Current, voltage and resistance
Grade 11 Science Worksheet - Challenge Me

Circle the best answer, or write your answer on the line.
Bo's small bulb carries 0.25 A at 1.5 V and 0.4 A at 6 V. By what percent does its resistance rise?
Esme's small bulb carries 0.4 A at 4 V and 0.5 A at 9 V. By what percent does its resistance rise?
Read this first
Readings for a small bulb (example data)
voltage (V) current (A) 1 0.1 3 0.2 6 0.3 9 0.36 Jun reads the bulb table. How does the bulb's power change when the voltage goes from 3 V to 9 V?
- It rises 3 times, in step with the voltage
- It rises 9 times, since P = V² ÷ R and the voltage triples
- It rises 1.8 times, in step with the current
- It rises 5.4 times, from 0.6 W to 3.24 W
Kira sees the bulb's current-voltage curve flatten as voltage rises. What does it show?
- The slope stays near 0.1 A per V, so the resistance is steady
- The curve is not a line, so V = IR cannot be used for the bulb
- The slope falls, so the resistance falls
- The slope ΔI ÷ ΔV falls from 0.05 to 0.02 A per V, so resistance rises
Bulb A (6 Ω) is in series with bulbs B and C (12 Ω each, in parallel) across 12 V. Which glows brightest, and with what power, Luz?
- A: 6 W, against 3 W for each of B and C
- A: 24 W against 12 W for B and C, from V² ÷ R with 12 V
- B and C: the larger resistances, 12 Ω each, glow brightest
- The three glow equally, since one battery powers them
“Circuit schematic (example data):” Milo says the bulb uses up current, so less leaves the bulb than enters it. Which reply fits the schematic?
- No: both ammeters read 0.30 A; the bulb transfers energy, not current
- No: the ammeters agree because they sit before the switch
- No: the bulb adds current as it heats up
- Yes: the bulb shines, so some of the current must be used up inside it
Readings for a small bulb (example data)
voltage (V) current (A) 1 0.1 3 0.2 6 0.3 9 0.36 Noah says doubling the voltage across any part doubles its current. Which reply fits the bulb table?
- Yes: doubling the voltage doubles the current, so the readings must be wrong
- Yes: 0.30 A is close to double 0.20 A, so the rule holds here too
- No: doubling the voltage halves the current instead of doubling it
- No: 3 V to 6 V raised the current 1.5 times; the rule is for ohmic parts
A 12.0 V battery with 0.50 Ω internal resistance is joined to a 5.5 Ω heater. What voltage is across the heater, Ren?
- 11.0 V: 12 ÷ 6.0 = 2.0 A, then 2.0 × 5.5
- 12.0 V, the emf of the battery
- 10.9 V: 12 − (12 ÷ 5.5) × 0.50
- 1.0 V, the voltage lost inside the battery
The 12.0 V battery with 0.50 Ω internal resistance drives a 5.5 Ω heater at 2.0 A. How much power is wasted inside the battery, and how much reaches the heater, Tala?
- 2.0 W is wasted inside; the heater gets 24 W
- 2.0 W is wasted inside; the heater gets 22 W, about 8% of 24 W
- 1.0 W is wasted inside; the heater gets 23 W
- 2.0 W is wasted inside; the heater gets 22 W, about 92% of 24 W
An identical bulb B is added to bulb A on a 6 V battery. How does A's brightness change when B is added in parallel, and when B is added in series, Zee?
- Parallel: A falls to half. Series: A falls to a quarter
- Parallel: A falls to half. Series: A falls to half
- Parallel: unchanged. Series: A's power falls to a quarter
- Parallel: unchanged. Series: A falls to half