Waves that add and cancel
Grade 8 Science Worksheet - Challenge Me

Circle the best answer.
Each wave repeats every 4 ms. Headphones add an anti-noise wave to cancel a hum. Which wave in the table leaves the quietest sound, Ari?
- X, whose crests match the hum's crests and whose size matches, so the two waves agree
- Y, whose crests meet the hum's troughs and whose size matches, so the sum is zero
- Z, whose crests meet the hum's troughs, which cancels any hum whatever the wave's size
- Any wave: adding a second wave to the hum can add sound but cannot take sound away
The copy has the same size as the hum. A headphone adds a copy of the hum, delayed. Which delay cancels the hum, Esme?
- P, since a copy with no delay reaches the ear first and removes the hum
- R, since a delay of 1.5 periods puts the copy's crests on the hum's troughs
- Q, since a delay of 1 period lines the copy's crests up with the hum's crests to cancel them
- S, since the longest delay gives the copy the most time to cancel the hum
Read this first
Sound intensity at four seats (example data)
seat one speaker alone both speakers A 1 4 B 1 0 C 1 4 D 1 0 Jun says destructive interference destroys sound energy. Which statement fits the table?
- Energy is moved, not destroyed: the seats average 2, the same as two speakers give separately, 1 + 1
- Energy is unchanged at each seat, since a single speaker gives 1 at each seat of the table
- Energy is destroyed at seats B and D, where the table shows 0, so the total energy of the room falls
- Energy is created at seats A and C, where 4 is more than 1, so the total energy of the room rises
A crest and a trough meeting on a rope (example data)
wave height at the meeting point (cm) Crest 3 Trough −2 Kira says a 2 cm trough cancels a 3 cm crest completely where they meet. What does the table show?
- The claim holds: the 1 cm that is left is too small to count as a wave
- The claim fails: the 2 cm trough has no effect, so the full 3 cm crest stays
- The claim holds: any trough cancels a crest, so nothing is left where they meet
- The claim fails: 3 + (−2) = 1 cm, so a 1 cm crest is left where they meet
Waves on a rope (example data)
amplitude (cm) energy carried each second (units) 1 2 2 8 3 18 Luz says a combined wave with twice the amplitude carries twice the energy. What does the table show?
- The claim fails: the energy stays at 2 units no matter how tall the wave becomes
- The claim holds: the energy rises by 6 units for each extra centimeter of amplitude
- The claim fails: doubling the amplitude from 1 cm to 2 cm took the energy from 2 to 8, four times
- The claim holds: a taller wave is a stretched copy, so doubling the amplitude doubles the energy it carries
The ripples are 2 cm long. Two dippers make ripples in step. Which points stay calm, Milo?
- R and S, where the distances differ by the most, 2 cm and 3 cm, so the waves cancel
- Q and S, where the distances differ by half and by one and a half wavelengths
- P and R, where the distances differ by no wavelengths and by one whole wavelength
- Q alone, where the distances differ by exactly half a wavelength, and no other point
The note has a wavelength of 0.4 m. Room echoes are ignored. Two speakers play one note in step. At which seats is the sound loudest, Noah?
- F alone, where the two waves travel the most nearly equal distances of any seat
- G and I, where the paths differ by 0.4 m and 0.8 m, one and two whole wavelengths
- H and I, where the paths differ by the most, 0.6 m and 0.8 m, so crests add the most
- F and H, where the paths differ by 0.2 m and 0.6 m, half and one and a half wavelengths
Sound travels 343 m/s in air, so frequency times wavelength is 343. Speakers play each note in step. Seat S is 6.0 m from one speaker and 6.25 m from the other. What does Pia hear at S?
- Quiet for the first note, since 0.25 m is half its wavelength, and loud for the second, since 0.25 m is its whole wavelength
- Loud for both notes, since the speakers play in step and the seat is almost the same distance from both
- Quiet for both notes, since the 0.25 m path difference does not change when the note changes
- Loud for the first note, since 0.25 m is half its wavelength, and quiet for the second, since 0.25 m is its whole wavelength
Two tuning forks (example data)
fork frequency (Hz) A 440 B 444 Ren sounds two tuning forks together, and the sound gets louder and softer again and again. How many times each second does it get loud?
- 884 times each second, the sum of the two frequencies, 444 Hz and 440 Hz
- 2 times each second, half of the difference between the two frequencies
- 442 times each second, the average of the two frequencies of the forks
- 4 times each second, the difference between 444 Hz and 440 Hz
Four pairs of tuning forks (example data)
pair fork 1 (Hz) fork 2 (Hz) P 256 260 Q 440 441 R 440 445 S 256 258 Two forks sound together in each pair. Which pair makes the loudness rise and fall most slowly, Tala?
- Pair P, because it has the lowest frequencies, which makes the slowest rise and fall in loudness
- Pair S, because a gap of 2 Hz is a middle value, which gives a steady, slow change
- Pair R, because its frequencies add up to the largest total, which slows the changes
- Pair Q, whose frequencies differ by just 1 Hz, so the loudness changes once a second