Current, voltage and resistance

Grade 11 Science Worksheet

NameDate

Circle the best answer, or write your answer on the line.

  1. A 9 V battery drives a current through a 100 Ω resistor and a 200 Ω resistor in series. What is the voltage across the 200 Ω resistor, Ari?

  2. A 12 V battery drives a current through a 150 Ω resistor and a 50 Ω resistor in series. What is the voltage across the 50 Ω resistor, Bo?

  3. A 6 V battery drives a current through a 20 Ω resistor and a 40 Ω resistor in series. What is the voltage across the 40 Ω resistor, Esme?

  4. Jun reads the graph of two resistors. Which has more resistance, and how much?

    • P, because its line is flatter
    • Neither: both lines are straight through the origin
    • Q, by 3 Ω more than P: 6 V against 3 V at 0.3 A
    • Q: 20 Ω against 10 Ω for P
  5. Kira joins each resistor in turn to a 3 V battery. What current flows through each?

    Use the picture in question 4.

    • 0.15 A through P and 0.30 A through Q
    • 0.30 A through both, since the voltage is the same
    • 0.30 A through P and 0.15 A through Q
    • 0.60 A through P and 0.30 A through Q
  6. Luz reads the bulb's graph. How does its resistance, V ÷ I, change from 0.2 A to 0.4 A?

    • It rises from 15 Ω to 35 Ω, the slope between the points
    • It stays near 15 Ω, since it is the same bulb
    • It falls from 15 Ω to 10 Ω, since voltage rises slowly at first
    • It rises from 15 Ω to 25 Ω
  7. A 20 Ω resistor is in series with a 30 Ω and a 60 Ω resistor wired in parallel, all across a 12 V battery. What current leaves the battery, Milo?

    • 0.11 A: 12 V ÷ (20 + 30 + 60) Ω, all in series
    • 0.30 A: the parallel pair makes 20 Ω, so 40 Ω in all
    • 0.60 A: 12 V ÷ 20 Ω, the first resistor alone
    • 0.18 A: 12 V ÷ (20 + 45) Ω, with the pair averaged
  8. A 20 Ω resistor is in series with a 30 Ω and a 60 Ω resistor wired in parallel across 12 V. What current flows through the 60 Ω resistor, Noah?

    • 0.30 A: the total current from the battery
    • 0.10 A: the pair has 6 V across it, and 6 ÷ 60
    • 0.20 A: 6 V ÷ 30 Ω, the other branch
    • 0.15 A: half of the total current
  9. Bulbs A (10 Ω) and B (30 Ω) are in series across a 12 V battery. Which glows brighter, and with what power, Pia?

    • A is brighter: 14.4 W against 4.8 W for B
    • They glow equally, since the same current passes through both
    • B is brighter: 2.7 W against 0.9 W for A
    • A is brighter, since a smaller resistance draws more current
  10. Read this first

    A battery under different loads (example data)

    current (A)terminal voltage (V)
    0.55.85
    15.7
    1.55.55
    25.4
  11. Tala fits a line to the battery table, V = ε − Ir. What emf and internal resistance does the line give?

    • 5.40 V and 0.30 Ω, using the last reading as the emf
    • 6.00 V and 0.15 Ω, using the drop in volts as r
    • 6.00 V and 2.7 Ω, using 5.4 V ÷ 2.0 A as r
    • 6.00 V and 0.30 Ω: V falls 0.15 V for each 0.5 A
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Current, voltage and resistance

Answer Key - Grade 11 Science Worksheet

Circle the best answer, or write your answer on the line.

  1. A 9 V battery drives a current through a 100 Ω resistor and a 200 Ω resistor in series. What is the voltage across the 200 Ω resistor, Ari?

    6 V
  2. A 12 V battery drives a current through a 150 Ω resistor and a 50 Ω resistor in series. What is the voltage across the 50 Ω resistor, Bo?

    3 V
  3. A 6 V battery drives a current through a 20 Ω resistor and a 40 Ω resistor in series. What is the voltage across the 40 Ω resistor, Esme?

    4 V
  4. Jun reads the graph of two resistors. Which has more resistance, and how much?

    • P, because its line is flatter
    • Neither: both lines are straight through the origin
    • Q, by 3 Ω more than P: 6 V against 3 V at 0.3 A
    • Q: 20 Ω against 10 Ω for P
  5. Kira joins each resistor in turn to a 3 V battery. What current flows through each?

    Use the picture in question 4.

    • 0.15 A through P and 0.30 A through Q
    • 0.30 A through both, since the voltage is the same
    • 0.30 A through P and 0.15 A through Q
    • 0.60 A through P and 0.30 A through Q
  6. Luz reads the bulb's graph. How does its resistance, V ÷ I, change from 0.2 A to 0.4 A?

    • It rises from 15 Ω to 35 Ω, the slope between the points
    • It stays near 15 Ω, since it is the same bulb
    • It falls from 15 Ω to 10 Ω, since voltage rises slowly at first
    • It rises from 15 Ω to 25 Ω
  7. A 20 Ω resistor is in series with a 30 Ω and a 60 Ω resistor wired in parallel, all across a 12 V battery. What current leaves the battery, Milo?

    • 0.11 A: 12 V ÷ (20 + 30 + 60) Ω, all in series
    • 0.30 A: the parallel pair makes 20 Ω, so 40 Ω in all
    • 0.60 A: 12 V ÷ 20 Ω, the first resistor alone
    • 0.18 A: 12 V ÷ (20 + 45) Ω, with the pair averaged
  8. A 20 Ω resistor is in series with a 30 Ω and a 60 Ω resistor wired in parallel across 12 V. What current flows through the 60 Ω resistor, Noah?

    • 0.30 A: the total current from the battery
    • 0.10 A: the pair has 6 V across it, and 6 ÷ 60
    • 0.20 A: 6 V ÷ 30 Ω, the other branch
    • 0.15 A: half of the total current
  9. Bulbs A (10 Ω) and B (30 Ω) are in series across a 12 V battery. Which glows brighter, and with what power, Pia?

    • A is brighter: 14.4 W against 4.8 W for B
    • They glow equally, since the same current passes through both
    • B is brighter: 2.7 W against 0.9 W for A
    • A is brighter, since a smaller resistance draws more current
  10. Read this first

    A battery under different loads (example data)

    current (A)terminal voltage (V)
    0.55.85
    15.7
    1.55.55
    25.4
  11. Tala fits a line to the battery table, V = ε − Ir. What emf and internal resistance does the line give?

    • 5.40 V and 0.30 Ω, using the last reading as the emf
    • 6.00 V and 0.15 Ω, using the drop in volts as r
    • 6.00 V and 2.7 Ω, using 5.4 V ÷ 2.0 A as r
    • 6.00 V and 0.30 Ω: V falls 0.15 V for each 0.5 A