Calculate kinetic and potential energy

Grade 11 Science Worksheet

NameDate

Circle the best answer, or write your answer on the line.

  1. Ari launches a 0.2 kg ball straight up at 7 m/s. Ignoring air, how high above the launch point does it rise? Use g = 9.8 m/s².

  2. Bo launches a 0.5 kg ball straight up at 14 m/s. Ignoring air, how high above the launch point does it rise? Use g = 9.8 m/s².

  3. Esme launches a 3 kg ball straight up at 4.2 m/s. Ignoring air, how high above the launch point does it rise? Use g = 9.8 m/s².

  4. A ball starts at rest 2.0 m up and ends 0.5 m up, with no friction. Path A is a straight ramp; path B dips to the floor first. Compare the paths, Kira.

    • Path A ends faster, because its shorter route wastes less energy
    • Same end speed, 5.4 m/s; path B reaches 6.3 m/s at its dip
    • Path B ends faster, because it dips lower and gains more speed
    • Same end speed, 6.3 m/s, as both start 2.0 m up
  5. A motor lifts a 5 kg box 3.0 m in 4.0 s while taking 200 J of electrical energy. Using g = 9.8 m/s², what are the useful power and efficiency, Luz?

    • 50 W useful, 73.5% efficient
    • 36.75 W useful, 73.5% efficient
    • 147 W useful, 73.5% efficient
    • 36.75 W useful, 26.5% efficient
  6. A 5 kg box rises from a shelf 1.5 m up to a hook 2.1 m up. Milo measures height from the floor; a friend uses a table top 0.9 m up. Results?

    • The floor reading gives a gain of 102.9 J and the table reading 29.4 J
    • Their gains differ by 44.1 J, the table's share of height
    • Neither can find a gain, because their totals disagree
    • Both find a gain of 29.4 J, though their totals differ
  7. A 0.5 kg ball floats 3 m above the ground over a pit 2 m deep. Using g = 9.8 m/s², what is its gravitational energy measured from the pit floor, Noah?

    • 14.7 J: measured from the ground
    • 24.5 J: 0.5 × 9.8 × 5
    • 9.8 J: 0.5 × 9.8 × 2, the depth of the pit
    • 4.9 J: 0.5 × 9.8 × 1, from 3 − 2
  8. Pia drops a ball and wants its speed at landing. Why can any zero level be used for the height?

    • Every zero level gives the ball the same gravitational energy at the start
    • The zero level must be the floor, so any other choice gives the same answer
    • Only the drop in height counts, and a drop is the same from any zero
    • The ball's kinetic energy is measured from the zero level too, so the two cancel
  9. A 4 kg cart rolls on a level track at 6.0 m/s and slows to 4.0 m/s over 5.0 m. With steady friction, how much farther does Ren's cart roll before it stops?

    • 4.0 m: 40 J ÷ 5.0 m = 8 N, then 32 J ÷ 8 N
    • 9.0 m: 72 J ÷ 8 N, the whole stop from 6 m/s
    • 8.0 m: 32 J ÷ 4 N, taking friction as 4 N
    • 5.0 m: the same distance as the first stretch
  10. A 0.50 kg pendulum bob is released 0.20 m above its lowest point and rises to 0.18 m on the far side. With g = 9.8 m/s², how much energy did the air remove, Tala?

    • 0.02 J, which is 10% of the starting energy
    • 0.098 J, which is 10% of the starting energy
    • 0.098 J, which is 90% of the starting energy
    • 0.88 J, which is 90% of the starting energy
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Calculate kinetic and potential energy

Answer Key - Grade 11 Science Worksheet

Circle the best answer, or write your answer on the line.

  1. Ari launches a 0.2 kg ball straight up at 7 m/s. Ignoring air, how high above the launch point does it rise? Use g = 9.8 m/s².

    2.5 m
  2. Bo launches a 0.5 kg ball straight up at 14 m/s. Ignoring air, how high above the launch point does it rise? Use g = 9.8 m/s².

    10 m
  3. Esme launches a 3 kg ball straight up at 4.2 m/s. Ignoring air, how high above the launch point does it rise? Use g = 9.8 m/s².

    0.9 m
  4. A ball starts at rest 2.0 m up and ends 0.5 m up, with no friction. Path A is a straight ramp; path B dips to the floor first. Compare the paths, Kira.

    • Path A ends faster, because its shorter route wastes less energy
    • Same end speed, 5.4 m/s; path B reaches 6.3 m/s at its dip
    • Path B ends faster, because it dips lower and gains more speed
    • Same end speed, 6.3 m/s, as both start 2.0 m up
  5. A motor lifts a 5 kg box 3.0 m in 4.0 s while taking 200 J of electrical energy. Using g = 9.8 m/s², what are the useful power and efficiency, Luz?

    • 50 W useful, 73.5% efficient
    • 36.75 W useful, 73.5% efficient
    • 147 W useful, 73.5% efficient
    • 36.75 W useful, 26.5% efficient
  6. A 5 kg box rises from a shelf 1.5 m up to a hook 2.1 m up. Milo measures height from the floor; a friend uses a table top 0.9 m up. Results?

    • The floor reading gives a gain of 102.9 J and the table reading 29.4 J
    • Their gains differ by 44.1 J, the table's share of height
    • Neither can find a gain, because their totals disagree
    • Both find a gain of 29.4 J, though their totals differ
  7. A 0.5 kg ball floats 3 m above the ground over a pit 2 m deep. Using g = 9.8 m/s², what is its gravitational energy measured from the pit floor, Noah?

    • 14.7 J: measured from the ground
    • 24.5 J: 0.5 × 9.8 × 5
    • 9.8 J: 0.5 × 9.8 × 2, the depth of the pit
    • 4.9 J: 0.5 × 9.8 × 1, from 3 − 2
  8. Pia drops a ball and wants its speed at landing. Why can any zero level be used for the height?

    • Every zero level gives the ball the same gravitational energy at the start
    • The zero level must be the floor, so any other choice gives the same answer
    • Only the drop in height counts, and a drop is the same from any zero
    • The ball's kinetic energy is measured from the zero level too, so the two cancel
  9. A 4 kg cart rolls on a level track at 6.0 m/s and slows to 4.0 m/s over 5.0 m. With steady friction, how much farther does Ren's cart roll before it stops?

    • 4.0 m: 40 J ÷ 5.0 m = 8 N, then 32 J ÷ 8 N
    • 9.0 m: 72 J ÷ 8 N, the whole stop from 6 m/s
    • 8.0 m: 32 J ÷ 4 N, taking friction as 4 N
    • 5.0 m: the same distance as the first stretch
  10. A 0.50 kg pendulum bob is released 0.20 m above its lowest point and rises to 0.18 m on the far side. With g = 9.8 m/s², how much energy did the air remove, Tala?

    • 0.02 J, which is 10% of the starting energy
    • 0.098 J, which is 10% of the starting energy
    • 0.098 J, which is 90% of the starting energy
    • 0.88 J, which is 90% of the starting energy