the energy it supplies pushes the substrate over the hill
- Disagree: it lowers the energy of the products instead
Read this first
Use this
Model drawing, not to scale. Enzyme E has a notch, its active site, shaped to hold a round bead joined to a square bead. Molecule M1: a round bead joined to a square bead. Molecule M2: a round bead joined to a triangle bead.
Esme’s friend says enzymes are tiny living things, so one can learn to work on any substrate. Which response is best?
- Disagree: an enzyme is a protein whose active site fits a matching substrate
- Agree: living enzymes reshape their active site to fit any substrate
- Agree: an enzyme is alive because it works inside living cells
- Disagree: an enzyme is a protein, so it fits any substrate equally
Use the table
Investigation card (model data; a teacher handles every chemical). Question: How does temperature affect catalase? What is changed: the temperature of the catalase solution. What is measured: the height of the oxygen foam after 1 minute. What stays the same: 5 mL of catalase solution and 5 mL of hydrogen peroxide in each tube.
temperature (°C) foam height (mm) 10 8 30 30 50 12 80 0 A teacher ran this catalase test while Jun’s class watched. Which conclusion do the data support?
- Among the four, 30 °C gave the most foam and 80 °C gave none
- More heat gave more foam, so catalase works best above 80 °C
- 30 °C is exactly the best temperature for catalase
- Catalase was used up at 80 °C, which is why no foam formed
Kira’s class reads a teacher’s catalase test. What is the flaw in the test?
- The catalase in Tube 1 was used up, so the tubes cannot be compared
- Two things changed at once: the temperature and the catalase amount
- The hydrogen peroxide amount should have changed in each tube
- Tube 2 should have been hotter, since heat speeds up enzymes
A teacher added water to Tube 2 on purpose, while Luz’s class watched. What does Tube 2 help show?
- Water stops foam from forming, since the water tube had none
- Catalase supplies the energy, since the water tube had none
- Catalase turns into foam, since the water tube had none
- Catalase is what makes the foam form: water alone made none
Use this
Rate-versus-substrate graph with and without inhibitor I (model data). Substrate amount (units) across, 0 to 7, a mark every 1. Reaction rate (units per minute) up, 0 to 100, a mark every 20. Enzyme alone joins (0 units, 0), (1 unit, 30), (2 units, 55), (3 units, 75), (4 units, 85), (5 units, 90), (6 units, 90), (7 units, 90) with straight pieces. Enzyme with inhibitor I joins (0 units, 0), (1 unit, 15), (2 units, 32), (3 units, 50), (4 units, 65), (5 units, 78), (6 units, 86), (7 units, 90) with straight pieces. A small drawing beside the graph shows inhibitor I, shaped like the substrate, sitting in the enzyme’s active site.
Milo sees inhibitor I sit in the enzyme’s active site in the drawing. Using the graph at substrate 2, what does I do, and why?
- The rate falls, because I uses up the enzyme over time
- The rate falls, because I takes up active sites
- The rate rises, because I adds energy to the active sites
- The rate falls, because I changes the substrate’s shape
Noah sees the two lines meet at 90 at substrate 7. Which explanation fits both the graph and the drawing of inhibitor I?
- I changes into whatever substrate the enzyme fits
- I is used up by the extra substrate that arrives
- The extra substrate brings energy that cancels I
- The extra substrate outcompetes I for active sites
Pia knows inhibitor I fits enzyme E’s active site, not F’s. Using the drawing and the table, which statement is best?
Rate at substrate amount 2, in units per minute (model data), 2 rows. Columns: enzyme, rate without I, rate with I. E, 55, 32; F, 40, 40. A drawing beside the table shows inhibitor I shaped to fit the active site of E; the active site of F has a different shape. Rate at substrate amount 2, in units per minute (model data), 2 rows. Columns: enzyme, rate without I, rate with I. E, 55, 32; F, 40, 40. A drawing beside the table shows inhibitor I shaped to fit the active site of E; the active site of F has a different shape. Rate at substrate amount 2, in units per minute (model data), 2 rows enzyme rate without I rate with I E 55 32 F 40 40 inhibitor I enzyme E active site of E enzyme F active site of F - I slows both, because an inhibitor blocks any enzyme it meets
- I slows E but not F, because I matches E’s active site
- I slows E by using E up, while F is left untouched
- I speeds F up, because F has no matching active site for I
Product made by 5 enzyme molecules (model data)
time (min) product molecules 0 0 1 1000 2 2000 3 3000 Zee’s tube holds 5 enzyme molecules. The table shows the product made over time. How can 5 enzymes make 3,000 products?
- The enzymes give off energy, which turns into extra product
- Each enzyme is unchanged, so it can work again and again
- Enzymes are alive, so each one makes copies of itself as it works
- Each enzyme is used up in one reaction, so new enzymes must have formed