Current, voltage and resistance
Grade 11 Science Worksheet

Circle the best answer, or write your answer on the line.
A 9 V battery drives a current through a 100 Ω resistor and a 200 Ω resistor in series. What is the voltage across the 200 Ω resistor, Ari?
A 6 V battery drives a current through a 20 Ω resistor and a 40 Ω resistor in series. What is the voltage across the 40 Ω resistor, Esme?
Kira joins each resistor in turn to a 3 V battery. What current flows through each?
- 0.15 A through P and 0.30 A through Q
- 0.30 A through P and 0.15 A through Q
- 0.30 A through both, since the voltage is the same
- 0.60 A through P and 0.30 A through Q
Luz reads the bulb's graph. How does its resistance, V ÷ I, change from 0.2 A to 0.4 A?
Voltage-current graph for a small bulb (example data): current (A) across, 0 to 0.5, a mark every 0.1 A; voltage (V) up, 0 to 12, a mark every 2 V. The line joins (0 A, 0 V), (0.1 A, 1 V), (0.2 A, 3 V), (0.3 A, 6 V), (0.4 A, 10 V) with straight pieces. Voltage-current graph for a small bulb (example data): current (A) across, 0 to 0.5, a mark every 0.1 A; voltage (V) up, 0 to 12, a mark every 2 V. The line joins (0 A, 0 V), (0.1 A, 1 V), (0.2 A, 3 V), (0.3 A, 6 V), (0.4 A, 10 V) with straight pieces. Voltage-current graph for a small bulb (example data) 0 0.1 0.2 0.3 0.4 0.5 0 2 4 6 8 10 12 current (A) voltage (V) - It stays near 15 Ω, since it is the same bulb
- It falls from 15 Ω to 10 Ω, since voltage rises slowly at first
- It rises from 15 Ω to 25 Ω
- It rises from 15 Ω to 35 Ω, the slope between the points
A 20 Ω resistor is in series with a 30 Ω and a 60 Ω resistor wired in parallel, all across a 12 V battery. What current leaves the battery, Milo?
- 0.18 A: 12 V ÷ (20 + 45) Ω, with the pair averaged
- 0.11 A: 12 V ÷ (20 + 30 + 60) Ω, all in series
- 0.60 A: 12 V ÷ 20 Ω, the first resistor alone
- 0.30 A: the parallel pair makes 20 Ω, so 40 Ω in all
A 20 Ω resistor is in series with a 30 Ω and a 60 Ω resistor wired in parallel across 12 V. What current flows through the 60 Ω resistor, Noah?
- 0.10 A: the pair has 6 V across it, and 6 ÷ 60
- 0.30 A: the total current from the battery
- 0.20 A: 6 V ÷ 30 Ω, the other branch
- 0.15 A: half of the total current
Bulbs A (10 Ω) and B (30 Ω) are in series across a 12 V battery. Which glows brighter, and with what power, Pia?
- They glow equally, since the same current passes through both
- A is brighter, since a smaller resistance draws more current
- A is brighter: 14.4 W against 4.8 W for B
- B is brighter: 2.7 W against 0.9 W for A
A battery reads 6.0 V with no load and 5.4 V while delivering 2.0 A. What is its internal resistance, Ren?
- 0.30 Ω: (6.0 − 5.4) V ÷ 2.0 A
- 3.0 Ω: 6.0 V ÷ 2.0 A
- 2.7 Ω: 5.4 V ÷ 2.0 A, the load resistance
- 0.60 Ω: the lost voltage in volts
Read this first
A battery under different loads (example data)
current (A) terminal voltage (V) 0.5 5.85 1 5.7 1.5 5.55 2 5.4 Tala fits a line to the battery table, V = ε − Ir. What emf and internal resistance does the line give?
- 5.40 V and 0.30 Ω, using the last reading as the emf
- 6.00 V and 0.15 Ω, using the drop in volts as r
- 6.00 V and 0.30 Ω: V falls 0.15 V for each 0.5 A
- 6.00 V and 2.7 Ω, using 5.4 V ÷ 2.0 A as r
A 12 Ω and a 24 Ω resistor are wired in parallel across a 6 V battery. What current leaves the battery, and how does it split, Zee?
- 0.75 A in all: 0.25 A in the 12 Ω and 0.50 A in the 24 Ω
- 0.75 A in all: 0.50 A in the 12 Ω and 0.25 A in the 24 Ω
- 0.38 A in all: the average of the two branch currents
- 0.17 A in all: 6 V ÷ (12 + 24) Ω