Current, voltage and resistance

Grade 11 Science Worksheet - Challenge Me

NameDate

Circle the best answer, or write your answer on the line.

  1. Ari's small bulb carries 0.2 A at 2 V and 0.5 A at 7 V. By what percent does its resistance rise?

  2. Bo's small bulb carries 0.25 A at 1.5 V and 0.4 A at 6 V. By what percent does its resistance rise?

  3. Esme's small bulb carries 0.4 A at 4 V and 0.5 A at 9 V. By what percent does its resistance rise?

  4. Read this first

    Readings for a small bulb (example data)

    voltage (V)current (A)
    10.1
    30.2
    60.3
    90.36
  5. Jun reads the bulb table. How does the bulb's power change when the voltage goes from 3 V to 9 V?

    • It rises 5.4 times, from 0.6 W to 3.24 W
    • It rises 3 times, in step with the voltage
    • It rises 1.8 times, in step with the current
    • It rises 9 times, since P = V² ÷ R and the voltage triples
  6. Kira sees the bulb's current-voltage curve flatten as voltage rises. What does it show?

    • The curve is not a line, so V = IR cannot be used for the bulb
    • The slope ΔI ÷ ΔV falls from 0.05 to 0.02 A per V, so resistance rises
    • The slope stays near 0.1 A per V, so the resistance is steady
    • The slope falls, so the resistance falls
  7. Bulb A (6 Ω) is in series with bulbs B and C (12 Ω each, in parallel) across 12 V. Which glows brightest, and with what power, Luz?

    • A: 24 W against 12 W for B and C, from V² ÷ R with 12 V
    • The three glow equally, since one battery powers them
    • A: 6 W, against 3 W for each of B and C
    • B and C: the larger resistances, 12 Ω each, glow brightest
  8. “Circuit schematic (example data):” Milo says the bulb uses up current, so less leaves the bulb than enters it. Which reply fits the schematic?

    • No: both ammeters read 0.30 A; the bulb transfers energy, not current
    • No: the bulb adds current as it heats up
    • Yes: the bulb shines, so some of the current must be used up inside it
    • No: the ammeters agree because they sit before the switch
  9. Pia says a 1.5 V battery is safe across a thick wire of 0.05 Ω because 1.5 V is a small voltage. Which reply fits Ohm's law?

    • Yes: 1.5 V ÷ 0.05 Ω is a tiny current, 0.03 A
    • No: 1.5 V ÷ 0.05 Ω = 30 A, which would heat the wire
    • Yes: a battery this small has too little voltage to heat a wire
    • No: 1.5 V × 0.05 Ω = 0.075 A, which is already too much
  10. A 12.0 V battery with 0.50 Ω internal resistance is joined to a 5.5 Ω heater. What voltage is across the heater, Ren?

    • 10.9 V: 12 − (12 ÷ 5.5) × 0.50
    • 12.0 V, the emf of the battery
    • 11.0 V: 12 ÷ 6.0 = 2.0 A, then 2.0 × 5.5
    • 1.0 V, the voltage lost inside the battery
  11. The 12.0 V battery with 0.50 Ω internal resistance drives a 5.5 Ω heater at 2.0 A. How much power is wasted inside the battery, and how much reaches the heater, Tala?

    • 1.0 W is wasted inside; the heater gets 23 W
    • 2.0 W is wasted inside; the heater gets 24 W
    • 2.0 W is wasted inside; the heater gets 22 W, about 92% of 24 W
    • 2.0 W is wasted inside; the heater gets 22 W, about 8% of 24 W
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Current, voltage and resistance

Answer Key - Grade 11 Science Worksheet - Challenge Me

Circle the best answer, or write your answer on the line.

  1. Ari's small bulb carries 0.2 A at 2 V and 0.5 A at 7 V. By what percent does its resistance rise?

    40 %
  2. Bo's small bulb carries 0.25 A at 1.5 V and 0.4 A at 6 V. By what percent does its resistance rise?

    150 %
  3. Esme's small bulb carries 0.4 A at 4 V and 0.5 A at 9 V. By what percent does its resistance rise?

    80 %
  4. Read this first

    Readings for a small bulb (example data)

    voltage (V)current (A)
    10.1
    30.2
    60.3
    90.36
  5. Jun reads the bulb table. How does the bulb's power change when the voltage goes from 3 V to 9 V?

    • It rises 5.4 times, from 0.6 W to 3.24 W
    • It rises 3 times, in step with the voltage
    • It rises 1.8 times, in step with the current
    • It rises 9 times, since P = V² ÷ R and the voltage triples
  6. Kira sees the bulb's current-voltage curve flatten as voltage rises. What does it show?

    • The curve is not a line, so V = IR cannot be used for the bulb
    • The slope ΔI ÷ ΔV falls from 0.05 to 0.02 A per V, so resistance rises
    • The slope stays near 0.1 A per V, so the resistance is steady
    • The slope falls, so the resistance falls
  7. Bulb A (6 Ω) is in series with bulbs B and C (12 Ω each, in parallel) across 12 V. Which glows brightest, and with what power, Luz?

    • A: 24 W against 12 W for B and C, from V² ÷ R with 12 V
    • The three glow equally, since one battery powers them
    • A: 6 W, against 3 W for each of B and C
    • B and C: the larger resistances, 12 Ω each, glow brightest
  8. “Circuit schematic (example data):” Milo says the bulb uses up current, so less leaves the bulb than enters it. Which reply fits the schematic?

    • No: both ammeters read 0.30 A; the bulb transfers energy, not current
    • No: the bulb adds current as it heats up
    • Yes: the bulb shines, so some of the current must be used up inside it
    • No: the ammeters agree because they sit before the switch
  9. Pia says a 1.5 V battery is safe across a thick wire of 0.05 Ω because 1.5 V is a small voltage. Which reply fits Ohm's law?

    • Yes: 1.5 V ÷ 0.05 Ω is a tiny current, 0.03 A
    • No: 1.5 V ÷ 0.05 Ω = 30 A, which would heat the wire
    • Yes: a battery this small has too little voltage to heat a wire
    • No: 1.5 V × 0.05 Ω = 0.075 A, which is already too much
  10. A 12.0 V battery with 0.50 Ω internal resistance is joined to a 5.5 Ω heater. What voltage is across the heater, Ren?

    • 10.9 V: 12 − (12 ÷ 5.5) × 0.50
    • 12.0 V, the emf of the battery
    • 11.0 V: 12 ÷ 6.0 = 2.0 A, then 2.0 × 5.5
    • 1.0 V, the voltage lost inside the battery
  11. The 12.0 V battery with 0.50 Ω internal resistance drives a 5.5 Ω heater at 2.0 A. How much power is wasted inside the battery, and how much reaches the heater, Tala?

    • 1.0 W is wasted inside; the heater gets 23 W
    • 2.0 W is wasted inside; the heater gets 24 W
    • 2.0 W is wasted inside; the heater gets 22 W, about 92% of 24 W
    • 2.0 W is wasted inside; the heater gets 22 W, about 8% of 24 W