Define a design problem and weigh trade-offs

Grade 11 Science Worksheet

NameDate

Circle the best answer, or write your answer on the line.

  1. A motor lifts a 120 kg load at 0.5 m/s and is 75% efficient. With g = 9.8 m/s², how much power does it draw, Bo?

  2. A motor lifts a 30 kg load at 1.5 m/s and is 60% efficient. With g = 9.8 m/s², how much power does it draw, Esme?

  3. Read this first

    Crash-barrier designs for a 1,200 kg car at 25 m/s (example data)

    designcrush length (m)cost ($ thousand)
    A1.540
    B2.555
    C480

    Limits: crush length at most 3.0 m and deceleration at most 15 g, where g is 9.8 m/s². Constant deceleration is v² ÷ (2d)

  4. Using the table, which is the cheapest barrier design that meets both limits, Jun?

    • C, since its 78 m/s² is the lowest deceleration of the three
    • B, since its 125 m/s² is under 147 and its 2.5 m fits
    • No design, since no crush length can meet both of the limits together
    • A, the cheapest, since its 1.5 m crush zone fits easily in the space
  5. Motors rated for the same job (example data) (example data)

    motorefficiency (%)mass (kg)cost ($)
    P881.2120
    Q881.5140
    R820.9100
  6. Using the table, which motor can be dropped whatever the weights, Luz?

    • R, since its efficiency is the lowest of the three motors
    • Q, since P matches its efficiency with less mass and lower cost
    • P, since it does not top the table on each column at once
    • No motor, since any motor can win under some choice of the weights
  7. A pump needs 500 W of output. Motor B (80%, 0.5 kg) replaces motor A (90%, 1.0 kg). What does B trade away, Milo?

    • About 7 W more input power, to save 0.5 kg of mass
    • About 50 W more input power, to save 0.5 kg of mass
    • About 69 W more input power, to save 0.5 kg of mass
    • About 10 W more input power, to save 0.5 kg of mass
  8. Crash-barrier designs for a 1,200 kg car at 25 m/s (example data)

    designcrush length (m)cost ($ thousand)
    A1.540
    B2.555
    C480

    Limits: crush length at most 3.0 m and deceleration at most 15 g, where g is 9.8 m/s². Constant deceleration is v² ÷ (2d)

  9. A team says barrier B is safe because it stops a 1,200 kg car in 2.5 m. B's average force is 150 kN. What is the flaw, Noah?

    • It was tested at one mass; at 150 kN a 3,000 kg SUV needs 6.25 m
    • Nothing is missing, since 2.5 m is under the 3.0 m limit for space
    • The speed of 25 m/s was not given, so the test says little
    • It should have used a lighter car, since light cars crush more
  10. A designer doubles a barrier's crush length from 1.5 m to 3.0 m. What changes, Pia?

    • Deceleration stays the same, but cost doubles
    • Deceleration falls to a quarter, with the same road space
    • Deceleration falls by a third, but it needs half the space
    • Deceleration halves, but it needs twice the road space
  11. Stopping distance of a car on two tire compounds, five trials each (m) (example data)

    trialcompound Xcompound Y
    124.123.2
    223.824.9
    324.522.8
    42424.6
    524.323.5

    Mean X is 24.14 m with a spread of 0.7 m. Mean Y is 23.8 m with a spread of 2.1 m.

  12. Ren claims compound Y stops the car in a shorter distance. Does the table support that claim?

    • No: X's trials vary less, so X must be the better compound
    • Yes: five trials are enough to show any difference
    • Yes: Y's mean is shorter and it holds the single shortest stop
    • No: the 0.34 m gap is smaller than Y's 2.1 m spread
  13. First test of a barrier with a 2.0 m crush zone (1,200 kg car at 25 m/s) (example data)

    measureresultlimit
    crush length (m)2at most 3.0
    deceleration (g)15.9at most 15
  14. A 2.0 m crush zone gave 15.9 g, over the 15 g limit. Which single next change should Tala test?

    • Change the zone length and the car's mass together
    • Shorten the zone to save road space and rerun the same test
    • Raise the limit to 16 g so that the first test passes
    • Lengthen the zone to about 2.5 m and rerun the same test
  15. The spec says at least 80%. The mean is 80.8% and the spread is 7 points. The spec says the motor is at least 80% efficient. Does the table clearly support it, Zee?

    • Yes: its top run reached 84%, which is well above the 80% spec
    • Not clearly: two runs fall under 80% and the spread is 7 points
    • No: two runs fell below 80%, so the motor fails the spec outright
    • Yes: the mean of 80.8% is above the 80% that the spec asks for
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Define a design problem and weigh trade-offs

Answer Key - Grade 11 Science Worksheet

Circle the best answer, or write your answer on the line.

