Congruent figures: corresponding parts and rigid motions
Grade 10 Math Worksheet

Circle the best answer.
A matches D, B matches E, C matches F. Luz's quilt piece △ABC has A(1, 2), B(4, 2), C(4, 4). Its image is D(-4, 2), E(-7, 2), F(-7, 4). Which sequence of moves maps △ABC onto △DEF?
- Turn 180° about the origin, then slide 3 left
- Slide 3 right, then flip across the y-axis
- Flip across the y-axis, then slide 3 right
- Flip across the x-axis, then slide 3 right
Ari's kite sail △ABC has A(3, 1), B(6, 1), C(6, 4). It turns 90° counterclockwise about A. Where does C land?
△ABC: A(3, 1), B(6, 1), C(6, 4). Rotate 90° counterclockwise about A. A quarter turn sends the arrow ⟨a, b⟩ to ⟨-b, a⟩. △ABC: A(3, 1), B(6, 1), C(6, 4). Rotate 90° counterclockwise about A. A quarter turn sends the arrow ⟨a, b⟩ to ⟨-b, a⟩. Rotate 90° counterclockwise about A. A quarter turn sends the arrow ?a, b? to ?-b, a?. 1 2 3 4 5 6 7 8 1 2 3 4 5 6 0 A B C - C′(-3, 3)
- C′(6, -2)
- C′(0, -2)
- C′(0, 4)
In two triangles, AB = DE, BC = EF and ∠A = ∠D. Tala says SAS proves them congruent. Is Tala right?
Equal parts: AB = DE, BC = EF, and ∠A = ∠D. The angle ∠A sits between sides AB and AC, not between AB and BC. Equal parts: AB = DE, BC = EF, and ∠A = ∠D. The angle ∠A sits between sides AB and AC, not between AB and BC. Equal parts: AB = DE, BC = EF, and ∠A = ∠D. AB = DE BC = EF ∠A ∠D A B C D E F The angle ∠A sits between sides AB and AC, not between AB and BC. - Yes: any three equal parts settle that two triangles are congruent
- No: congruence needs the six parts shown equal
- Yes: two sides and an angle are equal, so this is SAS and the triangles match
- No: ∠A is not between the equal sides, so the parts can fit two different triangles
Read this first
Use this
AB = DE, ∠A = ∠D, AC = DF. After sliding A onto D, the triangles share only the corner D.
Ren shows SAS works. Triangles have AB = DE, ∠A = ∠D and AC = DF. A is slid onto D. Which moves finish the argument?
- Turn about D until C reaches F, which works for any two triangles that have AB = DE
- Because ∠A = ∠D, the third sides already match, so no more moves are needed
- Turn so AB lies along DE, flip if needed so C is on F's side, then AC = DF puts C on F
- Enlarge until AC = DF, since the triangles need the same size to fit
Statement
△ABC ≅ △DEF. ∠A = (3x + 5)°, ∠D = (5x − 25)°, ∠B = (2x + 10)°. ∠F is not given.
Esme's paper triangles satisfy △ABC ≅ △DEF. ∠A = (3x + 5)°, ∠D = (5x − 25)° and ∠B = (2x + 10)°. How big is ∠F?
- 40°
- 130°
- 50°
- 90°
Triangle 1 has corners (0, 0), (6, 0), (0, 8). Triangle 2 has (1, 1), (1, 7), (9, 1). Zee says they are congruent. Which reason is best?
Triangle 1: (0, 0), (6, 0), (0, 8). Triangle 2: (1, 1), (1, 7), (9, 1). Both have area 24 square units. Triangle 1: (0, 0), (6, 0), (0, 8). Triangle 2: (1, 1), (1, 7), (9, 1). Both have area 24 square units. Both have area 24 square units. −1 1 2 3 4 5 6 7 8 9 10 −1 1 2 3 4 5 6 7 8 9 0 Triangle 1 Triangle 2 - Both have sides 6, 8 and 10, so SSS shows a rigid motion fits one onto the other
- Their corners sit at different points on the grid, so the two cannot be congruent
- Both have area 24, so they must be congruent
- Both have a right angle, so right angles settle congruence
Statement
△JKL ≅ △RST. JK = 2x + 7, RS = 4x − 5, KL = 3y − 1, ST = y + 9, in centimeters.
Bo's sails satisfy △JKL ≅ △RST. JK = 2x + 7, RS = 4x − 5, KL = 3y − 1 and ST = y + 9. How long is KL?
- 28 cm
- 5 cm
- 14 cm
- 19 cm
Use this
∠A = ∠D = 40°, ∠B = ∠E = 65°, AB = DE = 7. Side AB lies between ∠A and ∠B.
Pia studies △ABC and △DEF with ∠A = ∠D = 40°, ∠B = ∠E = 65° and AB = DE = 7. Which criterion proves them congruent, and why?
- AAA: the three angles are equal, so the two triangles must be congruent
- ASA: AB lies between the equal angles, so the rays from its ends meet alike
- AAS: the equal side is not between the equal angles, so ASA cannot be used
- No criterion fits: two angles and one side are not enough to settle congruence
Use this
△MNP: ∠M = 38°, ∠N = 72°, MN = 9 cm. △XYZ: ∠Y = 38°, ∠Z = 72°, YZ = 9 cm. Each 9 cm side lies between its two given angles.
Milo compares △MNP and △XYZ. ∠M = 38°, ∠N = 72°, MN = 9; ∠Y = 38°, ∠Z = 72°, YZ = 9. Which statement is correct?
- △MNP ≅ △XYZ
- △MNP ≅ △YXZ
- △MNP ≅ △YZX
- △MNP ≅ △ZYX
The proof uses AB = DE as a reason. The problem gave only BC = EF and ∠B = ∠E. Jun writes: "The triangles are congruent, so AB = DE. Also BC = EF and ∠B = ∠E, so SAS makes them congruent." What is wrong?
- It assumes the congruence to get AB = DE, which is what the proof must show
- A proof must use six parts of the triangles, and this one does not
- SAS needs two angles and a side, but the proof has two sides and an angle left
- AB = DE is true because congruent triangles have equal sides, so the proof is fine