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Grade 11 · Science · Physics

11th grade Current, voltage and resistance worksheet

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Current, voltage and resistance

Grade 11 Science Worksheet

NameDate

Circle the best answer, or write your answer on the line.

  1. A 9 V battery drives a current through a 100 Ω resistor and a 200 Ω resistor in series. What is the voltage across the 200 Ω resistor, Ari?

  2. A 12 V battery drives a current through a 150 Ω resistor and a 50 Ω resistor in series. What is the voltage across the 50 Ω resistor, Bo?

  3. Jun reads the graph of two resistors. Which has more resistance, and how much?

    • Q, by 3 Ω more than P: 6 V against 3 V at 0.3 A
    • Neither: both lines are straight through the origin
    • P, because its line is flatter
    • Q: 20 Ω against 10 Ω for P
  4. Kira joins each resistor in turn to a 3 V battery. What current flows through each?

    Use the picture in question 3.

    • 0.15 A through P and 0.30 A through Q
    • 0.30 A through P and 0.15 A through Q
    • 0.60 A through P and 0.30 A through Q
    • 0.30 A through both, since the voltage is the same
  5. Luz reads the bulb's graph. How does its resistance, V ÷ I, change from 0.2 A to 0.4 A?

    • It stays near 15 Ω, since it is the same bulb
    • It rises from 15 Ω to 35 Ω, the slope between the points
    • It falls from 15 Ω to 10 Ω, since voltage rises slowly at first
    • It rises from 15 Ω to 25 Ω
  6. A 20 Ω resistor is in series with a 30 Ω and a 60 Ω resistor wired in parallel, all across a 12 V battery. What current leaves the battery, Milo?

    • 0.60 A: 12 V ÷ 20 Ω, the first resistor alone
    • 0.11 A: 12 V ÷ (20 + 30 + 60) Ω, all in series
    • 0.18 A: 12 V ÷ (20 + 45) Ω, with the pair averaged
    • 0.30 A: the parallel pair makes 20 Ω, so 40 Ω in all
  7. Bulbs A (10 Ω) and B (30 Ω) are in series across a 12 V battery. Which glows brighter, and with what power, Pia?

    • B is brighter: 2.7 W against 0.9 W for A
    • A is brighter, since a smaller resistance draws more current
    • A is brighter: 14.4 W against 4.8 W for B
    • They glow equally, since the same current passes through both
  8. A battery reads 6.0 V with no load and 5.4 V while delivering 2.0 A. What is its internal resistance, Ren?

    • 0.60 Ω: the lost voltage in volts
    • 0.30 Ω: (6.0 − 5.4) V ÷ 2.0 A
    • 3.0 Ω: 6.0 V ÷ 2.0 A
    • 2.7 Ω: 5.4 V ÷ 2.0 A, the load resistance
  9. Read this first

    A battery under different loads (example data)

    current (A)terminal voltage (V)
    0.55.85
    15.7
    1.55.55
    25.4
  10. Tala fits a line to the battery table, V = ε − Ir. What emf and internal resistance does the line give?

    • 6.00 V and 0.15 Ω, using the drop in volts as r
    • 6.00 V and 0.30 Ω: V falls 0.15 V for each 0.5 A
    • 6.00 V and 2.7 Ω, using 5.4 V ÷ 2.0 A as r
    • 5.40 V and 0.30 Ω, using the last reading as the emf
  11. A 12 Ω and a 24 Ω resistor are wired in parallel across a 6 V battery. What current leaves the battery, and how does it split, Zee?

    • 0.38 A in all: the average of the two branch currents
    • 0.17 A in all: 6 V ÷ (12 + 24) Ω
    • 0.75 A in all: 0.50 A in the 12 Ω and 0.25 A in the 24 Ω
    • 0.75 A in all: 0.25 A in the 12 Ω and 0.50 A in the 24 Ω
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11th grade Current, voltage and resistance worksheet – printable
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About this worksheet

Current, voltage and resistance. Every version has 10 questions, and the answer key prints on the second page.

What your child will learn

  • I can use V = IR to find current, voltage (with mA changed to A) and resistance, from meter readings and V–I graphs.
  • I can connect meters: an ammeter goes in the loop and a voltmeter across a part. I know the units: amp = C/s, volt = J/C, ohm = V/A.
  • I can predict changes: twice the voltage gives twice the current, and twice the resistance gives half the current.
  • I can show that a bulb's resistance rises as its filament heats (V ÷ I at each reading), so it is not ohmic. I can choose a resistor for a needed current.

Standard: none (TX, FL)

Words to know

current (I): Charge flowing past a point each second, in amps

voltage (V): Energy given to each coulomb of charge, in volts

resistance (R): How much a part opposes current, in ohms

ohmic: Having a resistance that stays the same: a straight V–I line

ammeter / voltmeter: Meters for current (in the loop) and voltage (across a part)

Common mistakes

Your child read kΩ as ohms. 4 kΩ is 4,000 Ω, so the current is a thousand times smaller than V ÷ R in amps.

Your child multiplied. From V = IR, the current is I = V ÷ R.

Your child found the voltage across the other resistor. In series, the bigger resistor gets the bigger share.

Questions parents ask

What is the most common mistake with current, voltage and resistance?

Your child read kΩ as ohms. 4 kΩ is 4,000 Ω, so the current is a thousand times smaller than V ÷ R in amps.

Are these 11th grade science worksheets free to print?

Yes. All 6 printable versions at each level are free to print, with the answer key, and no account is needed.

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