  1. A motor lifts a 120 kg load at 0.5 m/s and is 75% efficient. With g = 9.8 m/s², how much power does it draw, Bo?

    784 W
  2. A motor lifts a 30 kg load at 1.5 m/s and is 60% efficient. With g = 9.8 m/s², how much power does it draw, Esme?

    735 W
  3. Read this first

    Crash-barrier designs for a 1,200 kg car at 25 m/s (example data)

    designcrush length (m)cost ($ thousand)
    A1.540
    B2.555
    C480

    Limits: crush length at most 3.0 m and deceleration at most 15 g, where g is 9.8 m/s². Constant deceleration is v² ÷ (2d)

  4. Using the table, which is the cheapest barrier design that meets both limits, Jun?

    • C, since its 78 m/s² is the lowest deceleration of the three
    • B, since its 125 m/s² is under 147 and its 2.5 m fits
    • No design, since no crush length can meet both of the limits together
    • A, the cheapest, since its 1.5 m crush zone fits easily in the space
  5. Motors rated for the same job (example data) (example data)

    motorefficiency (%)mass (kg)cost ($)
    P881.2120
    Q881.5140
    R820.9100
  6. Using the table, which motor can be dropped whatever the weights, Luz?

    • R, since its efficiency is the lowest of the three motors
    • Q, since P matches its efficiency with less mass and lower cost
    • P, since it does not top the table on each column at once
    • No motor, since any motor can win under some choice of the weights
  7. A pump needs 500 W of output. Motor B (80%, 0.5 kg) replaces motor A (90%, 1.0 kg). What does B trade away, Milo?

    • About 7 W more input power, to save 0.5 kg of mass
    • About 50 W more input power, to save 0.5 kg of mass
    • About 69 W more input power, to save 0.5 kg of mass
    • About 10 W more input power, to save 0.5 kg of mass
  8. Crash-barrier designs for a 1,200 kg car at 25 m/s (example data)

    designcrush length (m)cost ($ thousand)
    A1.540
    B2.555
    C480

    Limits: crush length at most 3.0 m and deceleration at most 15 g, where g is 9.8 m/s². Constant deceleration is v² ÷ (2d)

  9. A team says barrier B is safe because it stops a 1,200 kg car in 2.5 m. B's average force is 150 kN. What is the flaw, Noah?

    • It was tested at one mass; at 150 kN a 3,000 kg SUV needs 6.25 m
    • Nothing is missing, since 2.5 m is under the 3.0 m limit for space
    • The speed of 25 m/s was not given, so the test says little
    • It should have used a lighter car, since light cars crush more
  10. A designer doubles a barrier's crush length from 1.5 m to 3.0 m. What changes, Pia?

    • Deceleration stays the same, but cost doubles
    • Deceleration falls to a quarter, with the same road space
    • Deceleration falls by a third, but it needs half the space
    • Deceleration halves, but it needs twice the road space
  11. Stopping distance of a car on two tire compounds, five trials each (m) (example data)

    trialcompound Xcompound Y
    124.123.2
    223.824.9
    324.522.8
    42424.6
    524.323.5

    Mean X is 24.14 m with a spread of 0.7 m. Mean Y is 23.8 m with a spread of 2.1 m.

  12. Ren claims compound Y stops the car in a shorter distance. Does the table support that claim?

    • No: X's trials vary less, so X must be the better compound
    • Yes: five trials are enough to show any difference
    • Yes: Y's mean is shorter and it holds the single shortest stop
    • No: the 0.34 m gap is smaller than Y's 2.1 m spread
  13. First test of a barrier with a 2.0 m crush zone (1,200 kg car at 25 m/s) (example data)

    measureresultlimit
    crush length (m)2at most 3.0
    deceleration (g)15.9at most 15
  14. A 2.0 m crush zone gave 15.9 g, over the 15 g limit. Which single next change should Tala test?

    • Change the zone length and the car's mass together
    • Shorten the zone to save road space and rerun the same test
    • Raise the limit to 16 g so that the first test passes
    • Lengthen the zone to about 2.5 m and rerun the same test
  15. The spec says at least 80%. The mean is 80.8% and the spread is 7 points. The spec says the motor is at least 80% efficient. Does the table clearly support it, Zee?

    • Yes: its top run reached 84%, which is well above the 80% spec
    • Not clearly: two runs fall under 80% and the spread is 7 points
    • No: two runs fell below 80%, so the motor fails the spec outright
    • Yes: the mean of 80.8% is above the 80% that the spec asks for