Congruent figures: corresponding parts and rigid motions
Grade 10 Math Worksheet - Challenge Me

Circle the best answer.
Luz reflects P(3, -2) across the x-axis, then across the y-axis. Which single rigid motion does the pair equal?
- A flip across the y-axis alone, leaving the y values
- A quarter turn about the origin
- A flip across the line y = x
- A half turn about the origin
Noah claims any two congruent triangles are related by one flip. Does this pair support the claim?
△ABC: A(0, 0), B(4, 0), C(0, 3). △DEF: D(5, 5), E(9, 5), F(5, 8). Both have sides 3, 4, 5 and go around in the same direction. △ABC: A(0, 0), B(4, 0), C(0, 3). △DEF: D(5, 5), E(9, 5), F(5, 8). Both have sides 3, 4, 5 and go around in the same direction. A(0, 0) B(4, 0) C(0, 3) D(5, 5) E(9, 5) F(5, 8) 4 3 5 4 3 5 x y - No: DEF is ABC slid by ⟨5, 5⟩, and a flip would reverse the corner order
- Yes: a flip plus a slide works reliably, so one flip alone is surely enough
- No: the sides of DEF are different from those of ABC
- Yes: congruent triangles are mirror images of each other, with the same size
Both triangles are right triangles with hypotenuse 13 and one leg 5. The other leg is not given. Two right triangles each have a hypotenuse of 13 and a leg of 5. Ari says they are congruent. Which reason is best?
- Two sides and a non-included angle (SSA) do fix a triangle
- The hypotenuses match, so the two right triangles are congruent
- The other leg is √(169 − 25) = 12 in both, so the sides match (SSS)
- Both have a right angle, so the angles match and AAA applies to the pair
Esme's map: a rigid motion takes A(1, 2) to A′(5, 2) and C(4, 1) to C′(2, 1), and leaves B(3, 5) where it is. What is it?
A(1, 2) goes to A′(5, 2). C(4, 1) goes to C′(2, 1). B(3, 5) is fixed. A(1, 2) goes to A′(5, 2). C(4, 1) goes to C′(2, 1). B(3, 5) is fixed. A(1, 2) A'(5, 2) C(4, 1) C'(2, 1) B(3, 5) x y - A flip across the line y = 2
- A flip across the line x = 3
- A slide 4 units right
- A turn about B(3, 5), since B stays fixed
Kira's tile WXYZ is a parallelogram with its corners in order. Diagonal WY cuts it into two triangles. Which rigid motion maps △WXY onto △YZW?
Parallelogram WXYZ with corners in order W, X, Y, Z. The diagonal WY splits it into △WXY and △YZW. The sides are not all equal and the angles are not right angles. Parallelogram WXYZ with corners in order W, X, Y, Z. The diagonal WY splits it into △WXY and △YZW. The sides are not all equal and the angles are not right angles. WY W X Y Z triangle WXY triangle YZW The sides are not all equal and the angles are not right angles. - A slide along the diagonal WY
- A flip across the diagonal WY
- A flip across the perpendicular bisector of WY
- A half turn (180°) about the midpoint of WY
Read this first
Statement
△ABC ≅ △DEF. AB = 2x + 4, BC = 3x − 1, AC = x + 9, in centimeters. Perimeter of △ABC: 36 cm.
Zee's tiles satisfy △ABC ≅ △DEF. AB = 2x + 4, BC = 3x − 1 and AC = x + 9. The perimeter of △ABC is 36 cm. How long is DF?
- 13 cm
- 4 cm
- 12 cm
- 11 cm
Pia claims a rigid motion never changes a segment's slope. A quarter turn takes the segment from (0, 0) to (2, 1) onto the segment from (0, 0) to (-1, 2). What does this show?
Segment from (0, 0) to (2, 1) has slope 1/2. After a counterclockwise quarter turn about the origin it runs from (0, 0) to (-1, 2). Segment from (0, 0) to (2, 1) has slope 1/2. After a counterclockwise quarter turn about the origin it runs from (0, 0) to (-1, 2). −2 −1 1 2 3 −3 −2 −1 1 2 3 0 slope 1/2 counterclockwise quarter turn about the origin - The claim is false: the slope goes from 1/2 to -2, yet the length √5 stays
- The claim is true: slope is a ratio, and a ratio does not change in any motion
- The claim is false: the length changes from √5 to 5
- The claim is true: both lengths are √5, so the slopes must match as well
In isosceles △ABC with AB = AC, Tala draws the bisector AD of ∠A to the base BC and proves △ABD ≅ △ACD by SAS. Which facts does the proof need?
Triangle ABC with AB = AC. Segment AD bisects ∠BAC and meets BC at D. The goal is to show ∠B = ∠C. Triangle ABC with AB = AC. Segment AD bisects ∠BAC and meets BC at D. The goal is to show ∠B = ∠C. The goal is to show ∠B = ∠C. AB = AC AD A B C D - AB = AC (given), ∠ADB = ∠ADC (right angles), AD = AD (shared)
- AB = AC (given), ∠BAD = ∠CAD (bisector), AD = AD (shared)
- AB = AC (given), ∠B = ∠C (isosceles), AD = AD (shared)
- AB = AC (given), BD = CD (midpoint), AD = AD (shared)
a slide. Step 2: a dilation with scale factor 1. Step 3: a rotation. Jun slides △ABC, enlarges the image with scale factor 1, then turns it. Is the final triangle congruent to △ABC?
- No: any dilation changes the size of a figure, so the result is bigger
- Yes: a scale factor of one changes nothing, so all three steps are rigid
- Yes: a dilation with any scale factor keeps the shape, so the result is congruent
- No: a dilation is not a slide, flip or turn, so the steps are not rigid
Ren counts the rigid motions that map an equilateral triangle exactly onto itself, including turning by 0°. How many are there?
Equilateral triangle ABC. A motion counts if the triangle covers its own outline afterwards. Equilateral triangle ABC. A motion counts if the triangle covers its own outline afterwards. Equilateral triangle ABC. A B C A motion counts if the triangle covers its own outline afterwards. - 6: three turns (0°, 120°, 240°) and three flips
- 3: just the three turns, since a flip changes the picture of the triangle
- 9: three turns, three flips and three slides along the sides
- 12: each of the 6 positions can be reached in two ways