Acceleration
Grade 11 Science Worksheet

Circle the best answer, or write your answer on the line.
East is positive. A cart's sensor reads 14 m/s at t = 1 s and 2 m/s at t = 5 s. What is its acceleration, Ari?
East is positive. A cyclist reads 4 m/s at t = 2 s and -6 m/s at t = 10 s, after turning around. What is the acceleration, Bo?
The cart in the velocity-time graph reverses. What is its acceleration from 0 s to 5 s, Jun?
- 0 m/s² at 3 s, where v = 0
- +2 m/s², since the cart ends up going the other way
- −2 m/s², the same all the way
- −4 m/s², the lowest velocity reached
Velocity-time graph (example data): time (s) across, 0 to 5, a mark every 1 s; velocity (m/s) up, 0 to 18, a mark every 2 m/s. The curve passes through (0 s, 0 m/s), (1 s, 7 m/s), (2 s, 12 m/s), (3 s, 15 m/s), (4 s, 16 m/s), (5 s, 15 m/s). Velocity-time graph (example data): time (s) across, 0 to 5, a mark every 1 s; velocity (m/s) up, 0 to 18, a mark every 2 m/s. The curve passes through (0 s, 0 m/s), (1 s, 7 m/s), (2 s, 12 m/s), (3 s, 15 m/s), (4 s, 16 m/s), (5 s, 15 m/s). Velocity-time graph (example data) 0 1 2 3 4 5 0 2 4 6 8 10 12 14 16 18 time (s) velocity (m/s) The curved velocity-time graph rises, then levels at 4 s. What are the average acceleration from 0 to 4 s and the acceleration at 4 s, Kira?
- Average 4 m/s²; at 4 s the slope is 0
- Average 4 m/s²; at 4 s it is 16 m/s²
- Average 16 m/s²; at 4 s the slope is 0
- Average 4 m/s²; at 4 s it is still 4 m/s²
Using the same curve, in which one-second step is the average acceleration largest, and how large, Luz?
Use the picture in question 4.
- The last second: −1 m/s², the final slope
- The first second: 16 m/s²
- 0 to 4 s: 4 m/s², the longest step
- The first second: 7 m/s²
A car moves at 20 m/s. The driver reacts for 0.80 s, then brakes at 5.0 m/s². How far does it travel before stopping, Milo?
- 56 m: 16 m before braking and 40 m while braking
- 96 m, using 20 × 4.0 s for the braking part
- 40 m, leaving out the reaction time
- 16 m, the reaction distance alone, before it stops
A cart speeds from 3.0 m/s to 11 m/s over 28 m. The time is unknown. Which equation fits, and what is a, Pia?
- v² = v₀² + 2ad, giving a = 4.0 m/s²
- v² = v₀² + 2ad, giving a = 1.0 m/s²
- v = v₀ + at, giving a = 0.29 m/s²
- v² = v₀² + 2ad, giving a = 2.0 m/s²
Read this first
Two balls dropped from rest (example data)
time (s) ball A in vacuum speed (m/s) ball B in air speed (m/s) 0 0 0 1 9.8 9.5 2 19.6 17.2 3 29.4 23.4 Ren drops two balls and records speed each second. Ball A falls in a vacuum, ball B in air. Which statement fits the table?
- B's acceleration shrinks each second; A's stays 9.8 m/s²
- A's acceleration grows because its speed grows
- Both have a = 9.8 m/s², since gravity is the same
- B is slowing down, since its gains get smaller
A sign says: "Raising the limit from 30 to 40 mph adds only a third more braking distance." Judge the claim, Tala.
- Not supported: it is about 133% more
- Not supported: distance scales as v², so about 78% more
- Not supported: it is about 178% more
- Supported: a third more speed gives a third more distance
A ball is thrown down at 4.0 m/s from a bridge and hits the water after 2.0 s. How high is the bridge, Zee?
- About 20 m, if the ball were simply dropped
- About 24 m, the final speed used as the height
- About 47 m, using g t² without the one half
- About 28 m: 8.0 m from the throw, 19.6 m from gravity